python 用于组织音乐的脚本中的 IndentationError

Question

我以前制作过这个脚本，现在想使用它，但是在尝试运行时出现错误。这个脚本是关于组织我的音乐的。我有一个按标签组织的目录，想从标签和年份目录中的目录名称中获取艺术家姓名，并在艺术家和年份目录中创建新目录。

label里面的目录名是这样的

标签名称_[艺术家-专辑名称]_2015-08-09

并且想像这样在艺术家目录和年份目录（按日期）内创建符号链接

2015-08-09_[艺术家-专辑名称]_标签名称

import os
basedir = "/home/zab/Music/#01.Label"
artist_parent_dir = "/home/zab/Music/#03.Artist"
date_parent_dir = "/home/zab/Music/#04.ReleaseDate"
for fn in os.listdir(basedir):
    label_path = os.path.join( basedir, fn)
    for album in os.listdir(label_path):
        i = 1
        words = album.split("_")
        for word in words:
            if i == 1:
                label = word
            elif i == 2:
                name = word
            else:
                date = word
            i = i + 1
        artist_album = name.split("-")
        j = 1
        for part in artist_album:
            if j == 1:
                artist = part.replace("[","")
            j = j + 1
        date_parts = date.split("-")
        z =  1
        for part_two in date_parts:
            if z == 1:
                year = part_two
            z = z + 1
        if not os.path.isdir(os.path.join(artist_parent_dir,artist)):
            os.mkdir(os.path.join(artist_parent_dir,artist))
        if not os.path.isdir(os.path.join(date_parent_dir,year)):
            os.mkdir(os.path.join(date_parent_dir,year))
        src = os.path.join(label_path,album)
        artist_dst = os.path.join(artist_parent_dir, artist, name + "_" + label + "_" + date)
        year_dst = os.path.join(date_parent_dir,year, date + "_" + name + "_" + label)
        if not os.path.exists(artist_dst):
            os.symlink(src, artist_dst)
        if not os.path.exists(year_dst):
            os.symlink(src, year_dst)

File "/home/zab/Music/_Scripts/OrganizeByArtist.py", line 22
    artist = part.replace("[","")
                                ^
IndentationError: expected an indented block

出了什么问题？ part.replace 过时了吗？任何改进此脚本的建议将不胜感激。

Answer 1

您可能混用了空格和制表符，这使得很难弄清楚 Python 如何看待缩进。

Answer 2

您正在混用制表符和空格；从您的 post 此处获取源代码显示：

>>> '''\
...             for part in artist_album:
...                 if j == 1:
...                     artist = part.replace("[","")
... '''.splitlines()
['            for part in artist_album:', '\t            if j == 1:', '                    artist = part.replace("[","")']
>>> from pprint import pprint
>>> pprint(_)
['            for part in artist_album:',
 '\t            if j == 1:',
 '                    artist = part.replace("[","")']

注意 if 行开头的 \t。 Python 将制表符扩展为 8 个空格，但您可能将编辑器设置为使用 4 个空格。所以 Python 看到了这个：

for part in artist_album:
        if j == 1:
        artist = part.replace("[","")']

您的编辑向您显示的位置：

for part in artist_album:
    if j == 1:
        artist = part.replace("[","")']

将您的编辑器配置为仅使用空格进行缩进。如果这样配置，好的编辑器会为您将 TAB 键转换为空格。

引自 Python Style Guide (PEP 8):

Spaces are the preferred indentation method.

Tabs should be used solely to remain consistent with code that is already indented with tabs.

python 用于组织音乐的脚本中的 IndentationError

IndentationError in python script for organising Music

python

linux

symlink

archlinux