Django:如何将数据插入字段,其中pk =?
Django: How to insert data into field, where pk =?
假设我有一个事件加载到数据库中,description
和 status
字段中有信息,但 action_taken
为空。
class Incident(models.Model):
description = models.TextField()
status = models.ForeignKey(Status, default="open")
action_taken = models.TextField()
如何使用此表单将信息加载到 action_taken
字段并查看?
forms.py
class ResolveForm(forms.Form):
action_taken = forms.CharField(widget=forms.Textarea)
views.py
def detail(request, incident_id):
incident = get_object_or_404(Incident, pk=incident_id)
template = "incidents/detail.html"
if request.method == 'POST':
form = ResolveForm(request.POST or None)
if form.is_valid():
action_taken = (form.cleaned_data['action_taken'])
######### MY EFFORTS #########################
q = Incident(action_taken=action_taken)
q.save()
print(incident.id)
#new_incident, created = Incident.objects.get_or_create(action_taken)
##############################################
return render(request, template, {'form': form})
else:
form = ResolveForm()
context = { 'incident': incident,
'form': form}
return render(request, template, context)
错误
incident.action_taken = action_taken
错误:名称'action_taken'未定义
How can I load information into the action_taken
field using this form and view?
我看到您已经有了模型实例 incident
,所以应该这样做
incident = get_object_or_404(Incident, pk=incident_id)
incident.action_taken = action_taken
incident.save()
如果您在更新中不想触及其他字段:
incident = get_object_or_404(Incident, pk=incident_id)
incident.action_taken = action_taken
incident.save(update_fields=['action_taken'])
评论你的尝试:
q = Incident(action_taken=action_taken)
q.save()
这不会获取您要更新的对象,而是会创建一个新对象并保存(不是您想要的)
假设我有一个事件加载到数据库中,description
和 status
字段中有信息,但 action_taken
为空。
class Incident(models.Model):
description = models.TextField()
status = models.ForeignKey(Status, default="open")
action_taken = models.TextField()
如何使用此表单将信息加载到 action_taken
字段并查看?
forms.py
class ResolveForm(forms.Form):
action_taken = forms.CharField(widget=forms.Textarea)
views.py
def detail(request, incident_id):
incident = get_object_or_404(Incident, pk=incident_id)
template = "incidents/detail.html"
if request.method == 'POST':
form = ResolveForm(request.POST or None)
if form.is_valid():
action_taken = (form.cleaned_data['action_taken'])
######### MY EFFORTS #########################
q = Incident(action_taken=action_taken)
q.save()
print(incident.id)
#new_incident, created = Incident.objects.get_or_create(action_taken)
##############################################
return render(request, template, {'form': form})
else:
form = ResolveForm()
context = { 'incident': incident,
'form': form}
return render(request, template, context)
错误
incident.action_taken = action_taken
错误:名称'action_taken'未定义
How can I load information into the
action_taken
field using this form and view?
我看到您已经有了模型实例 incident
,所以应该这样做
incident = get_object_or_404(Incident, pk=incident_id)
incident.action_taken = action_taken
incident.save()
如果您在更新中不想触及其他字段:
incident = get_object_or_404(Incident, pk=incident_id)
incident.action_taken = action_taken
incident.save(update_fields=['action_taken'])
评论你的尝试:
q = Incident(action_taken=action_taken)
q.save()
这不会获取您要更新的对象,而是会创建一个新对象并保存(不是您想要的)