数字回文检查器

Question

我目前正在尝试做作业。我的回文检查器需要一些帮助。这是我到目前为止所做的

begin = int(input('Enter begin: '))
end = int(input('Enter end: '))

palindromes = 0
#Add your code here. You will want to start with a "for x in range" style loop.
for x in range(begin, end, -1):


print('There are', palindromes, 'palindrome(s) between', begin, 'and', end)

这不是函数。请帮忙。

Answer 1

检查数字是否为回文的最简单方法可能是将其视为字符串，翻转它，然后检查翻转后的字符串是否与原始字符串相同。从那以后，它只是一个循环，计算你遇到了多少：

begin = int(input('Enter begin: '))
end = int(input('Enter end: '))

palindromes = 0
#Add your code here. You will want to start with a "for x in range" style loop.
for x in range(begin, end):
    if str(x) == str(x)[::-1]:
        palindromes += 1

print('There are', palindromes, 'palindrome(s) between', begin, 'and', end)

数字回文检查器

Palindrome Checker for numbers

python

palindrome