Android 地理编码功能不如 iOS
Android geocoding not functioning as well as iOS
所以我有一个将地址(字符串)转换为坐标的函数。
这是 iOS 中的样子:
func setCoords(buildet: BuildingDetail) {
let geoCoder = CLGeocoder()
geoCoder.geocodeAddressString(buildet.address, completionHandler:
{(placemarks: [AnyObject]!, error: NSError!) in
if error != nil {
println("Geocode failed with error: \(error.localizedDescription)")
} else if placemarks.count > 0 {
let placemark = placemarks[0] as! CLPlacemark
let location = placemark.location
buildet.lat = location.coordinate.latitude
buildet.lon = location.coordinate.longitude
}
self.setupMarker(buildet)
})
}
这是 Android 中的样子:
public static double[] getLatLongPositions(String address) throws Exception
{
int responseCode = 0;
String api = "http://maps.googleapis.com/maps/api/geocode/xml?address=" + URLEncoder.encode(address, "UTF-8") + "&sensor=true";
System.out.println("URL : "+api);
URL url = new URL(api);
HttpURLConnection httpConnection = (HttpURLConnection)url.openConnection();
httpConnection.connect();
responseCode = httpConnection.getResponseCode();
if(responseCode == 200)
{
DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();;
Document document = builder.parse(httpConnection.getInputStream());
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile("/GeocodeResponse/status");
String status = (String)expr.evaluate(document, XPathConstants.STRING);
if(status.equals("OK"))
{
expr = xpath.compile("//geometry/location/lat");
String latitude = (String)expr.evaluate(document, XPathConstants.STRING);
expr = xpath.compile("//geometry/location/lng");
String longitude = (String)expr.evaluate(document, XPathConstants.STRING);
return new double[] {Double.parseDouble(latitude), Double.parseDouble(longitude)};
}
}
return new double[]{0,0};
}
现在,上面的 iOS 函数只运行 setupMarker 函数,其中 Android 方法 returns 坐标,没什么大不了的!
我遇到的问题是,我为两个函数提供了完全相同的地址参数。
iOSreturns所有坐标完美.
然而,Android 只有 returns 大约 30% 正确。
是否有一个 Android 函数等同于上面的 iOS 函数,或者只有一个可以正确地理编码的函数。
如您所见,Android 在此处调用了 API:
http://maps.googleapis.com/maps/api/geocode/xml?address=
我也测试过这个,效果不是很好,至少不如iOS。
我该怎么办?
编辑 - 一些示例(全部适用于 iOS)
- EBS,伯灵顿路 2 号,都柏林 2
- AIB Bankcentre, Merrion Road, Ballsbridge, Dublin 4, Ireland
- AIB, Unit 33, Sandyford Business Centre, Sandyford, Dublin 18
尝试使用 URL returns 格式的 JSON 数据,然后您可以解析并获取纬度和经度。这是一个例子:
public static void getLatLongFromAddress(String youraddress) {
String uri = "http://maps.google.com/maps/api/geocode/json?address=" +
youraddress + "&sensor=false";
HttpGet httpGet = new HttpGet(uri);
HttpClient client = new DefaultHttpClient();
HttpResponse response;
StringBuilder stringBuilder = new StringBuilder();
try {
response = client.execute(httpGet);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
double lng = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lng");
double lat = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lat");
Log.d("latitude", "" + lat);
Log.d("longitude", "" + lng);
} catch (JSONException e) {
e.printStackTrace();
}
}
希望这对您有所帮助。
所以我有一个将地址(字符串)转换为坐标的函数。
这是 iOS 中的样子:
func setCoords(buildet: BuildingDetail) {
let geoCoder = CLGeocoder()
geoCoder.geocodeAddressString(buildet.address, completionHandler:
{(placemarks: [AnyObject]!, error: NSError!) in
if error != nil {
println("Geocode failed with error: \(error.localizedDescription)")
} else if placemarks.count > 0 {
let placemark = placemarks[0] as! CLPlacemark
let location = placemark.location
buildet.lat = location.coordinate.latitude
buildet.lon = location.coordinate.longitude
}
self.setupMarker(buildet)
})
}
这是 Android 中的样子:
public static double[] getLatLongPositions(String address) throws Exception
{
int responseCode = 0;
String api = "http://maps.googleapis.com/maps/api/geocode/xml?address=" + URLEncoder.encode(address, "UTF-8") + "&sensor=true";
System.out.println("URL : "+api);
URL url = new URL(api);
HttpURLConnection httpConnection = (HttpURLConnection)url.openConnection();
httpConnection.connect();
responseCode = httpConnection.getResponseCode();
if(responseCode == 200)
{
DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();;
Document document = builder.parse(httpConnection.getInputStream());
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile("/GeocodeResponse/status");
String status = (String)expr.evaluate(document, XPathConstants.STRING);
if(status.equals("OK"))
{
expr = xpath.compile("//geometry/location/lat");
String latitude = (String)expr.evaluate(document, XPathConstants.STRING);
expr = xpath.compile("//geometry/location/lng");
String longitude = (String)expr.evaluate(document, XPathConstants.STRING);
return new double[] {Double.parseDouble(latitude), Double.parseDouble(longitude)};
}
}
return new double[]{0,0};
}
现在,上面的 iOS 函数只运行 setupMarker 函数,其中 Android 方法 returns 坐标,没什么大不了的!
我遇到的问题是,我为两个函数提供了完全相同的地址参数。
iOSreturns所有坐标完美.
然而,Android 只有 returns 大约 30% 正确。
是否有一个 Android 函数等同于上面的 iOS 函数,或者只有一个可以正确地理编码的函数。
如您所见,Android 在此处调用了 API:
http://maps.googleapis.com/maps/api/geocode/xml?address=
我也测试过这个,效果不是很好,至少不如iOS。
我该怎么办?
编辑 - 一些示例(全部适用于 iOS)
- EBS,伯灵顿路 2 号,都柏林 2
- AIB Bankcentre, Merrion Road, Ballsbridge, Dublin 4, Ireland
- AIB, Unit 33, Sandyford Business Centre, Sandyford, Dublin 18
尝试使用 URL returns 格式的 JSON 数据,然后您可以解析并获取纬度和经度。这是一个例子:
public static void getLatLongFromAddress(String youraddress) {
String uri = "http://maps.google.com/maps/api/geocode/json?address=" +
youraddress + "&sensor=false";
HttpGet httpGet = new HttpGet(uri);
HttpClient client = new DefaultHttpClient();
HttpResponse response;
StringBuilder stringBuilder = new StringBuilder();
try {
response = client.execute(httpGet);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
double lng = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lng");
double lat = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lat");
Log.d("latitude", "" + lat);
Log.d("longitude", "" + lng);
} catch (JSONException e) {
e.printStackTrace();
}
}
希望这对您有所帮助。