PHP-单元测试：如何实现TYPO3 Extbase对象接口

Question

我的控制器 PHP 单元测试有一些问题：

这是我的控制器代码中需要测试的函数

public function newAction(\ReRe\Rere\Domain\Model\Fach $newFach = NULL) {
    // Holt die übergebene Modulnummer
    if ($this->request->hasArgument('modul')) {
        // Holt das Modul-Objekt aus dem Repository
        $modul = $this->modulRepository->findByUid($this->request->getArgument('modul'));
    }
    // Ausgabe in der View
    $this->view->assignMultiple(array(
        'newFach' => $newFach, self::MODULUID => $modul->getUid(), 'modulname' => $modul->getModulname(), 'modulnummer' => $modul->getModulnr(), 'gueltigkeitszeitraum' => $modul->getGueltigkeitszeitraum()
    ));
}

这是PHP函数的单元测试代码

public function newActionAssignsTheGivenFachToView() {
    $fach = new \ReRe\Rere\Domain\Model\Fach();
    $modul = array('');

    $MockGetArgument = $this->getMock('ReRe\Rere\Domain\Repository\ModulRepository', array('getArgument'), array(), '', FALSE);
    $MockGetArgument->expects($this->any())->method('getArgument')->with('modul');

    $mockRequest = $this->getMock('TYPO3\CMS\Extbase\Mvc\Request');
    $mockRequest->expects($this->any())->method('hasArgument')->with('modul');
    $this->inject($this->subject, 'request', $mockRequest);

    $objectManager = $this->getMock('TYPO3\CMS\Extbase\Persistence\ObjectManager', array(), array(), '', FALSE);
    $this->inject($this->subject, 'objectManager', $objectManager);

    $modulRepository = $this->getMock('ReRe\Rere\Domain\Repository\ModulRepository');
    $modulRepository->expects($this->any())->method('findByUid')->will($this->returnValue($modul));
    $this->inject($this->subject, 'modulRepository', $modulRepository);

    $view = $this->getMock(self::VIEWINTERFACE);
    $view->expects($this->any())->method(self::ASSIGN)->with('newFach', $fach);
    $this->inject($this->subject, 'view', $view);

    $this->subject->newAction($fach);
}

我在运行测试

时不断收到此错误

测试用例 newActionAssignsTheGivenFachToView 出错文件：/Applications/MAMP/typo3_src/typo3/sysext/extbase/Classes/Mvc/Controller/AbstractController.php 线路：162 传递给 TYPO3\CMS\Extbase\Mvc\Controller\AbstractController::injectObjectManager() 的参数 1 必须实现接口 TYPO3\CMS\Extbase\Object\ObjectManagerInterface，给定的 Mock_ObjectManager_fa2fde18 实例，在第 260 行的 /Applications/MAMP/typo3_src/typo3/sysext/core/Tests/BaseTestCase.php 中调用并定义

这是来自 AbstractController.php 的那行被称为

public function injectObjectManager(\TYPO3\CMS\Extbase\Object\ObjectManagerInterface $ObjectManager) {
    $this->ObjectManager = $ObjectManager;
    $this->arguments = $this->ObjectManager->get('TYPO3\CMS\Extbase\Mvc\Controller\Arguments');
}

如何实现这个接口TYPO3\CMS\Extbase\Object\ObjectManagerInterface？

非常感谢每一个答案！几周来我一直在尝试寻找答案:(

2015 年 2 月 18 日更新：问题已解决

配置代码：

$fach = new \ReRe\Rere\Domain\Model\Fach();
        $modul = new \ReRe\Rere\Domain\Model\Modul();

        $request = $this->getMock(self::REQUEST, array(), array(), '', FALSE);
        $request->expects($this->once())->method('hasArgument')->will($this->returnValue($this->subject));

        $modulRepository = $this->getMock(self::MODULREPOSITORY, array('findByUid'), array(), '', FALSE);
        $modulRepository->expects($this->once())->method('findByUid')->will($this->returnValue($modul));
        $this->inject($this->subject, 'modulRepository', $modulRepository);

        $request->expects($this->once())->method('getArgument')->will($this->returnValue($this->subject));
        $this->inject($this->subject, 'request', $request);

        $view = $this->getMock(self::VIEWINTERFACE);
        $view->expects($this->once())->method('assignMultiple')->with(array(
            'newFach' => $fach,
            'moduluid' => $modul->getUid(),
            'modulname' => $modul->getModulname(),
            'modulnummer' => $modul->getModulnr(),
            'gueltigkeitszeitraum' => $modul->getGueltigkeitszeitraum()
        ));
        $this->inject($this->subject, 'view', $view);

        $this->subject->newAction($fach);

Answer 1

您在模拟错误的（不存在的）ObjectManager。正确的命名空间是 TYPO3\CMS\Extbase\Object\ObjectManager.

所以正确的行应该是$objectManager = $this->getMock('TYPO3\CMS\Extbase\Object\ObjectManager', ...);

否则我想知道你为什么要模拟 ObjectManager。你没有在你的方法中使用它。

附带说明：如果请求中没有 'modul'，您的代码将失败。然后 $modul 未设置，您将在非对象上调用 getUid()、getModulname()、...。

PHP-单元测试：如何实现TYPO3 Extbase对象接口

PHP-Unit Tests: how to implement a TYPO3 Extbase object interface

implementation

phpunit

interface

typo3

extbase