ServiceWorker 'fetch' 事件未针对图标触发

Question

我正在使用 Service Worker 在我的站点中缓存内容 (https://adhiyan.in)。 Serviceworker 正在正确安装和激活。在 'fetch' 事件处理程序中，如果可用，我将从缓存中提供内容。如果内容在缓存中不可用，我将获取内容并使用相同内容更新缓存。它能够提供资产并按需缓存新资产。

importScripts('/assets/js/serviceworker-cache-polyfill.js');

var CACHE_NAME = 'adhiyan-cache-v1';
var urlsToCache = [
  '/',
  '/assets/css/app.min.css',
  '/assets/js/app.min.js'
];

self.addEventListener('install', function(event) {
  // Perform install steps
  event.waitUntil(
    caches.open(CACHE_NAME)
    .then(function(cache) {
      console.log('Opened cache');
      return cache.addAll(urlsToCache);
    })
  );
});

self.addEventListener('fetch', function(event) {
  event.respondWith(
    caches.match(event.request)
    .then(function(response) {
      // Cache hit - return response
      if (response) {
        console.log("Cache hit for '" + event.request.url + "'- return response");
        return response;
      }

      console.log("Cache miss for '" + event.request.url + "'");

      // IMPORTANT: Clone the request. A request is a stream and
      // can only be consumed once. Since we are consuming this
      // once by cache and once by the browser for fetch, we need
      // to clone the response
      var fetchRequest = event.request.clone();

      return fetch(fetchRequest).then(
        function(response) {
          // Check if we received a valid response
          if (!response || response.status !== 200 || response.type !== 'basic') {
            console.log("Invalid response for '" + event.request.url + "'");
            return response;
          }

          // Cache only '/assets'
          if (event.request.url.indexOf('/assets') == -1) {
            console.log("Not an asset '" + event.request.url + "'");
            return response;
          }

          // IMPORTANT: Clone the response. A response is a stream
          // and because we want the browser to consume the response
          // as well as the cache consuming the response, we need
          // to clone it so we have 2 stream.
          var responseToCache = response.clone();
          console.log("Updating cache for '" + event.request.url + "'");
          caches.open(CACHE_NAME)
            .then(function(cache) {
              cache.put(event.request, responseToCache);
            });

          return response;
        }
      );
    })
  );
});

但是，我看到浏览器在没有触发 'fetch' 事件的情况下下载网站图标。我可以从 Chrome devtools 的网络面板确认行为。有人可以帮助我理解这种行为吗？我是否遗漏了代码中的某些内容？

Answer 1

这是 Chrome 中的错误：https://code.google.com/p/chromium/issues/detail?id=448427

它应该允许 service workers 拦截请求。

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