将双精度转换为 swift 中的科学记数法

Question

我正在尝试将给定的双精度转换为科学记数法，并将运行转换为一些问题。我似乎也找不到很多关于如何做的文档。目前我正在使用：

 var val = 500
 var numberFormatter = NSNumberFormatter()
 numberFormatter.numberStyle = NSNumberFormatterStyle.ScientificStyle
 let number = numberFormatter.numberFromString("\(val)")
 println(number as Double?) 
 // Prints optional(500) instead of optional(5e+2)

我做错了什么？

Answer 1

您可以设置 NumberFormatter 属性 positiveFormat 和 exponent Symbol 来根据需要格式化您的字符串，如下所示：

let val = 500
let formatter = NumberFormatter()
formatter.numberStyle = .scientific
formatter.positiveFormat = "0.###E+0"
formatter.exponentSymbol = "e"
if let scientificFormatted = formatter.string(for: val) {
    print(scientificFormatted)  // "5e+2"
}

更新：Xcode 9 • Swift 4

您还可以创建扩展以从数字类型获取科学格式的描述，如下所示：

extension Formatter {
    static let scientific: NumberFormatter = {
        let formatter = NumberFormatter()
        formatter.numberStyle = .scientific
        formatter.positiveFormat = "0.###E+0"
        formatter.exponentSymbol = "e"
        return formatter
    }()
}

extension Numeric {
    var scientificFormatted: String {
        return Formatter.scientific.string(for: self) ?? ""
    }
}

print(500.scientificFormatted)   // "5e+2"

Answer 2

问题是您正在打印数字...而不是格式化数字。您正在调用 numberForString 而不是 stringForNumber

var val = 500
var numberFormatter = NSNumberFormatter()
numberFormatter.numberStyle = NSNumberFormatterStyle.ScientificStyle
let numberString = numberFormatter.stringFromNumber(val)
println(numberString)

Answer 3

将 leo-dabus 的答案略微修改为 Xcode 9 Swift 4:

extension Double {
    struct Number {
        static var formatter = NumberFormatter()
    }
    var scientificStyle: String {
        Number.formatter.numberStyle = .scientific
        Number.formatter.positiveFormat = "0.###E+0"
        Number.formatter.exponentSymbol = "e"
        let number = NSNumber(value: self)
        return Number.formatter.string(from :number) ?? description
    }
}

将双精度转换为 swift 中的科学记数法

Convert Double to Scientific Notation in swift

ios

swift

math

nsnumberformatter