在共享内存中锁定互斥锁
Lock mutex in shared memory
我正在尝试在 mutil 多进程程序中使用 pthread_mutex_t,我需要在共享内存中锁定一个互斥体以进行同步。这是我复制的代码 from.
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <sys/mman.h>
#include <pthread.h>
pthread_mutex_t* g_mutex;
void init_mutex(void)
{
int ret;
g_mutex=(pthread_mutex_t*)mmap(NULL, sizeof(pthread_mutex_t), PROT_READ|PROT_WRITE, MAP_SHARED|MAP_ANONYMOUS, -1, 0);
if( MAP_FAILED==g_mutex )
{
perror("mmap");
exit(1);
}
pthread_mutexattr_t attr;
pthread_mutexattr_init(&attr);
//set mutex process shared
ret=pthread_mutexattr_setpshared(&attr,PTHREAD_PROCESS_SHARED);
if( ret!=0 )
{
perror("init_mutex pthread_mutexattr_setpshared");
exit(1);
}
pthread_mutex_init(g_mutex, &attr);
}
int main(int argc, char *argv[])
{
init_mutex();
int ret;
char str1[]="this is child process/r/n";
char str2[]="this is father process/r/n";
int fd=open("tmp", O_RDWR|O_CREAT|O_TRUNC, 0666);
if( -1==fd )
{
perror("open");
exit(1);
}
pid_t pid;
pid=fork();
if( pid<0 )
{
perror("fork");
exit(1);
}
else if( 0==pid )
{
ret=pthread_mutex_lock(g_mutex);
if( ret!=0 )
{
perror("child pthread_mutex_lock");
}
sleep(10);
write(fd, str1, sizeof(str1));
ret=pthread_mutex_unlock(g_mutex);
if( ret!=0 )
{
perror("child pthread_mutex_unlock");
}
}
else
{
sleep(2);
ret=pthread_mutex_lock(g_mutex);
if( ret!=0 )
{
perror("father pthread_mutex_lock");
}
write(fd, str2, sizeof(str2));
ret=pthread_mutex_unlock(g_mutex);
if( ret!=0 )
{
perror("father pthread_mutex_unlock");
}
}
wait(NULL);
munmap(g_mutex, sizeof(pthread_mutex_t));
}
问题是我必须在调用 pthread_mutex_lock
之后调用 msync
吗?
不,您不需要调用 msync()
。该函数将映射内存刷新到磁盘,但您可能并不关心这一点:您关心同一台机器上的其他程序将看到相同的互斥锁状态。只要其中 none 个崩溃,它们就会崩溃。我想如果您的程序无论如何都会崩溃,您会重置互斥量。
将映射内存刷新到磁盘与 运行 程序是否会看到对该内存的更改无关——就像它与写入更改的同一程序是否能够看到一样阅读它们。
我正在尝试在 mutil 多进程程序中使用 pthread_mutex_t,我需要在共享内存中锁定一个互斥体以进行同步。这是我复制的代码 from.
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <sys/mman.h>
#include <pthread.h>
pthread_mutex_t* g_mutex;
void init_mutex(void)
{
int ret;
g_mutex=(pthread_mutex_t*)mmap(NULL, sizeof(pthread_mutex_t), PROT_READ|PROT_WRITE, MAP_SHARED|MAP_ANONYMOUS, -1, 0);
if( MAP_FAILED==g_mutex )
{
perror("mmap");
exit(1);
}
pthread_mutexattr_t attr;
pthread_mutexattr_init(&attr);
//set mutex process shared
ret=pthread_mutexattr_setpshared(&attr,PTHREAD_PROCESS_SHARED);
if( ret!=0 )
{
perror("init_mutex pthread_mutexattr_setpshared");
exit(1);
}
pthread_mutex_init(g_mutex, &attr);
}
int main(int argc, char *argv[])
{
init_mutex();
int ret;
char str1[]="this is child process/r/n";
char str2[]="this is father process/r/n";
int fd=open("tmp", O_RDWR|O_CREAT|O_TRUNC, 0666);
if( -1==fd )
{
perror("open");
exit(1);
}
pid_t pid;
pid=fork();
if( pid<0 )
{
perror("fork");
exit(1);
}
else if( 0==pid )
{
ret=pthread_mutex_lock(g_mutex);
if( ret!=0 )
{
perror("child pthread_mutex_lock");
}
sleep(10);
write(fd, str1, sizeof(str1));
ret=pthread_mutex_unlock(g_mutex);
if( ret!=0 )
{
perror("child pthread_mutex_unlock");
}
}
else
{
sleep(2);
ret=pthread_mutex_lock(g_mutex);
if( ret!=0 )
{
perror("father pthread_mutex_lock");
}
write(fd, str2, sizeof(str2));
ret=pthread_mutex_unlock(g_mutex);
if( ret!=0 )
{
perror("father pthread_mutex_unlock");
}
}
wait(NULL);
munmap(g_mutex, sizeof(pthread_mutex_t));
}
问题是我必须在调用 pthread_mutex_lock
之后调用 msync
吗?
不,您不需要调用 msync()
。该函数将映射内存刷新到磁盘,但您可能并不关心这一点:您关心同一台机器上的其他程序将看到相同的互斥锁状态。只要其中 none 个崩溃,它们就会崩溃。我想如果您的程序无论如何都会崩溃,您会重置互斥量。
将映射内存刷新到磁盘与 运行 程序是否会看到对该内存的更改无关——就像它与写入更改的同一程序是否能够看到一样阅读它们。