如何将变量传递给此运行() 函数？

Question

我这里说的class来自于Android的Picasso Lib。我在这个函数中有一个名为 "ImageName" 的变量。但是我似乎无法弄清楚如何将参数传递给函数以更改该变量名称。我已经尝试扩展目标 class 但我似乎仍然遇到错误，而且我还不够先进，不知道我做错了什么。

private Target target = new Target() {
    @Override
    public void onBitmapLoaded(final Bitmap bitmap, Picasso.LoadedFrom from)
{
        new Thread(new Runnable() {
            @Override
            public void run() {

                File file = new File(
                        Environment.getExternalStorageDirectory().getPath()
                                + ImageName + ."jpg");//+ "/saved.jpg");
                try {
                    file.createNewFile();
                    FileOutputStream ostream = new FileOutputStream(file);
                    bitmap.compress(Bitmap.CompressFormat.JPEG,100,ostream);
                    ostream.close();
                }
                catch (Exception e) {
                    e.printStackTrace();
                }
            }
        }).start();
    }

    @Override
    public void onBitmapFailed(Drawable errorDrawable) {}

    @Override
    public void onPrepareLoad(Drawable placeHolderDrawable) {}
};

//我同时想到了什么...

public interface TargetImageName extends Target
{

    public void TargetImageName(String ImageName);

    @Override
    void onBitmapLoaded(Bitmap bitmap, Picasso.LoadedFrom from);

    @Override
    void onBitmapFailed(Drawable errorDrawable);

    @Override
    void onPrepareLoad(Drawable placeHolderDrawable);
}

private TargetImageName target2 = new TargetImageName() {
    String name;
    @Override
    public void TargetImageName(String ImageName) {
        name = ImageName;
    }

    @Override
    public void onBitmapLoaded(final Bitmap bitmap, Picasso.LoadedFrom from) {
        new Thread(new Runnable() {
            @Override
            public void run() {

                File file = new File(
                        Environment.getExternalStorageDirectory().getPath()
                                + name);//+ "/saved.jpg");
                try {
                    file.createNewFile();
                    FileOutputStream ostream = new FileOutputStream(file);
                    bitmap.compress(Bitmap.CompressFormat.JPEG,100,ostream);
                    ostream.close();
                }
                catch (Exception e) {
                    e.printStackTrace();
                }
            }
        }).start();
    }

    @Override
    public void onBitmapFailed(Drawable errorDrawable) {}

    @Override
    public void onPrepareLoad(Drawable placeHolderDrawable) {}
};

Answer 1

您不能将任何内容传递给 run()，因为它不带任何参数。你应该做的只是扩展 Runnable 并通过构造函数传递你需要的任何东西：

public class MyRunnable implements Runnable {
     protected Integer mFoo;

     public MyRunnable(Integer foo) { 
        mFoo = foo;
     }

     @Override
     public void run() {
          // access mFoo when you need it
           ...
     }
}

然后

...
 new Thread(new MyRunnable(...)) {
    ...

Answer 2

创建一个实现 Target 的 class 而不是另一个接口。

public class TargetImageName implements Target
    {
        String name;
        public  TargetImageName(String ImageName) {
            name = ImageName;
        }
        @Override
        public void onBitmapFailed(Drawable errorDrawable) {

        ...}
        @Override
        public void onBitmapLoaded(Bitmap bitmap, Picasso.LoadedFrom from) {
        ...}

        @Override
        public void onPrepareLoad(Drawable placeHolderDrawable) {
        ...}
    }

现在创建一个对象并将其作为 Picasso 回调对象传递

Picasso.with(getActivity()).load(<url>).into(new TargetImageName(<parameter>));

如何将变量传递给此运行() 函数？

How can I pass a Variable to this run() function?

java

multithreading

android

runnable

picasso

如何将变量传递给此 运行() 函数？

How can I pass a Variable to this run() function?

java

multithreading

android

runnable

picasso

如何将变量传递给此运行() 函数？