Python

Question

我只想提取邮件正文和 return。我可以过滤字段并显示代码段而不是正文。

def GetMimeMessage(service, user_id, msg_id):
    try:
            message = service.users().messages().get(userId=user_id, id=msg_id, format='raw').execute()
            print 'Message snippet: %s' % message['snippet']
            msg_str = base64.urlsafe_b64decode(message['raw'].encode('ASCII'))
            mime_msg = email.message_from_string(msg_str)
            return mime_msg
    except errors.HttpError, error:
            print 'An error occurred: %s' % error

https://developers.google.com/gmail/api/v1/reference/users/messages/get

Answer 1

试试这个：

mail 参数是你的 mime_msg 变量

def get_mpart(mail):
    maintype = mail.get_content_maintype()
    if maintype == 'multipart':
        for part in mail.get_payload():
            # This includes mail body AND text file attachments.
            if part.get_content_maintype() == 'text':
                return part.get_payload()
        # No text at all. This is also happens
        return ""
    elif maintype == 'text':
        return mail.get_payload()


def get_mail_body(mail):
    """
    There is no 'body' tag in mail, so separate function.
    :param mail: Message object
    :return: Body content
    """
    body = ""
    if mail.is_multipart():
        # This does not work.
        # for part in mail.get_payload():
        #    body += part.get_payload()
        body = get_mpart(mail)
    else:
        body = mail.get_payload()
    return body

Answer 2

base64url 编码的字符串在传递到解码函数之前需要进行一些更改，如下所示：

msg_str = base64.urlsafe_b64decode(message['raw'].replace('-_', '+/').encode('ASCII'))

看看这是否有帮助

Answer 3

谢谢。所以经过一些修改，这里的解决方案：

def GetMessageBody(service, user_id, msg_id):
    try:
            message = service.users().messages().get(userId=user_id, id=msg_id, format='raw').execute()
            msg_str = base64.urlsafe_b64decode(message['raw'].encode('ASCII'))
            mime_msg = email.message_from_string(msg_str)
            messageMainType = mime_msg.get_content_maintype()
            if messageMainType == 'multipart':
                    for part in mime_msg.get_payload():
                            if part.get_content_maintype() == 'text':
                                    return part.get_payload()
                    return ""
            elif messageMainType == 'text':
                    return mime_msg.get_payload()
    except errors.HttpError, error:
            print 'An error occurred: %s' % error

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