仅替换已解析的正则表达式
Replace only parsed regular expression
这道题类似于堆栈题。
objective是解析一个正则表达式,只替换匹配的模式。示例:
data <- c("cat 6kg","cat g250", "dog","cat 10 kg", "no cat")
解析感兴趣的匹配项 cat
:
data[grepl("cat",data)]
[1] "cat 6kg" "cat g250" "cat 10 kg" "no cat"
理想的结果是用chicken
替换所有出现的cat
:
[1] "chicken 6kg" "chicken g250" "chicken 10 kg" "no chicken"
知道如何实现吗?谢谢大家。
使用 gsub:
gsub("cat", "chicken", data)
[1] "chicken 6kg" "chicken g250" "dog" "chicken 10 kg" "no chicken"
或者如果你只想要包含猫的:
gsub("cat", "chicken", data[grepl("cat",data)])
[1] "chicken 6kg" "chicken g250" "chicken 10 kg" "no chicken"
这道题类似于堆栈题
objective是解析一个正则表达式,只替换匹配的模式。示例:
data <- c("cat 6kg","cat g250", "dog","cat 10 kg", "no cat")
解析感兴趣的匹配项 cat
:
data[grepl("cat",data)]
[1] "cat 6kg" "cat g250" "cat 10 kg" "no cat"
理想的结果是用chicken
替换所有出现的cat
:
[1] "chicken 6kg" "chicken g250" "chicken 10 kg" "no chicken"
知道如何实现吗?谢谢大家。
使用 gsub:
gsub("cat", "chicken", data)
[1] "chicken 6kg" "chicken g250" "dog" "chicken 10 kg" "no chicken"
或者如果你只想要包含猫的:
gsub("cat", "chicken", data[grepl("cat",data)])
[1] "chicken 6kg" "chicken g250" "chicken 10 kg" "no chicken"