parse.com 微调器

Question

我想从 parse.com 获取列表并将其设置为我创建的微调器
我已经使用过此代码，但它 returns 微调器中的项目以这种格式

com.parse.ParseObject@132610f4

final Spinner country = (Spinner) findViewById(R.id.schoolSelect);
    ParseQuery<ParseObject> query = new ParseQuery<ParseObject>("school");
    query.findInBackground(new FindCallback<ParseObject>() {
        @Override
        public void done(List<ParseObject> list, ParseException e) {
            if (e == null) {
                ArrayAdapter adapter = new ArrayAdapter(
                        getApplicationContext(),android.R.layout.simple_list_item_1 ,list);
                country.setAdapter(adapter);
            } else {

            }
        }
    });

有谁知道如何只在查询中获取某列，让里面的数据显示出来我想要获取其内容的列称为

SchoolName

Answer 1

只需创建另一个列表来存储您的 ParseObject

的名称

final Spinner country = (Spinner) findViewById(R.id.schoolSelect);
ParseQuery<ParseObject> query = new ParseQuery<ParseObject>("school");
query.findInBackground(new FindCallback<ParseObject>() {
    @Override
    public void done(List<ParseObject> list, ParseException e) {
        if (e == null) {
            ArrayList<String> nameList = new ArrayList<>();
            for(ParseObject object : list) {
                 nameList.add(object.getString("SchoolName"));
            }
            ArrayAdapter adapter = new ArrayAdapter(
                    getApplicationContext(),android.R.layout.simple_list_item_1 ,nameList);
            country.setAdapter(adapter);
        } else {

        }
    }
});

parse.com 微调器

Spinner with parse.com

android

android-arrayadapter

android-spinner

parse-platform