在 Swift 中为 Sprite 创建随机位置

Question

我有一个圆形精灵，我想将它移动到 iOS 设备屏幕范围内的随机位置。我正在尝试在 Swift 中执行此操作，但我仍然是初学者，我什至不知道从哪里开始。有谁知道如何为精灵创建随机位置？提前致谢！

-文尼

Answer 1

假设您从场景中调用代码 class:

func spawnAtRandomPosition() {
    let height = self.view!.frame.height
    let width = self.view!.frame.width

    let randomPosition = CGPointMake(CGFloat(arc4random()) % height, CGFloat(arc4random()) % width)

    let sprite = SKSpriteNode()
    sprite.position = randomPosition
}

Answer 2

Swift3:

func spawnRandomPosition() {

let height = self.view!.frame.height
let width = self.view!.frame.width

let randomPosition = CGPoint(x:CGFloat(arc4random()).truncatingRemainder(dividingBy: height),
                                 y: CGFloat(arc4random()).truncatingRemainder(dividingBy: width))

let sprite = SKSpriteNode()
sprite.position = randomPosition
 }

Answer 3

Swift 3:

let randomPosition = CGPoint( x:CGFloat( arc4random_uniform( UInt32( floor( width  ) ) ) ),
                              y:CGFloat( arc4random_uniform( UInt32( floor( height ) ) ) )
                              )

在 Swift 中为 Sprite 创建随机位置

Creating a Random Position for a Sprite in Swift

random

xcode

position

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