Hibernate 从多对一关系中获取剩余对象

Question

我有一个存储俱乐部和球队的数据库。一个俱乐部有多个团队，一个团队只是一个俱乐部的一部分。是否可以使用查询不属于特定俱乐部的所有球队休眠条件 api？这是（剥离的）Club.java 和 Team.java

Club.java

@Entity
@Table(name = "clubs")
public class Club {
    @Id
    @GeneratedValue
    @Column(name = "club_id")
    private int id;
    @Column(name = "name")
    private String name;
    @OneToMany(mappedBy = "club")
    private java.util.Set<Team> teams;

    [setters, constructors etc]
}

Team.java

@Entity
@Table(name = "team")
public class Team {
    @Id
    @GeneratedValue
    @Column(name = "team_id")
    private int id;
    @Column(name = "name")
    private String name;
    @ManyToOne
    @JoinColumn(name = "club_id")
    private Club club;

    [same here]   
}

Answer 1

应该是这样的：

Criteria criteria=session.createCriteria(Team.class);
        .createAlias("club", "c")
        .add( Restrictions.not(Restrictions.like("c.name", "nameOfTheClubIAmLookingFor", MatchMode.EXACT)) )
        List<Team> teams=criteria.list();

Answer 2

作为上述答案的细微变化，如果您已经有了 Club 对象，您希望找到不属于它的所有球队，您应该能够执行类似以下操作：

Criteria criteria = session.createCriteria(Team.class);
criteria.add(Restrictions.ne("club", myClub));
List<Team> teams = criteria.list();

这避免了查询俱乐部名称，恕我直言，代码更简洁。

Hibernate 从多对一关系中获取剩余对象

Hibernate get remaining objects from many to one relation

java

hibernate

criteria