git 中最近的共同祖先可以是模棱两可的吗？
Can the most recent common ancestor in git be ambiguous?
既然修订可以有多个父项（合并）和多个子项，那么 "most recent common ancestor" 不能有歧义吗？
例如：
A---B--C--D
\ \ /
\ E /
\ / /
F-G
E 和 D 最近的共同祖先可能是 B 或 F。
我尝试在 git 中复制它，我认为它给了 B 作为共同祖先。这里有选择 B 而不是 F 的理由吗？也许求助于时间戳？或者它只是算法发现的第一个共同祖先，这将是一个任意的实现细节？
这不仅仅是可能的，documentation for git merge-base中提到了它：
git merge-base finds best common ancestor(s) between two commits to use in a three-way merge. One common ancestor is better than another common ancestor if the latter is an ancestor of the former. A common ancestor that does not have any better common ancestor is a best common ancestor, i.e. a merge base. Note that there can be more than one merge base for a pair of commits.
[强调我的——我认为强调的句子应该包括"best"这个词，真的]，并且：
... Neither one is better than the other (both are best merge bases). When the --all option is not given, it is unspecified which best one is output.
（这意味着，正如您所建议的，这是一个实现细节）。
既然修订可以有多个父项（合并）和多个子项，那么 "most recent common ancestor" 不能有歧义吗？
例如：
A---B--C--D
\ \ /
\ E /
\ / /
F-G
E 和 D 最近的共同祖先可能是 B 或 F。
我尝试在 git 中复制它，我认为它给了 B 作为共同祖先。这里有选择 B 而不是 F 的理由吗？也许求助于时间戳？或者它只是算法发现的第一个共同祖先，这将是一个任意的实现细节？
这不仅仅是可能的，documentation for git merge-base中提到了它：
git merge-base finds best common ancestor(s) between two commits to use in a three-way merge. One common ancestor is better than another common ancestor if the latter is an ancestor of the former. A common ancestor that does not have any better common ancestor is a best common ancestor, i.e. a merge base. Note that there can be more than one merge base for a pair of commits.
[强调我的——我认为强调的句子应该包括"best"这个词，真的]，并且：
... Neither one is better than the other (both are best merge bases). When the
--alloption is not given, it is unspecified which best one is output.
（这意味着，正如您所建议的，这是一个实现细节）。