Tkinter

Question

这是我创建的代码，我正在尝试运行:

import tkinter as tk


def ok(val):
    print("Value is: ", val)

def say_hi(self):
    print("hi there, everyone!")

class Application(tk.Frame):

    def __init__(self, master=None):
        tk.Frame.__init__(self, master)
        master.title("Hi There")
        master.geometry("400x400")
        self.createWidgets(master)

    def createWidgets(self, master=None):
        var = str()

        self.select = tk.OptionMenu(master, var, "one", "two","three", command=ok).grid(column=1, row=1)

        self.QUIT = tk.Button(master, text="QUIT", fg="red", command=root.destroy).grid(column=2, row=1)
        print ("HI")

root = tk.Tk()
app = Application(master=root)
app.mainloop()

但我收到以下错误：

Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Python34\lib\tkinter\__init__.py", line 1533, in __call__
    return self.func(*args)
  File "C:\Python34\lib\tkinter\__init__.py", line 3308, in __call__
    self.__var.set(self.__value)
AttributeError: 'str' object has no attribute 'set'

我尝试修改一些变量并使用不同的方法使菜单正常工作，但似乎无法消除错误。

知道如何修复错误吗？

Answer 1

使用 StringVar 而不是 str

  def createWidgets(self, master=None):
        var = tk.StringVar()

A python str 没有 set 方法或属性，StringVar 特定于 tkinter 以及您打算使用的内容。

Tkinter - AttributeError: 'str' object has no attribute 'set'

Tkinter - AttributeError: 'str' object has no attribute 'set'

python

string

set

optionmenu