不确定如何覆盖随机

Question

import random
import time
import math
import sys

card_numbers = [1,2,3,4,5,6,7,8,9]
card_suite = ["of hearts", "of diamonds", "of clubs", "of spades", "Queen", "King", "Jack", "Ace"] #4,5,6,7
random_number = random.choice(card_numbers)
random_number2 = random.choice(card_numbers)
random_number3 = random.choice(card_numbers)
random_suite = random.choice(card_suite)

numberadd = random_number + random_number2
numberadd2 = random_number + random_number2 + random_number3

def setup():
    setupinput = raw_input("Type deal to deal the cards!")
    if setupinput == "deal":
        deal()
    elif setupinput != "deal":
        goodbye()
    else:
        print "Invalid Syntax!" 
        sys.exit(0)

def deal():
    print "Your first card is... ", random_number, random_suite
    print "Your second card is... ", random_number2, random_suite
    if numberadd >= 21:
        retry()
    else:
        thirdround()

def thirdround():
    thirdroundinput = raw_input("Would you like another card?")
    if thirdroundinput == "yes":
        print "Your next card is... ", random_number3, random_suite
        if numberadd2 >= 21:
            retry()
        else:
            print "You win! Your total was... ", numberadd2
            retry()
    elif thirdroundinput == "no":
        print "Okay... safe! Your total was... ", numberadd
    else:
        print "Invalid Syntax!"
        sys.exit(0)

def goodbye():
    print "Okay... goodbye!"
    sys.exit(0)

def retry():
    retryinput = raw_input("Would you like to try again?")
    if retryinput == "yes":
        setup()
    elif retryinput != "yes":
        goodbye()
    else:
        print "Invalid Syntax!"
        sys.exit(0)

def ifblacklist():
    if random_number or random_number2 or random_number3 == "Queen" or "King" or "Jack":
setup()

全新编码，刚刚完成编码（几乎作为初学者项目完成）并且想知道随机套件是否选择了 A、K、Q 或 J，或者我是否让它输出数字 10（或 1 代表 A）？

谢谢

为了澄清，ifblacklist 函数是我尝试使输出数字 10，并且想知道是否有人可以指出我正确的完成方向 it/rewriting

Answer 1

首先，所有else块都是这样；

retryinput = raw_input("Would you like to try again?")
    if retryinput == "yes":
        setup()
    elif retryinput != "yes":
        goodbye()
    else:
        print "Invalid Syntax!"
        sys.exit(0)

不需要。因为您的程序从不处理 else ，因为 elif retryinput != "yes": 包含所有情况。所以你应该删除 else 块，它们是无用的或者你应该改变它们;

retryinput = raw_input("Would you like to try again?")
    if retryinput == "yes":
        setup()
    elif retryinput == "no":
        goodbye()
    else:
        print "Invalid Syntax!"
        sys.exit(0)

二、这个功能

def ifblacklist():
   if random_number or random_number2 or random_number3 == "Queen" or "King" or "Jack":
setup()

应该是；

if random_number=="Queen" or random_number2=="King" or random_number3=="Jack":
    do something

否则一直是True，你应该全部写成conditions/equalitions。您将如何确保这些数字是 10；

你可以这样做；做一个口述并像这样输入 key/values;

mydict={"Queen":10,"King":10...}

然后在这个字典中搜索你的卡片，然后将它们的值相加。

不确定如何覆盖随机

Not sure how to override a random

python

python-2.7

random