将十进制转换为二进制和将二进制转换为十进制时，substr、整数和循环的问题

Question

我为不使用 ToBinaryString 和 ToString 方法的人编写了这个程序。我编写了该应用程序，但它不起作用！如果我做 Dec2Bin，它会给我 null！如果我执行 Bin2Dec，它会给我 String out of index: -1！有人可以帮我解决吗？

代码：

package decimalBinary;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class DecBin {
    public static void main(String[] args) throws NumberFormatException, IOException {
        int conargs1,conargs2;
        // conargs1 is input
        // conargs2 is mode, if = 1 then dec2bin, if = 2 then bin2dec
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        System.out.println("Enter number: ");
        conargs1=Integer.parseInt(br.readLine());
        System.out.println("Enter mode: ");
        conargs2 = Integer.parseInt(br.readLine());
        System.out.println(conargs2==1 ? "Dec2Bin" : (conargs2==2 ? "Bin2Dec" : "none"));
        if (args.length == 2){ // TO BINARY
            if(conargs2==1){
                System.out.println(DecBin.dec2bin(String.valueOf(conargs1)));
            }else if (conargs2==2){ // TO DECIMAL
                System.out.println(DecBin.bin2dec(String.valueOf(conargs1)));
            }
            System.exit(0);
        }
    }

    public static String dec2bin(String arg){
        String out = null;
        String tmp;
        long i, x;
        int maxpower = 30;
        x = Long.parseLong(arg);

        if (x == 0){
            return "0";
        }else if (x > 0){ // positive decimals
            if (x > Math.pow(2, maxpower)) {
                return "should be no larger than " + String.valueOf(2 ^ maxpower);
            }
            out = "";
            for(i = maxpower+1; i <= 0; i--){
                if (x % (Math.pow(2, i))==0){
                    out = out + "1";
                }else{
                    out = out + "0";
                }
            }
        }else{ // negative decimals
            x = -x;
            x = Math.abs(x);
            if (x > Math.pow(2, maxpower)) {
                return "should be no larger than " + String.valueOf(2 ^ maxpower);
            }
            out = "";
            for(i = maxpower+1; i <= 0; i--){ // Inverted Binary
                if (x % (Math.pow(2, i))==0){
                    out = out + "0";
                }else{
                    out = out + "1";
                }
            }

            x = DecBin.bin2dec(out)+1;

            out= "";
            for(i = maxpower+1; i <= 0; i--){
                if (x % (Math.pow(2, i))==0){
                    out = out + "1";
                }else{
                    out = out + "0";
                }

            }

        }
        return out;
    }

    public static long bin2dec(String arg){
        // If it was a positive number.
        long dec = 0; // initializing decimal number
        long length = arg.length(); // length of our binary string
        char temp;
        //long charplace;
        long lengthofchar = 1;
        long x = 0;
        if (arg.length() <= 0){return 0;}
        for (x = 0; x <= length; x++) {
            // charplace = 0;
            // charplace = -x;
            // charplace += -1;
            // charplace += arg.length();

            // charplace = Long.sum(charplace, 5);
            // charplace -= lengthofchar;
            // charplace--;
            temp = arg.charAt(arg.length()-x-1);
            // length = length - 1;
            if (temp != '0') {
                dec += Math.pow(2 , x - 1);
            }
        }

        return dec;
    }

}

这是我在使用 bin2dec 时遇到的错误：

Exception in thread "main" java.lang.Error: Unresolved compilation problem: 
    The method charAt(int) in the type String is not applicable for the arguments (long)

    at decimalBinary.DecBin.bin2dec(DecBin.java:98)
    at decimalBinary.DecBin.main(DecBin.java:22)

在此之前，我为变量使用了 int 类型，但在我使用 charAt 的行中得到了 String out of Index: -1。之前我也用过substr，我也遇到了同样的错误！

编辑：如果我使用 temp = arg.charAt(Integer.parseInt(String.valueOf(arg.length()-x-1))); 我会得到这个错误：

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: -1
    at java.lang.String.charAt(Unknown Source)
    at decimalBinary.DecBin.bin2dec(DecBin.java:98)
    at decimalBinary.DecBin.main(DecBin.java:22)

Answer 1

你的 for loop 不等式语句有问题，即：

在您的 dec2bin 方法中：for(i = maxpower+1; i <= 0; i--) 应该是 for(i = maxpower+1; i >= 0; i--) 因为您永远不会进入循环并且您打印 out 的默认值 null.

在您的 bin2dec 方法中：for (x = 0; x <= length; x++) 应该是 for (x = 0; x < length; x++) 因为 temp = arg.charAt(arg.length()-x-1); 在循环结束时可以是 -1。

*在使用错误堆栈跟踪更新问题后，使用 int 而不是 long 作为变量，否则您需要转换为 int 才能使 charAt 工作.

Answer 2

最后，我成功地编辑了我的代码:)

感谢 Konstantinos Chalkias 我找到了我必须做的事情 :D

这是最后的 class（效果很好！）：

package decimalBinary;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class DecBin {
    public static void main(String[] args) throws NumberFormatException, IOException {
        int conargs1,conargs2;
        // conargs1 is input
        // conargs2 is mode, if = 1 then dec2bin, if = 2 then bin2dec
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        System.out.println("Enter number: ");
        conargs1=Integer.parseInt(br.readLine());
        System.out.println("Enter mode: ");
        conargs2 = Integer.parseInt(br.readLine());
        System.out.println(conargs2==1 ? "Dec2Bin" : (conargs2==2 ? "Bin2Dec" : "none"));
        if (args.length == 2){ // TO BINARY
            if(conargs2==1){
                System.out.println(DecBin.dec2bin(String.valueOf(conargs1)));
            }else if (conargs2==2){ // TO DECIMAL
                System.out.println(DecBin.bin2dec(String.valueOf(conargs1)));
            }
            System.exit(0);
        }
    }

    public static String dec2bin(String arg){
        String out = null;
        String tmp;
        long i, x;
        int maxpower = 30;
        x = Integer.parseInt(arg);

        if (x == 0){
            return "0";
        }else if (x > 0){ // positive decimals
            if (x > Math.pow(2, maxpower)) {
                return "should be no larger than " + String.valueOf(2 ^ maxpower);
            }
            out = "";

            int binary[] = new int[30];
            int index = 0;
            while(x > 0){
                binary[index++] = (int) (x % 2);
                x = x/2;
            }

            for(i = index-1;i >= 0;i--){
                out = out+binary[(int) i];
            }
        }else{ // negative decimals
            // x = -x;
            x = Math.abs(x); // convert positive of decimal to binary 
            if (x > Math.pow(2, maxpower)) {
                return "should be no larger than " + String.valueOf(2 ^ maxpower);
            }
            long xBinaryPositive;
            xBinaryPositive = Long.parseLong(DecBin.dec2bin(String.valueOf(x)));
            String xBinaryInverted;
            out = "";


            xBinaryInverted = String.valueOf(xBinaryPositive).replace('0', '2').replace('1', '0').replace('2', '1');
            long xBinaryInvertedIntVal;
            xBinaryInvertedIntVal = DecBin.bin2dec(xBinaryInverted);
            out = DecBin.dec2bin(String.valueOf(xBinaryInvertedIntVal+1));
        }
        return out;
    }

    public static long bin2dec(String binaryInput){
        long binary = Long.parseLong(binaryInput);
        long decimal = 0;
        long power = 0;
        while(true){
            if(binary == 0){
                break; 
            } else {
                long tmp = binary % 10;
                decimal += tmp * Math.pow(2, power);
                binary = binary/10;
                power++;
            }
        } 
        return decimal; 
    }
}

在最终代码中，我使用 while 而不是 for。
我在 Java2Novice's Interview Programs 中找到了大部分代码。非常感谢他们提供这些代码。

将十进制转换为二进制和将二进制转换为十进制时，substr、整数和循环的问题

iProblems with substr, integers and loops in converting decimal to binary and binary to decimal

java

substr