如何使用 RowMapper 向 table 中插入记录？

Question

如何使用行映射器将数据插入 table？

我正在尝试这个：

Employee user1 = jtemplate.queryForObject("INSERT INTO employee(id, name,salary) VALUES(10,'ABC',12333);",new BeanPropertyRowMapper<Employee>(Employee.class));

它给我带来了严重的 SQL 语法错误。

但查询在 SQL 开发人员中有效。我做错了什么？

Exception in thread "main" org.springframework.jdbc.BadSqlGrammarException: StatementCallback; bad SQL grammar [INSERT INTO employee(id, name,salary) VALUES(99,'ABC',12333)]; nested exception is java.sql.SQLSyntaxErrorException: ORA-00900: invalid SQL statement

    at org.springframework.jdbc.support.SQLErrorCodeSQLExceptionTranslator.doTranslate(SQLErrorCodeSQLExceptionTranslator.java:231)
    at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:73)
    at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:411)
    at org.springframework.jdbc.core.JdbcTemplate.query(JdbcTemplate.java:466)
    at org.springframework.jdbc.core.JdbcTemplate.query(JdbcTemplate.java:476)
    at com.cts.orm.rowmapper.Test.main(Test.java:29)
Caused by: java.sql.SQLSyntaxErrorException: ORA-00900: invalid SQL statement

    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:445)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:389)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:382)
    at oracle.jdbc.driver.T4CTTIfun.processError(T4CTTIfun.java:600)
    at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:450)
    at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:192)
    at oracle.jdbc.driver.T4C8Odscrarr.doODNY(T4C8Odscrarr.java:98)
    at oracle.jdbc.driver.T4CStatement.doDescribe(T4CStatement.java:805)
    at oracle.jdbc.driver.OracleStatement.describe(OracleStatement.java:3978)
    at oracle.jdbc.driver.OracleResultSetMetaData.<init>(OracleResultSetMetaData.java:55)
    at oracle.jdbc.driver.OracleResultSetImpl.getMetaData(OracleResultSetImpl.java:175)
    at org.springframework.jdbc.core.BeanPropertyRowMapper.mapRow(BeanPropertyRowMapper.java:240)
    at org.springframework.jdbc.core.RowMapperResultSetExtractor.extractData(RowMapperResultSetExtractor.java:93)
    at org.springframework.jdbc.core.RowMapperResultSetExtractor.extractData(RowMapperResultSetExtractor.java:60)
    at org.springframework.jdbc.core.JdbcTemplateQueryStatementCallback.doInStatement(JdbcTemplate.java:455)
    at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:400)
    ... 3 more

Answer 1

删除语句末尾的分号应该可以解决问题，像这样使用它。使用 jdbc 模板时，在 sql 语句

末尾使用分号是不好的

Employee user1 = jtemplate.queryForObject("INSERT INTO employee(id, name,salary) VALUES(10,'ABC',12333)",new BeanPropertyRowMapper<Employee>(Employee.class));

尝试像这样使用它

    jtemplate.update("INSERT INTO Employee(ID, NAME, Salary) VALUES (?, ?, ?)",
     new Object[] { employee.getId(), employee.getName(), employee.getSalary() });

我正在使用它并且它工作正常并且没有显示错误

Answer 2

试试这个：

jdbcTemplate.update("INSERT INTO employee(id, name,salary) VALUES(?,?,?)", 10, "ABC", 12333);

Answer 3

NamedParameterJdbcTemplate 为所欲为：

namedParameterJdbcTemplate.update(
    "INSERT INTO employee(id, name, salary) VALUES (:id, :name, :salary)",
    new BeanPropertySqlParameterSource(Employee.class));

如何使用 RowMapper 向 table 中插入记录？

How to use RowMapper to insert record into table?

jdbctemplate