在 Tkinter 文本框中突出显示两个 xml 文件之间的差异
Highlight differences between two xml files in a Tkinter textbox
我尝试了各种逻辑和方法,甚至谷歌了很多,但仍然无法为我的问题想出满意的答案。我编写了如下所示的程序来突出显示我遇到问题的特定 xml 代码。抱歉让这个 post 有点长。我只是想清楚地解释我的问题。
编辑: 对于下面给定程序的 运行,您将需要两个 xml 文件,它们位于:sample1 and sample2。保存此文件并在下面的代码中编辑要在 C:/Users/editThisLocation/Desktop/sample1.xml
中保存文件的位置
from lxml import etree
from collections import defaultdict
from collections import OrderedDict
from distutils.filelist import findall
from lxml._elementpath import findtext
from Tkinter import *
import Tkinter as tk
import ttk
root = Tk()
class CustomText(tk.Text):
def __init__(self, *args, **kwargs):
tk.Text.__init__(self, *args, **kwargs)
def highlight_pattern(self, pattern, tag, start, end,
regexp=True):
start = self.index(start)
end = self.index(end)
self.mark_set("matchStart", start)
self.mark_set("matchEnd", start)
self.mark_set("searchLimit", end)
count = tk.IntVar()
while True:
index = self.search(pattern, "matchEnd","searchLimit",
count=count, regexp=regexp)
if index == "": break
self.mark_set("matchStart", index)
self.mark_set("matchEnd", "%s+%sc" % (index, count.get()))
self.tag_add(tag, "matchStart", "matchEnd")
def Remove_pattern(self, pattern, tag, start="1.0", end="end",
regexp=True):
start = self.index(start)
end = self.index(end)
self.mark_set("matchStart", start)
self.mark_set("matchEnd", start)
self.mark_set("searchLimit", end)
count = tk.IntVar()
while True:
index = self.search(pattern, "matchEnd","searchLimit",
count=count, regexp=regexp)
if index == "": break
self.mark_set("matchStart", index)
self.mark_set("matchEnd", "%s+%sc" % (index, count.get()))
self.tag_remove(tag, start, end)
recovering_parser = etree.XMLParser(recover=True)
sample1File = open('C:/Users/editThisLocation/Desktop/sample1.xml', 'r')
contents_sample1 = sample1File.read()
sample2File = open('C:/Users/editThisLocation/Desktop/sample2.xml', 'r')
contents_sample2 = sample2File.read()
frame1 = Frame(width=768, height=25, bg="#000000", colormap="new")
frame1.pack()
Label(frame1, text="sample 1 below - scroll to see more").pack()
textbox = CustomText(root)
textbox.insert(END,contents_sample1)
textbox.pack(expand=1, fill=BOTH)
frame2 = Frame(width=768, height=25, bg="#000000", colormap="new")
frame2.pack()
Label(frame2, text="sample 2 below - scroll to see more").pack()
textbox1 = CustomText(root)
textbox1.insert(END,contents_sample2)
textbox1.pack(expand=1, fill=BOTH)
sample1 = etree.parse("C:/Users/editThisLocation/Desktop/sample1.xml", parser=recovering_parser).getroot()
sample2 = etree.parse("C:/Users/editThisLocation/Desktop/sample2.xml", parser=recovering_parser).getroot()
ToStringsample1 = etree.tostring(sample1)
sample1String = etree.fromstring(ToStringsample1, parser=recovering_parser)
ToStringsample2 = etree.tostring(sample2)
sample2String = etree.fromstring(ToStringsample2, parser=recovering_parser)
timesample1 = sample1String.findall('{http://www.example.org/eHorizon}time')
timesample2 = sample2String.findall('{http://www.example.org/eHorizon}time')
for i,j in zip(timesample1,timesample2):
for k,l in zip(i.findall("{http://www.example.org/eHorizon}feature"), j.findall("{http://www.example.org/eHorizon}feature")):
if [k.attrib.get('color'), k.attrib.get('type')] != [l.attrib.get('color'), l.attrib.get('type')]:
faultyLine = [k.attrib.get('color'), k.attrib.get('type'), k.text]
def high(event):
textbox.tag_configure("yellow", background="yellow")
limit_1 = '<p1:time nTimestamp="{0}">'.format(5) #limit my search between timestamp 5 and timestamp 6
limit_2 = '<p1:time nTimestamp="{0}">'.format((5+1)) # timestamp 6
highlightString = '<p1:feature color="{0}" type="{1}">{2}</p1:feature>'.format(faultyLine[0],faultyLine[1],faultyLine[2]) #string to be highlighted
textbox.highlight_pattern(limit_1, "yellow", start=textbox.search(limit_1, '1.0', stopindex=END), end=textbox.search(limit_2, '1.0', stopindex=END))
textbox.highlight_pattern(highlightString, "yellow", start=textbox.search(limit_1, '1.0', stopindex=END), end=textbox.search(limit_2, '1.0', stopindex=END))
button = 'press here to highlight error line'
c = ttk.Label(root, text=button)
c.bind("<Button-1>",high)
c.pack()
root.mainloop()
我想要的
如果你运行上面的代码,它会给出下面给出的输出:
正如您在图片中看到的,我只打算突出显示带有绿色勾号的代码。你们中的一些人可能会考虑限制开始和结束索引以突出显示该模式。但是,如果您在我的程序中看到我已经在使用开始和结束索引将我的输出限制为仅 nTimestamp="5"
,为此我正在使用 limit_1
和 limit_2
变量。
那么在这种类型的数据中如何正确地突出显示许多内部个体中的一个模式nTimestamp
?
编辑:这里我特别想突出显示 nTimestamp="5"
中的第 3 项,因为该项目不存在于 sample2.xml
中,正如您在两个 xml 文件和当程序 运行s 它也区分这一点。唯一的问题是突出显示正确的项目,在我的案例中是第 3 项。
我正在使用来自 Bryan Oakley 的代码 here
的突出显示 class
编辑最近
根据 kobejohn 在评论中提出的问题,目标文件永远不会为空。目标文件总是有可能有额外或缺失的元素。最后,我目前的意图是仅突出显示不同或缺失的深层元素以及它们所在的 timestamps
。然而, timestamps
的突出显示是正确完成的,但是像上面解释的那样突出显示深层元素的问题仍然是一个问题。感谢 kobejohn 澄清这一点。
注意:
我知道并且你可能会建议正确工作的一种方法是提取绿色勾选图案的索引并简单地 运行 在其上突出显示标记,但这种方法是非常硬编码的并且在大您必须处理大量变化的数据是完全无效的。我正在寻找另一个更好的选择。
此解决方案的工作原理是根据您提供的描述在 base.xml
和 test.xml
之间执行简化的差异。 diff 结果是第 3 棵 XML 树,它结合了原始树。输出是对文件之间不匹配的行进行颜色编码突出显示的差异。
我希望你能使用这个或者根据你的需要改编它。
复制粘贴脚本
import copy
from lxml import etree
import Tkinter as tk
# assumption: the root element of both trees is the same
# note: missing subtrees will only have the parent element highlighted
def element_content_equal(e1, e2):
# starting point here:
try:
if e1.tag != e1.tag:
return False
elif e1.text != e2.text:
return False
elif e1.tail != e2.tail:
return False
elif e1.attrib != e2.attrib:
return False
except AttributeError:
# e.g. None is passed in for an element
return False
return True
def element_is_in_sequence(element, sequence):
for e in sequence:
if element_content_equal(e, element):
return True
return False
def copy_element_without_children(element):
e_copy = etree.Element(element.tag, attrib=element.attrib, nsmap=element.nsmap)
e_copy.text = element.text
e_copy.tail = element.tail
return e_copy
# start at the root of both xml trees
parser = etree.XMLParser(recover=True, remove_blank_text=True)
base_root = etree.parse('base.xml', parser=parser).getroot()
test_root = etree.parse('test.xml', parser=parser).getroot()
# each element from the original xml trees will be placed into a merge tree
merge_root = copy_element_without_children(base_root)
# additionally each merge tree element will be tagged with its source
DIFF_ATTRIB = 'diff'
FROM_BASE_ONLY = 'base'
FROM_TEST_ONLY = 'test'
# process the pair of trees, one set of parents at a time
parent_stack = [(base_root, test_root, merge_root)]
while parent_stack:
base_parent, test_parent, merge_parent = parent_stack.pop()
base_children = base_parent.getchildren()
test_children = test_parent.getchildren()
# compare children and transfer to merge tree
base_children_iter = iter(base_children)
test_children_iter = iter(test_children)
base_child = next(base_children_iter, None)
test_child = next(test_children_iter, None)
while (base_child is not None) or (test_child is not None):
# first handle the case of a unique base child
if (base_child is not None) and (not element_is_in_sequence(base_child, test_children)):
# base_child is unique: deep copy with base only tag
merge_child = copy.deepcopy(base_child)
merge_child.attrib[DIFF_ATTRIB] = FROM_BASE_ONLY
merge_parent.append(merge_child)
# this unique child has already been fully copied to the merge tree so it doesn't go on the stack
# only move the base child since test child hasn't been handled yet
base_child = next(base_children_iter, None)
elif (test_child is not None) and (not element_is_in_sequence(test_child, base_children)):
# test_child is unique: deep copy with base only tag
merge_child = copy.deepcopy(test_child)
merge_child.attrib[DIFF_ATTRIB] = FROM_TEST_ONLY
merge_parent.append(merge_child)
# this unique child has already been fully copied to the merge tree so it doesn't go on the stack
# only move test child since base child hasn't been handled yet
test_child = next(test_children_iter, None)
elif element_content_equal(base_child, test_child):
# both trees share the same element: shallow copy either child with shared tag
merge_child = copy_element_without_children(base_child)
merge_parent.append(merge_child)
# put pair of children on stack as parents to be tested since their children may differ
parent_stack.append((base_child, test_child, merge_child))
# move on to next children in both trees since this was a shared element
base_child = next(base_children_iter, None)
test_child = next(test_children_iter, None)
else:
raise RuntimeError # there is something wrong - element should be unique or shared.
# display merge_tree with highlighting to indicate source of each line
# no highlight: common element in both trees
# green: line that exists only in test tree (i.e. additional)
# red: line that exists only in the base tree (i.e. missing)
root = tk.Tk()
textbox = tk.Text(root)
textbox.pack(expand=1, fill=tk.BOTH)
textbox.tag_config(FROM_BASE_ONLY, background='#ff5555')
textbox.tag_config(FROM_TEST_ONLY, background='#55ff55')
# find diff lines to highlight within merge_tree string that includes kludge attributes
merge_tree_string = etree.tostring(merge_root, pretty_print=True)
diffs_by_line = []
for line, line_text in enumerate(merge_tree_string.split('\n')):
for diff_type in (FROM_BASE_ONLY, FROM_TEST_ONLY):
if diff_type in line_text:
diffs_by_line.append((line+1, diff_type))
# remove kludge attributes
for element in merge_root.iter():
try:
del(element.attrib[DIFF_ATTRIB])
except KeyError:
pass
merge_tree_string = etree.tostring(merge_root, pretty_print=True)
# highlight final lines
textbox.insert(tk.END, merge_tree_string)
for line, diff_type in diffs_by_line:
textbox.tag_add(diff_type, '{}.0'.format(line), '{}.0'.format(int(line)+1))
root.mainloop()
输入:
请注意,我清理了 xml,因为我的行为与原始 XML 不一致。原来的基本上是使用反斜杠而不是正斜杠,并且在开始标签上也有错误的结束斜杠。
base.xml
(与此脚本位于同一位置)
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<p1:sample1 xmlns:p1="http://www.example.org/eHorizon">
<p1:time nTimestamp="5">
<p1:location hours = "1" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
</p1:location>
</p1:time>
<p1:time nTimestamp="6">
<p1:location hours = "1" path = '1'>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="9" type="b">590</p1:feature>
<p1:feature color="10" type="c">600</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
</p1:time>
</p1:sample1>
test.xml
(与此脚本位于同一位置)
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<p1:sample1 xmlns:p1="http://www.example.org/eHorizon">
<p1:time nTimestamp="5">
<p1:location hours = "1" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="9" type="b">1111</p1:feature>
<p1:feature color="10" type="c">2222</p1:feature>
</p1:location>
</p1:time>
<p1:time nTimestamp="6">
<p1:location hours = "1" path = '1'>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="9" type="b">590</p1:feature>
<p1:feature color="10" type="c">600</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
</p1:time>
</p1:sample1>
我尝试了各种逻辑和方法,甚至谷歌了很多,但仍然无法为我的问题想出满意的答案。我编写了如下所示的程序来突出显示我遇到问题的特定 xml 代码。抱歉让这个 post 有点长。我只是想清楚地解释我的问题。
编辑: 对于下面给定程序的 运行,您将需要两个 xml 文件,它们位于:sample1 and sample2。保存此文件并在下面的代码中编辑要在 C:/Users/editThisLocation/Desktop/sample1.xml
from lxml import etree
from collections import defaultdict
from collections import OrderedDict
from distutils.filelist import findall
from lxml._elementpath import findtext
from Tkinter import *
import Tkinter as tk
import ttk
root = Tk()
class CustomText(tk.Text):
def __init__(self, *args, **kwargs):
tk.Text.__init__(self, *args, **kwargs)
def highlight_pattern(self, pattern, tag, start, end,
regexp=True):
start = self.index(start)
end = self.index(end)
self.mark_set("matchStart", start)
self.mark_set("matchEnd", start)
self.mark_set("searchLimit", end)
count = tk.IntVar()
while True:
index = self.search(pattern, "matchEnd","searchLimit",
count=count, regexp=regexp)
if index == "": break
self.mark_set("matchStart", index)
self.mark_set("matchEnd", "%s+%sc" % (index, count.get()))
self.tag_add(tag, "matchStart", "matchEnd")
def Remove_pattern(self, pattern, tag, start="1.0", end="end",
regexp=True):
start = self.index(start)
end = self.index(end)
self.mark_set("matchStart", start)
self.mark_set("matchEnd", start)
self.mark_set("searchLimit", end)
count = tk.IntVar()
while True:
index = self.search(pattern, "matchEnd","searchLimit",
count=count, regexp=regexp)
if index == "": break
self.mark_set("matchStart", index)
self.mark_set("matchEnd", "%s+%sc" % (index, count.get()))
self.tag_remove(tag, start, end)
recovering_parser = etree.XMLParser(recover=True)
sample1File = open('C:/Users/editThisLocation/Desktop/sample1.xml', 'r')
contents_sample1 = sample1File.read()
sample2File = open('C:/Users/editThisLocation/Desktop/sample2.xml', 'r')
contents_sample2 = sample2File.read()
frame1 = Frame(width=768, height=25, bg="#000000", colormap="new")
frame1.pack()
Label(frame1, text="sample 1 below - scroll to see more").pack()
textbox = CustomText(root)
textbox.insert(END,contents_sample1)
textbox.pack(expand=1, fill=BOTH)
frame2 = Frame(width=768, height=25, bg="#000000", colormap="new")
frame2.pack()
Label(frame2, text="sample 2 below - scroll to see more").pack()
textbox1 = CustomText(root)
textbox1.insert(END,contents_sample2)
textbox1.pack(expand=1, fill=BOTH)
sample1 = etree.parse("C:/Users/editThisLocation/Desktop/sample1.xml", parser=recovering_parser).getroot()
sample2 = etree.parse("C:/Users/editThisLocation/Desktop/sample2.xml", parser=recovering_parser).getroot()
ToStringsample1 = etree.tostring(sample1)
sample1String = etree.fromstring(ToStringsample1, parser=recovering_parser)
ToStringsample2 = etree.tostring(sample2)
sample2String = etree.fromstring(ToStringsample2, parser=recovering_parser)
timesample1 = sample1String.findall('{http://www.example.org/eHorizon}time')
timesample2 = sample2String.findall('{http://www.example.org/eHorizon}time')
for i,j in zip(timesample1,timesample2):
for k,l in zip(i.findall("{http://www.example.org/eHorizon}feature"), j.findall("{http://www.example.org/eHorizon}feature")):
if [k.attrib.get('color'), k.attrib.get('type')] != [l.attrib.get('color'), l.attrib.get('type')]:
faultyLine = [k.attrib.get('color'), k.attrib.get('type'), k.text]
def high(event):
textbox.tag_configure("yellow", background="yellow")
limit_1 = '<p1:time nTimestamp="{0}">'.format(5) #limit my search between timestamp 5 and timestamp 6
limit_2 = '<p1:time nTimestamp="{0}">'.format((5+1)) # timestamp 6
highlightString = '<p1:feature color="{0}" type="{1}">{2}</p1:feature>'.format(faultyLine[0],faultyLine[1],faultyLine[2]) #string to be highlighted
textbox.highlight_pattern(limit_1, "yellow", start=textbox.search(limit_1, '1.0', stopindex=END), end=textbox.search(limit_2, '1.0', stopindex=END))
textbox.highlight_pattern(highlightString, "yellow", start=textbox.search(limit_1, '1.0', stopindex=END), end=textbox.search(limit_2, '1.0', stopindex=END))
button = 'press here to highlight error line'
c = ttk.Label(root, text=button)
c.bind("<Button-1>",high)
c.pack()
root.mainloop()
我想要的
如果你运行上面的代码,它会给出下面给出的输出:
正如您在图片中看到的,我只打算突出显示带有绿色勾号的代码。你们中的一些人可能会考虑限制开始和结束索引以突出显示该模式。但是,如果您在我的程序中看到我已经在使用开始和结束索引将我的输出限制为仅 nTimestamp="5"
,为此我正在使用 limit_1
和 limit_2
变量。
那么在这种类型的数据中如何正确地突出显示许多内部个体中的一个模式nTimestamp
?
编辑:这里我特别想突出显示 nTimestamp="5"
中的第 3 项,因为该项目不存在于 sample2.xml
中,正如您在两个 xml 文件和当程序 运行s 它也区分这一点。唯一的问题是突出显示正确的项目,在我的案例中是第 3 项。
我正在使用来自 Bryan Oakley 的代码 here
的突出显示 class编辑最近
根据 kobejohn 在评论中提出的问题,目标文件永远不会为空。目标文件总是有可能有额外或缺失的元素。最后,我目前的意图是仅突出显示不同或缺失的深层元素以及它们所在的 timestamps
。然而, timestamps
的突出显示是正确完成的,但是像上面解释的那样突出显示深层元素的问题仍然是一个问题。感谢 kobejohn 澄清这一点。
注意:
我知道并且你可能会建议正确工作的一种方法是提取绿色勾选图案的索引并简单地 运行 在其上突出显示标记,但这种方法是非常硬编码的并且在大您必须处理大量变化的数据是完全无效的。我正在寻找另一个更好的选择。
此解决方案的工作原理是根据您提供的描述在 base.xml
和 test.xml
之间执行简化的差异。 diff 结果是第 3 棵 XML 树,它结合了原始树。输出是对文件之间不匹配的行进行颜色编码突出显示的差异。
我希望你能使用这个或者根据你的需要改编它。
复制粘贴脚本
import copy
from lxml import etree
import Tkinter as tk
# assumption: the root element of both trees is the same
# note: missing subtrees will only have the parent element highlighted
def element_content_equal(e1, e2):
# starting point here:
try:
if e1.tag != e1.tag:
return False
elif e1.text != e2.text:
return False
elif e1.tail != e2.tail:
return False
elif e1.attrib != e2.attrib:
return False
except AttributeError:
# e.g. None is passed in for an element
return False
return True
def element_is_in_sequence(element, sequence):
for e in sequence:
if element_content_equal(e, element):
return True
return False
def copy_element_without_children(element):
e_copy = etree.Element(element.tag, attrib=element.attrib, nsmap=element.nsmap)
e_copy.text = element.text
e_copy.tail = element.tail
return e_copy
# start at the root of both xml trees
parser = etree.XMLParser(recover=True, remove_blank_text=True)
base_root = etree.parse('base.xml', parser=parser).getroot()
test_root = etree.parse('test.xml', parser=parser).getroot()
# each element from the original xml trees will be placed into a merge tree
merge_root = copy_element_without_children(base_root)
# additionally each merge tree element will be tagged with its source
DIFF_ATTRIB = 'diff'
FROM_BASE_ONLY = 'base'
FROM_TEST_ONLY = 'test'
# process the pair of trees, one set of parents at a time
parent_stack = [(base_root, test_root, merge_root)]
while parent_stack:
base_parent, test_parent, merge_parent = parent_stack.pop()
base_children = base_parent.getchildren()
test_children = test_parent.getchildren()
# compare children and transfer to merge tree
base_children_iter = iter(base_children)
test_children_iter = iter(test_children)
base_child = next(base_children_iter, None)
test_child = next(test_children_iter, None)
while (base_child is not None) or (test_child is not None):
# first handle the case of a unique base child
if (base_child is not None) and (not element_is_in_sequence(base_child, test_children)):
# base_child is unique: deep copy with base only tag
merge_child = copy.deepcopy(base_child)
merge_child.attrib[DIFF_ATTRIB] = FROM_BASE_ONLY
merge_parent.append(merge_child)
# this unique child has already been fully copied to the merge tree so it doesn't go on the stack
# only move the base child since test child hasn't been handled yet
base_child = next(base_children_iter, None)
elif (test_child is not None) and (not element_is_in_sequence(test_child, base_children)):
# test_child is unique: deep copy with base only tag
merge_child = copy.deepcopy(test_child)
merge_child.attrib[DIFF_ATTRIB] = FROM_TEST_ONLY
merge_parent.append(merge_child)
# this unique child has already been fully copied to the merge tree so it doesn't go on the stack
# only move test child since base child hasn't been handled yet
test_child = next(test_children_iter, None)
elif element_content_equal(base_child, test_child):
# both trees share the same element: shallow copy either child with shared tag
merge_child = copy_element_without_children(base_child)
merge_parent.append(merge_child)
# put pair of children on stack as parents to be tested since their children may differ
parent_stack.append((base_child, test_child, merge_child))
# move on to next children in both trees since this was a shared element
base_child = next(base_children_iter, None)
test_child = next(test_children_iter, None)
else:
raise RuntimeError # there is something wrong - element should be unique or shared.
# display merge_tree with highlighting to indicate source of each line
# no highlight: common element in both trees
# green: line that exists only in test tree (i.e. additional)
# red: line that exists only in the base tree (i.e. missing)
root = tk.Tk()
textbox = tk.Text(root)
textbox.pack(expand=1, fill=tk.BOTH)
textbox.tag_config(FROM_BASE_ONLY, background='#ff5555')
textbox.tag_config(FROM_TEST_ONLY, background='#55ff55')
# find diff lines to highlight within merge_tree string that includes kludge attributes
merge_tree_string = etree.tostring(merge_root, pretty_print=True)
diffs_by_line = []
for line, line_text in enumerate(merge_tree_string.split('\n')):
for diff_type in (FROM_BASE_ONLY, FROM_TEST_ONLY):
if diff_type in line_text:
diffs_by_line.append((line+1, diff_type))
# remove kludge attributes
for element in merge_root.iter():
try:
del(element.attrib[DIFF_ATTRIB])
except KeyError:
pass
merge_tree_string = etree.tostring(merge_root, pretty_print=True)
# highlight final lines
textbox.insert(tk.END, merge_tree_string)
for line, diff_type in diffs_by_line:
textbox.tag_add(diff_type, '{}.0'.format(line), '{}.0'.format(int(line)+1))
root.mainloop()
输入:
请注意,我清理了 xml,因为我的行为与原始 XML 不一致。原来的基本上是使用反斜杠而不是正斜杠,并且在开始标签上也有错误的结束斜杠。
base.xml
(与此脚本位于同一位置)
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<p1:sample1 xmlns:p1="http://www.example.org/eHorizon">
<p1:time nTimestamp="5">
<p1:location hours = "1" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
</p1:location>
</p1:time>
<p1:time nTimestamp="6">
<p1:location hours = "1" path = '1'>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="9" type="b">590</p1:feature>
<p1:feature color="10" type="c">600</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
</p1:time>
</p1:sample1>
test.xml
(与此脚本位于同一位置)
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<p1:sample1 xmlns:p1="http://www.example.org/eHorizon">
<p1:time nTimestamp="5">
<p1:location hours = "1" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="9" type="b">1111</p1:feature>
<p1:feature color="10" type="c">2222</p1:feature>
</p1:location>
</p1:time>
<p1:time nTimestamp="6">
<p1:location hours = "1" path = '1'>
<p1:feature color="2" type="a">564</p1:feature>
<p1:feature color="3" type="b">570</p1:feature>
<p1:feature color="4" type="c">570</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="9" type="b">590</p1:feature>
<p1:feature color="10" type="c">600</p1:feature>
</p1:location>
<p1:location hours = "5" path = '1'>
<p1:feature color="6" type="a">560</p1:feature>
<p1:feature color="7" type="b">570</p1:feature>
<p1:feature color="8" type="c">580</p1:feature>
</p1:location>
</p1:time>
</p1:sample1>