如何在Unity中制作onGUI方法？

Question

using UnityEngine;
using System.Collections;

public class GameRootScript : MonoBehaviour {

    public GameObject prefab = null;

    private AudioSource audio;
    public AudioClip jumpSound;

    public Texture2D icon = null;
    public static string mes_text = "test";


    // Use this for initialization
    void Start () {
        this.audio = this.gameObject.AddComponent<AudioSource> ();
        this.audio.clip = this.jumpSound;
        this.audio.loop = false;
    }

    void onGUI()
    {
        Debug.Log ("Image");
        GUI.DrawTexture (new Rect (Screen.width/2, 64, 64, 64), icon);
        GUI.Label (new Rect (Screen.width / 2, 128, 128, 32), mes_text);
    }

    // Update is called once per frame
    void Update () {
        if(Input.GetKeyDown (KeyCode.Z)){
            Debug.Log("Prefab");
            GameObject go = GameObject.Instantiate(this.prefab) as GameObject;
            go.transform.position = new Vector3(Random.Range(-2.0f,2.0f), 1.0f, 1.0f);

            this.audio.Play();
        }
    }
}

我在Unity中制作了onGUI()方法，但是这个方法不起作用。
只是照着书看，不知道是什么问题
即使我编译该代码也没有错误。
书上的Unity版本是4.xx，我的Unity版本是5.1.2.

Answer 1

您的 onGUI 方法有错字。它应该是 OnGUI 大写 "O".

由于存在拼写错误，即使可以编译，Unity 引擎基本上也会忽略此方法。

如何在Unity中制作onGUI方法？

How to make the onGUI method in Unity?

c#

unity3d

unityscript