JAVA 中具有反向引用的递归组捕获正则表达式

Question

我正在尝试在正则表达式中使用对组的反向引用以递归方式捕获字符串中的多个组。即使我使用模式和匹配器以及 "while(matcher.find())" 循环，它仍然只捕获最后一个实例而不是所有实例。在我的例子中，唯一可能的标签是、、、、、、、。由于这些是格式化标签，我需要捕获：

标签外的任何文本（以便我可以将其格式化为 "normal" 文本，我将通过在一组中捕获标签之前的任何文本而在另一组中捕获标签本身来解决这个问题组，当我遍历这些事件时，我删除了从原始字符串中捕获的所有内容；如果我最后留下任何文本，我将其格式化为 "normal" 文本）
标签的"name"让我知道我将如何拥有格式化标签内的文本
将根据标签名称及其相关规则格式化的标签文本内容

这是我的示例代码：

        String currentText = "the man said:<pof>“This one, at last, is bone of my bones</pof><poi>and flesh of my flesh;</poi><po>This one shall be called ‘woman,’</po><poil>for out of man this one has been taken.”</poil>";
        String remainingText = currentText;

        //first check if our string even has any kind of xml tag, because if not we will just format the whole string as "normal" text
        if(currentText.matches("(?su).*<[/]{0,1}(?:sm|po)[f|l|s|i|3]{0,1}[f|l]{0,1}>.*"))
        {                
            //an opening or closing tag has been found, so let us start our pattern captures
            //I am using a backreference \2 to make sure the closing tag is the same as the opening tag
            Pattern pattern1 = Pattern.compile("(.*)<((sm|po)[f|l|s|i|3]{0,1}[f|l]{0,1})>(.*?)</\2>",Pattern.UNICODE_CHARACTER_CLASS);
            Matcher matcher1 = pattern1.matcher(currentText);                
            int iteration = 0;
            while(matcher1.find()){
                System.out.print("Iteration ");
                System.out.println(++iteration);
                System.out.println("group1:"+matcher1.group(1));
                System.out.println("group2:"+matcher1.group(2));
                System.out.println("group3:"+matcher1.group(3));
                System.out.println("group4:"+matcher1.group(4));

                if(matcher1.group(1) != null && matcher1.group(1).isEmpty() == false)
                {
                    m_xText.insertString(xTextRange, matcher1.group(1), false);
                    remainingText = remainingText.replaceFirst(matcher1.group(1), "");
                }
                if(matcher1.group(4) != null && matcher1.group(4).isEmpty() == false)
                {
                    switch (matcher1.group(2)) {
                        case "pof": [...]
                        case "pos": [...]
                        case "poif": [...]
                        case "po": [...]
                        case "poi": [...]
                        case "pol": [...]
                        case "poil": [...]
                        case "sm": [...]
                    }
                    remainingText = remainingText.replaceFirst("<"+matcher1.group(2)+">"+matcher1.group(4)+"</"+matcher1.group(2)+">", "");
                }
            }

System.out.println 在我的控制台中只输出一次，结果如下：

Iteration 1:
  group1:the man said:<pof>“This one, at last, is bone of my bones</pof><poi>and flesh of my flesh;</poi><po>This one shall be called ‘woman,’</po>; 
  group2:poil
  group3:po
  group4:for out of man this one has been taken.”

要忽略第 3 组，唯一有用的组是 1、2 和 4（第 3 组是第 2 组的一部分）。为什么这只捕获最后一个标记实例 "poil"，而不捕获前面的 "pof"、"poi" 和 "po" 标记？

我希望看到的输出是这样的：

Iteration 1:
  group1:the man said:
  group2:pof
  group3:po
  group4:“This one, at last, is bone of my bones

Iteration 2:
  group1:
  group2:poi
  group3:po
  group4:and flesh of my flesh;

Iteration 3:
  group1:
  group2:po
  group3:po
  group4:This one shall be called ‘woman,’

Iteration 3:
  group1:
  group2:poil
  group3:po
  group4:for out of man this one has been taken.”

Answer 1

我刚刚找到了这个问题的答案，它只是在第一次捕获中需要一个非贪婪量词，就像我在第四个捕获组中那样。这完全符合需要：

Pattern pattern1 = Pattern.compile("(.*?)<((sm|po)[f|l|s|i|3]{0,1}[f|l]{0,1})>(.*?)</\2>",Pattern.UNICODE_CHARACTER_CLASS);

JAVA 中具有反向引用的递归组捕获正则表达式

Recursive group capturing regex with backreference in JAVA

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recursive-regex