Ruby 在 rails 休息客户端，处理错误响应

Question

我是 ruby 的新手（也是编程方面的新手）

我构建了这段代码：

    #This method executing a url and give the response in json format
    def get url
      return JSON.parse(RestClient::Request.execute(method: :get, url: url))
    end

现在我正在尝试处理来自任何 url 的响应代码不正确的情况，我想将其替换为错误消息 "error"

我尝试用这段代码替换 get 方法：

def get url
 if ((RestClient::Request.execute(method: :get, url: url)).code == 200)
    return JSON.parse(RestClient::Request.execute(method: :get, url: url))
 else
  error = "error"
    return  error.as_json
 end
end

但是如果 url 的响应不是 200，我会收到错误消息“406 不可接受”而不是 "error"

提前致谢

Answer 1

RestClient::Request收到错误响应时会抛出异常（响应码不是2xx/3xx）：

for result codes between 200 and 207, a RestClient::Response will be returned

for result codes 301, 302 or 307, the redirection will be followed if the request is a GET or a HEAD

for result code 303, the redirection will be followed and the request transformed into a GET

for other cases, a RestClient::Exception holding the Response will be raised; a specific exception class will be thrown for known error codes

call .response on the exception to get the server's response

Documentation

您应该处理该异常：

def get url
  result = RestClient::Request.execute(method: :get, url: url)
  JSON.parse(result)
rescue RestClient::Exception
  "error" # no need to call 'as_json'
end

有关 Ruby 异常处理的更多信息：

Ruby Exceptions

Ruby 在 rails 休息客户端，处理错误响应

Ruby on rails rest client, handling error response

ruby-on-rails

json

rest-client