如何访问辅助文件中的 codeigniter 对象和变量?
How to access codeigniter objects and variables in helper file?
我正在 codeigniter 3.0 中创建一个 Web 应用程序。我在从 codeigniter 实例访问数据库对象并像在模型中一样使用它时遇到问题。
我的代码是:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
$CI =& get_instance();
$CI->load->database();
function get_menu($slug)
{
$CI->db->select('menuid');
$CI->db->where(array('slug'=>$slug));
$query=$CI->db->get('menus')->row();
echo $menuid= $query->menuid;
$query="SELECT * FROM menu_items WHERE menuid=".$menuid;
write_menu($query);
}
这显示了这样的错误
A PHP Error was encountered
Severity: Notice
Message: Undefined variable: CI
Filename: helpers/menu_helper.php
Line Number: 9
Backtrace:
File: C:\Users\Pradeep\Google Drive\control\helpers\menu_helper.php
Line: 9
Function: _error_handler
File: C:\Users\Pradeep\Google Drive\control\controllers\Welcome.php
Line: 19
Function: get_menu
File: C:\Users\Pradeep\Google Drive\index.php
Line: 292
Function: require_once
有什么合适的方法吗?
请提出建议。
您需要在函数中声明 $CI
。在您的代码中,您在函数
之外声明了 $CI =& get_instance();
function get_menu($slug)
{
$CI =& get_instance();
$CI->load->database();
$CI->db->select('menuid');
$CI->db->where(array('slug' => $slug));
$query = $CI->db->get('menus')->row();
echo $menuid = $query->menuid;
$query = "SELECT * FROM menu_items WHERE menuid=" . $menuid;
write_menu($query);
}
我正在 codeigniter 3.0 中创建一个 Web 应用程序。我在从 codeigniter 实例访问数据库对象并像在模型中一样使用它时遇到问题。 我的代码是:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
$CI =& get_instance();
$CI->load->database();
function get_menu($slug)
{
$CI->db->select('menuid');
$CI->db->where(array('slug'=>$slug));
$query=$CI->db->get('menus')->row();
echo $menuid= $query->menuid;
$query="SELECT * FROM menu_items WHERE menuid=".$menuid;
write_menu($query);
}
这显示了这样的错误
A PHP Error was encountered
Severity: Notice
Message: Undefined variable: CI
Filename: helpers/menu_helper.php
Line Number: 9
Backtrace:
File: C:\Users\Pradeep\Google Drive\control\helpers\menu_helper.php
Line: 9
Function: _error_handler
File: C:\Users\Pradeep\Google Drive\control\controllers\Welcome.php
Line: 19
Function: get_menu
File: C:\Users\Pradeep\Google Drive\index.php
Line: 292
Function: require_once
有什么合适的方法吗? 请提出建议。
您需要在函数中声明 $CI
。在您的代码中,您在函数
$CI =& get_instance();
function get_menu($slug)
{
$CI =& get_instance();
$CI->load->database();
$CI->db->select('menuid');
$CI->db->where(array('slug' => $slug));
$query = $CI->db->get('menus')->row();
echo $menuid = $query->menuid;
$query = "SELECT * FROM menu_items WHERE menuid=" . $menuid;
write_menu($query);
}