Django:如何将数据插入字段,其中pk =?

Django: How to insert data into field, where pk =?

假设我有一个事件加载到数据库中,descriptionstatus 字段中有信息,但 action_taken 为空。

class Incident(models.Model):
    description = models.TextField()
    status = models.ForeignKey(Status, default="open")
    action_taken = models.TextField()

如何使用此表单将信息加载到 action_taken 字段并查看?

forms.py

class ResolveForm(forms.Form):
    action_taken = forms.CharField(widget=forms.Textarea)

views.py

def detail(request, incident_id):

    incident = get_object_or_404(Incident, pk=incident_id)
    template = "incidents/detail.html"

    if request.method == 'POST':    
        form = ResolveForm(request.POST or None)
        if form.is_valid():     
            action_taken = (form.cleaned_data['action_taken'])

            ######### MY EFFORTS #########################
            q = Incident(action_taken=action_taken)
            q.save()
            print(incident.id)
            #new_incident, created = Incident.objects.get_or_create(action_taken)
            ##############################################

            return render(request, template, {'form': form})
    else:
        form = ResolveForm()        
        context = { 'incident': incident,
                    'form': form}

        return render(request, template, context)

错误

incident.action_taken = action_taken

错误:名称'action_taken'未定义

How can I load information into the action_taken field using this form and view?

我看到您已经有了模型实例 incident,所以应该这样做

incident = get_object_or_404(Incident, pk=incident_id)
incident.action_taken = action_taken
incident.save()

如果您在更新中不想触及其他字段:

incident = get_object_or_404(Incident, pk=incident_id)
incident.action_taken = action_taken
incident.save(update_fields=['action_taken'])

评论你的尝试:

q = Incident(action_taken=action_taken)
q.save()

这不会获取您要更新的对象,而是会创建一个新对象并保存(不是您想要的)