将带有转义字符的字符串分配给属性

Question

我想为 $Shortcut 对象的字符串属性设置一个字符串路径，但它无法正常工作。

运行此代码：

$WshShell = New-Object -comObject WScript.Shell ;
$Shortcut = $WshShell.CreateShortcut('c:\aaa.lnk');
$Shortcut.TargetPath = '"c:\Program Files\MyApp.exe" /param1: (2) /param2 "val"'

我在设置 $Shortcut.TargetPath 时遇到此错误：

Exception setting "TargetPath": "The parameter is incorrect. (Exception from HRESULT:
0x80070057 (E_INVALIDARG))"
At line:1 char:11
+ $Shortcut. <<<< TargetPath = '"c:\Program Files\MyApp.exe" /param1: (2) /param2 "val"'
    + CategoryInfo          : InvalidOperation: (:) [], RuntimeException
    + FullyQualifiedErrorId : PropertyAssignmentException

奇怪的是，尝试在新的自定义对象上重现此行为，问题并没有出现。只需运行以下命令：

$object = New-Object -TypeName PSObject
Add-Member -MemberType NoteProperty -Name prop -Value "aaa"
$object.prop = '"c:\Program Files\MyApp.exe" /param1: (2) /param2 "val"'

Answer 1

如有疑问，请阅读 documentation. The TargetPath property takes just the path to the excutable. The arguments go into the Arguments 属性:

$WshShell = New-Object -ComObject WScript.Shell
$Shortcut = $WshShell.CreateShortcut('c:\aaa.lnk')
$Shortcut.TargetPath = 'c:\Program Files\MyApp.exe'
$Shortcut.Arguments  = '/param1: (2) /param2 "val"'

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将带有转义字符的字符串分配给属性