如何在不相关的 ViewModel 中设置数据
How do I set data in an unrelated ViewModel
我有一个登录过程I've roughed into a fiddle(我卡住的部分从第 110 行开始)。
这是代码的副本:
Ext.define('MyApp.MyPanel',{
extend: 'Ext.panel.Panel',
title: 'My App',
controller: 'mypanelcontroller',
viewModel: {
data:{
email: 'Not signed in'
}
},
width: 500,
height: 200,
renderTo: Ext.getBody(),
bind:{
html: "Logged in as: <b>{email}</b>"
},
buttons:[
{
text: 'Sign in',
handler: 'showSignInWindow'
}
]
});
Ext.define('MyApp.MyPanelController',{
extend: 'Ext.app.ViewController',
alias: 'controller.mypanelcontroller',
showSignInWindow: function (b,e,eOpts){
Ext.widget('signinwindow').show();
}
});
Ext.define('MyApp.SignInWindow',{
extend: 'Ext.window.Window',
title: 'Sign in',
controller: 'signincontroller',
xtype: 'signinwindow',
width: 400,
title: 'Sign In',
modal: true,
layout: 'fit',
items:[
{
xtype: 'form',
reference: 'signinfields',
layout: 'anchor',
bodyPadding: 5,
defaults: {
anchor: '100%',
xtype: 'textfield'
},
items:[
{
fieldLabel: 'Email',
name: 'email',
allowBlank: false
},
{
fieldLabel: 'Password',
name: 'password',
allowBlank: false,
inputType: 'password'
}
],
buttons:[
{
text: 'forgot password',
width: 120,
//handler: 'onForgotPassword'
},
'->',
{
text: 'sign in',
width: 120,
handler: 'onSignIn'
}
]
}
]
});
Ext.define('MyApp.SignInController',{
extend: 'Ext.app.ViewController',
alias: 'controller.signincontroller',
onSignIn: function (button, event, eOpts){
var data = button.up('form').getValues();
button.up('window').mask('Signing in...');
Ext.Ajax.request({
// sorry, I don't know how to fake an API response yet :/
url: '/authenticate/login',
jsonData: data,
scope: this,
success: function (response){
var result = Ext.decode(response.responseText);
if(result.loggedIn == true){
/*
This is where I need help.
From the sign in window, I would like to update the viewmodel in `MyApp.MyPanel` with the
email returned in the response. If the window was a child of MyPanel, I would be able to update
via the ViewModel inheritance, but I can't here because the window isn't part of the `items` config.
*/
this.getViewModel().set('email', result.data[0].email);
Ext.toast({
title: 'Sign in successful',
html: "You've been signed in.",
align: 't',
closable: true,
width: 300
});
button.up('window').destroy();
} else {
Ext.toast({
title: 'Sign in failed',
html: "You sign in failed: " + result.message,
closable: true,
width: 300,
align: 't'
});
button.up('window').unmask();
}
},
failure: function (){
// debugger;
}
})
},
onForgotPassword: function (){
Ext.Ajax.request({
url: '/authenticate/test',
success: function (response){
},
failure: function (){
}
})
// Ext.Msg.alert('trigger forgot password logic', "This is where you need to trigger the API to send the forgot email form. <br>Say something here about how you'll get an email");
}
});
Ext.application({
name : 'Fiddle',
launch : function() {
Ext.create('MyApp.MyPanel');
}
});
我想做的是:
- 显示带有登录按钮的面板
- 点击按钮显示登录 window
- 提交登录表单会尝试对服务器进行身份验证
- 身份验证成功后,用户的电子邮件将在初始面板的 ViewModel 中设置
最后一个项目符号是我遇到的问题。
如果登录 window 是面板的子项,那么我可以通过 ViewModel 继承来设置它,但是因为我使用的是小部件显示,所以我无法通过面板的项目配置进行设置.
有没有正确的方法?
没关系,我想通了。答案一直在我的问题中:
If the sign in window was a child of the panel then I could set it through the ViewModel inheritance, but since I'm using a widget show I can't set back through the panel's items config.
只需将 window 设为面板的子项:
Ext.define('MyApp.MyPanelController',{
extend: 'Ext.app.ViewController',
alias: 'controller.mypanelcontroller',
showSignInWindow: function (b,e,eOpts){
// Instead of creating the widget and showing it, create it and add it to the panel.
// The window is going to float anyway, so being a child of the panel is no big deal
var signinwindow = Ext.widget('signinwindow');
this.getView().add(signinwindow).show();
}
});
这样做意味着 window 继承面板的视图模型,您可以像这样设置视图模型数据:
Ext.define('Registration.view.signin.SignInController', {
extend: 'Ext.app.ViewController',
alias: 'controller.signin-signin',
onSignIn: function (button, event, eOpts){
var data = button.up('form').getValues();
button.up('window').mask('Signing in...');
Ext.Ajax.request({
url: '/authenticate/login',
jsonData: data,
scope: this,
success: function (response){
debugger;
var result = Ext.decode(response.responseText);
if(result.loggedIn == true){
// Now that the window has inherited the panel's viewmodel
// you can set it's data from the windows controller
this.getViewModel().set('username', result.data[0].eMail);
...
愤怒的表情符号:/
我有一个登录过程I've roughed into a fiddle(我卡住的部分从第 110 行开始)。
这是代码的副本:
Ext.define('MyApp.MyPanel',{
extend: 'Ext.panel.Panel',
title: 'My App',
controller: 'mypanelcontroller',
viewModel: {
data:{
email: 'Not signed in'
}
},
width: 500,
height: 200,
renderTo: Ext.getBody(),
bind:{
html: "Logged in as: <b>{email}</b>"
},
buttons:[
{
text: 'Sign in',
handler: 'showSignInWindow'
}
]
});
Ext.define('MyApp.MyPanelController',{
extend: 'Ext.app.ViewController',
alias: 'controller.mypanelcontroller',
showSignInWindow: function (b,e,eOpts){
Ext.widget('signinwindow').show();
}
});
Ext.define('MyApp.SignInWindow',{
extend: 'Ext.window.Window',
title: 'Sign in',
controller: 'signincontroller',
xtype: 'signinwindow',
width: 400,
title: 'Sign In',
modal: true,
layout: 'fit',
items:[
{
xtype: 'form',
reference: 'signinfields',
layout: 'anchor',
bodyPadding: 5,
defaults: {
anchor: '100%',
xtype: 'textfield'
},
items:[
{
fieldLabel: 'Email',
name: 'email',
allowBlank: false
},
{
fieldLabel: 'Password',
name: 'password',
allowBlank: false,
inputType: 'password'
}
],
buttons:[
{
text: 'forgot password',
width: 120,
//handler: 'onForgotPassword'
},
'->',
{
text: 'sign in',
width: 120,
handler: 'onSignIn'
}
]
}
]
});
Ext.define('MyApp.SignInController',{
extend: 'Ext.app.ViewController',
alias: 'controller.signincontroller',
onSignIn: function (button, event, eOpts){
var data = button.up('form').getValues();
button.up('window').mask('Signing in...');
Ext.Ajax.request({
// sorry, I don't know how to fake an API response yet :/
url: '/authenticate/login',
jsonData: data,
scope: this,
success: function (response){
var result = Ext.decode(response.responseText);
if(result.loggedIn == true){
/*
This is where I need help.
From the sign in window, I would like to update the viewmodel in `MyApp.MyPanel` with the
email returned in the response. If the window was a child of MyPanel, I would be able to update
via the ViewModel inheritance, but I can't here because the window isn't part of the `items` config.
*/
this.getViewModel().set('email', result.data[0].email);
Ext.toast({
title: 'Sign in successful',
html: "You've been signed in.",
align: 't',
closable: true,
width: 300
});
button.up('window').destroy();
} else {
Ext.toast({
title: 'Sign in failed',
html: "You sign in failed: " + result.message,
closable: true,
width: 300,
align: 't'
});
button.up('window').unmask();
}
},
failure: function (){
// debugger;
}
})
},
onForgotPassword: function (){
Ext.Ajax.request({
url: '/authenticate/test',
success: function (response){
},
failure: function (){
}
})
// Ext.Msg.alert('trigger forgot password logic', "This is where you need to trigger the API to send the forgot email form. <br>Say something here about how you'll get an email");
}
});
Ext.application({
name : 'Fiddle',
launch : function() {
Ext.create('MyApp.MyPanel');
}
});
我想做的是:
- 显示带有登录按钮的面板
- 点击按钮显示登录 window
- 提交登录表单会尝试对服务器进行身份验证
- 身份验证成功后,用户的电子邮件将在初始面板的 ViewModel 中设置
最后一个项目符号是我遇到的问题。
如果登录 window 是面板的子项,那么我可以通过 ViewModel 继承来设置它,但是因为我使用的是小部件显示,所以我无法通过面板的项目配置进行设置.
有没有正确的方法?
没关系,我想通了。答案一直在我的问题中:
If the sign in window was a child of the panel then I could set it through the ViewModel inheritance, but since I'm using a widget show I can't set back through the panel's items config.
只需将 window 设为面板的子项:
Ext.define('MyApp.MyPanelController',{
extend: 'Ext.app.ViewController',
alias: 'controller.mypanelcontroller',
showSignInWindow: function (b,e,eOpts){
// Instead of creating the widget and showing it, create it and add it to the panel.
// The window is going to float anyway, so being a child of the panel is no big deal
var signinwindow = Ext.widget('signinwindow');
this.getView().add(signinwindow).show();
}
});
这样做意味着 window 继承面板的视图模型,您可以像这样设置视图模型数据:
Ext.define('Registration.view.signin.SignInController', {
extend: 'Ext.app.ViewController',
alias: 'controller.signin-signin',
onSignIn: function (button, event, eOpts){
var data = button.up('form').getValues();
button.up('window').mask('Signing in...');
Ext.Ajax.request({
url: '/authenticate/login',
jsonData: data,
scope: this,
success: function (response){
debugger;
var result = Ext.decode(response.responseText);
if(result.loggedIn == true){
// Now that the window has inherited the panel's viewmodel
// you can set it's data from the windows controller
this.getViewModel().set('username', result.data[0].eMail);
...
愤怒的表情符号:/