带有 java.util.zip 并保持结构的 Zip 目录

Question

我正在尝试压缩一个看起来像这样的文件夹：

Folder1
     file.xml
     file.xml
     folder2
        file.txt

当我用我的 Java 程序压缩它时，它看起来像这样：

Folder1.zip
   Folder1 (i dont want hist directory)
      file.xml
      file.xml
      folder2
         file.txt

我需要直接在 folder1.zip 中获取 folder1 的内容。但是，我不知道我的代码要更改什么（代码来自示例，但我找不到 link atm）。

 /*
 * Zip function zip all files and folders
 */
@SuppressWarnings("finally")
public boolean zipFiles(String srcFolder, String destZipFile) {
    boolean result = false;
    try {
        logger.info("Program Start zipping the given files");
        /*
         * send to the zip procedure
         */
        zipFolder(srcFolder, destZipFile);
        result = true;
        logger.info("Given files are successfully zipped");
    } catch (Exception e) {
        System.out.println("Some Errors happned during the zip process");
    } finally {
        return result;
    }
}

/*
 * zip the folders
 */
private void zipFolder(String srcFolder, String destZipFile) throws Exception {
    ZipOutputStream zip = null;
    FileOutputStream fileWriter = null;
    /*
     * create the output stream to zip file result
     */
    fileWriter = new FileOutputStream(destZipFile + ".zip");
    zip = new ZipOutputStream(fileWriter);
    /*
     * add the folder to the zip
     */
    addFolderToZip("", srcFolder, zip);
    /*
     * close the zip objects
     */
    zip.flush();
    zip.close();
}

/*
 * recursively add files to the zip files
 */
private void addFileToZip(String path, String srcFile, ZipOutputStream zip, boolean flag) throws Exception {
    /*
     * create the file object for inputs
     */
    File folder = new File(srcFile);

    /*
     * if the folder is empty add empty folder to the Zip file
     */
    if (flag == true) {
        zip.putNextEntry(new ZipEntry(path + "/" + folder.getName() + "/"));
    } else { /*
             * if the current name is directory, recursively traverse it
             * to get the files
             */
        if (folder.isDirectory()) {
            /*
             * if folder is not empty
             */
            addFolderToZip(path, srcFile, zip);
        } else {
            /*
             * write the file to the output
             */
            byte[] buf = new byte[1024];
            int len;
            FileInputStream in = new FileInputStream(srcFile);
            zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
            while ((len = in.read(buf)) > 0) {
                /*
                 * Write the Result
                 */
                zip.write(buf, 0, len);
            }

            in.close();
        }
    }
}

/*
 * add folder to the zip file
 */
private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip) throws Exception {
    File folder = new File(srcFolder);

    /*
     * check the empty folder
     */
    if (folder.list().length == 0) {
        logger.info(folder.getName());
        addFileToZip(path, srcFolder, zip, true);
    } else {
        /*
         * list the files in the folder
         */
        for (String fileName : folder.list()) {
            if (path.equals("")) {
                addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip, false);
            } else {
                addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip, false);
            }
        }
    }
}

Answer 1

我能够通过在添加 FileToZip 的方法中包含这行代码来解决问题

if (folder.getAbsolutePath().substring(folder.getAbsolutePath().indexOf(".")).equals(".xml")) {
                // save xml File in root directory
                zip.putNextEntry(new ZipEntry(folder.getName()));
            } else {
                zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
            }

和

 if (path.equals("")) {
                addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip, false);
            } else {
                if (rootDirectory) {
                    addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip, false);
                } else {
                    addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip, false);
                }
            }

在方法 addFolderToZip 中。