Swagger UI 和 Play routing *path

Question

我在 Swagger 理解 Play 时遇到了问题！ 2.0 路由通配符路由，所以 swagger ui 以损坏的 URL 结束。我的路线文件有这条路线：

GET           /settings/api/:project/*path                       @controllers.API.getParams(project, path)

然后我的控制器有如下代码：

@ApiOperation(value = "Returns settings for given project and path.", response = String.class, httpMethod = "GET")
@ApiResponses(value = {
        @ApiResponse(code = 200, message = "Request completed successfully."),
        @ApiResponse(code = 500, message = "Internal error while processing request")
})
@ApiImplicitParams({
        @ApiImplicitParam(name = "project", value = "Project name", required = true, dataType = "String", paramType = "path"),
        @ApiImplicitParam(name = "path", value = "path", required = true, dataType = "String", paramType = "path")
})
public Result getParams(String project, String path) {
    return ok(path);
}

然后当 Swagger UI 被渲染时，我看到这个动作的路径被渲染为

POST /settings/api/{project}/{path<.+>

当我打电话时，它变成了

/settings/api/test/{path<.+>

所以基本上 :project 被替换了，但 *path 仍然存在 broken/intact。如果您知道如何解决此问题，请分享。谢谢！

Answer 1

事实证明 swagger 不支持通配符路由。

Swagger UI 和 Play routing *path

Swagger UI and Play routing *path

java

routing

playframework-2.0

swagger

swagger-ui