php 计算变量数组中的单词数

Question

我有一个可变字符串数组，我想计算所有逗号的数量并找出所有字符串中的逗号总数。我知道我必须使用 explode 和 foreach 但不知道如何将它们放在一起以及如何在末尾添加所有逗号...

 $log1 = "one, two, three,";

 $log2 = "red, blye, green,";

 $log3 = "sunny day, snowy day, nice one,";

 $main_log = array(log1, log2, log3);

Answer 1

substr_count($string, ',');

对于数组....@vp_arth 的解决方案可行...

$log1 = "one, two, three,";

$log2 = "red, blye, green,";

$log3 = "sunny day, snowy day, nice one,";

$main_log = array($log1, $log2, $log3);

$result= array_sum(array_map(function($str){
  return substr_count($str, ',');
}, $main_log));


echo $result;

Answer 2

像这样修改你的代码 -

$log1 = "one, two, three";
$log2 = "red, blye, green";
$log3 = "sunny day, snowy day, nice one";

$arr1 = explode(',', $log1);
$arr2 = explode(',', $log2);
$arr3 = explode(',', $log3);


$main_log = array_merge($arr1,$arr2,$arr3);   //Array merge
$count = array_count_values($main_log); //Total count the array values

Answer 3

您想数逗号 - 就这样做吧：

array_sum(array_map(function($str){
  return substr_count($str, ',');
}, $main_log));

Answer 4

请更正。连接所有字符串，而不是按照在以下代码中完成的方式将它们推入数组；

$log1 = "one, two, three,";

 $log2 = "red, blye, green,";

 $log3 = "sunny day, snowy day, nice one,";

 $main_log = $log1.$log2.$log3;
 echo substr_count($main_log, ','); //prints 9

Answer 5

这里还有另外两个解决方案：

$log1 = "one, two, three,";
$log2 = "red, blye, green,";
$log3 = "sunny day, snowy day, nice one,";

$main_log = $log1.$log2.$log3;

echo count(explode(',',$main_log))-1;

echo substr_count($main_log, ',');

php 计算变量数组中的单词数

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