无法在 tomcat 上访问网络服务，出现 500 错误

Question

请在这里帮助我：- 项目名称：- RESTFULWebService

java class:-

package com.packages.restful;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

@Path("/two")
public class SimpleRESTFULService {

    @GET
    @Produces(MediaType.TEXT_HTML)
    public String simpleMessage() {

        return "<p>This is a simple RESTFUL WebService</p>";

    }
}

web.xml:-

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>RESTFULWebService</display-name>
  <servlet>
    <servlet-name>Jersey REST Service</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
      <param-name>com.sun.jersey.config.property.packages</param-name>
      <param-value>RESTFULWebService</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>Jersey REST Service</servlet-name>
    <url-pattern>/one/*</url-pattern>
  </servlet-mapping>
</web-app>

我放置了 Jersey 1.18 lib，将所有 jar 扩展到我的 lib 文件夹中 URL 我正在使用 :- http://localhost:8080/RESTFULWebService/one/two 但我收到错误：- 说明服务器遇到内部错误 ()，导致它无法完成此请求。

异常

javax.servlet.ServletException: Servlet.init() for servlet Jersey REST Service threw exception
    org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:462)
    org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
    org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:562)
    org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:395)
    org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:250)
    org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:1


root cause

com.sun.jersey.api.container.ContainerException: The ResourceConfig instance does not contain any root resource classes.
    com.sun.jersey.server.impl.application.RootResourceUriRules.<init>(RootResourceUriRules.java:99)
    com.sun.jersey.server.impl.application.WebApplicationImpl._initiate(WebApplicationImpl.java:1359)
    com.sun.jersey.server.impl.application.WebApplicationImpl.access0(WebApplicationImpl.java:180)
    com.sun.jersey.server.impl.application.WebApplicationImpl.f(WebApplicationImpl.java:799)
    com.sun.jersey.server.impl.application.WebApplicationImpl.f(WebApplicationImpl.java:795)
    com.sun.jersey.spi.inject.Errors.processWithErrors(Errors.java:193)
    com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:795)
    com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:790)
    com.sun.jersey.spi.container.servlet.ServletContainer.initiate(ServletContainer.java:491)
    com.sun.jersey.spi.container.servlet.ServletContainer$InternalWebComponent.initiate(ServletContainer.java:321)
    com.sun.jersey.spi.container.servlet.WebComponent.load(WebComponent.java:605)
    com.sun.jersey.spi.container.servlet.WebComponent.init(WebComponent.java:207)
    com.sun.jersey.spi.container.servlet.ServletContainer.init(ServletContainer.java:376)

请帮帮我，我搜索了整个 google，但是虽然我写的都是正确的，但为什么我没有得到输出？

Answer 1

param com.sun.jersey.config.property.packages 的值必须是您拥有资源的 Java 包（类用 @Path 注释）。

所以，你需要改变这个：

<init-param>
  <param-name>com.sun.jersey.config.property.packages</param-name>
  <param-value>RESTFULWebService</param-value>
</init-param>

作者：

<init-param>
  <param-name>com.sun.jersey.config.property.packages</param-name>
  <param-value>com.packages.restful</param-value>
</init-param>

无法在 tomcat 上访问网络服务，出现 500 错误

Unable to hit webservice on tomcat getting 500 error

java

web-services

tomcat