Python - 如何创建一个接受参数的新修饰函数?
Python - how do I create a new decorated function that takes arguments?
我读完了这篇很棒的文章 post:How to make a chain of function decorators?
我决定 fiddle 使用它并且我正在使用它的这个块:
# It’s not black magic, you just have to let the wrapper
# pass the argument:
def a_decorator_passing_arguments(function_to_decorate):
def a_wrapper_accepting_arguments(arg1, arg2):
print "I got args! Look:", arg1, arg2
function_to_decorate(arg1, arg2)
return a_wrapper_accepting_arguments
# Since when you are calling the function returned by the decorator, you are
# calling the wrapper, passing arguments to the wrapper will let it pass them to
# the decorated function
@a_decorator_passing_arguments
def print_full_name(first_name, last_name):
print "My name is", first_name, last_name
print_full_name("Peter", "Venkman")
# outputs:
#I got args! Look: Peter Venkman
#My name is Peter Venkman
如果我不想将修饰后的 print_full_name(first_name, last_name)
重命名为它自己,而是想将修饰后的版本另存为不同的函数名称,例如 decorated_print_full_name(first_name, last_name)
,会怎样?基本上,我更好奇如何更改代码,所以我 DON'T 使用 @a_decorator_passing_arguments
快捷方式。
我重写了上面的内容(针对Python 3):
def a_decorator_passing_arguments(function_to_decorate):
def a_wrapper_accepting_arguments(arg1, arg2):
print("I got args! Look:", arg1, arg2)
function_to_decorate(arg1, arg2)
return a_wrapper_accepting_arguments
#@a_decorator_passing_arguments
def print_full_name(first_name, last_name):
print("My name is", first_name, last_name)
decorated_print_full_name = a_decorator_passing_arguments(print_full_name(first_name, last_name))
decorated_print_full_name("Peter", "Venkman")
但是 Python 抱怨 first_name
没有在第 11 行定义。我对 Python 还是个新手所以如果我在这里遗漏了一些非常明显的东西请原谅我。
它应该适用于:
decorated_print_full_name = a_decorator_passing_arguments(print_full_name)
我读完了这篇很棒的文章 post:How to make a chain of function decorators?
我决定 fiddle 使用它并且我正在使用它的这个块:
# It’s not black magic, you just have to let the wrapper
# pass the argument:
def a_decorator_passing_arguments(function_to_decorate):
def a_wrapper_accepting_arguments(arg1, arg2):
print "I got args! Look:", arg1, arg2
function_to_decorate(arg1, arg2)
return a_wrapper_accepting_arguments
# Since when you are calling the function returned by the decorator, you are
# calling the wrapper, passing arguments to the wrapper will let it pass them to
# the decorated function
@a_decorator_passing_arguments
def print_full_name(first_name, last_name):
print "My name is", first_name, last_name
print_full_name("Peter", "Venkman")
# outputs:
#I got args! Look: Peter Venkman
#My name is Peter Venkman
如果我不想将修饰后的 print_full_name(first_name, last_name)
重命名为它自己,而是想将修饰后的版本另存为不同的函数名称,例如 decorated_print_full_name(first_name, last_name)
,会怎样?基本上,我更好奇如何更改代码,所以我 DON'T 使用 @a_decorator_passing_arguments
快捷方式。
我重写了上面的内容(针对Python 3):
def a_decorator_passing_arguments(function_to_decorate):
def a_wrapper_accepting_arguments(arg1, arg2):
print("I got args! Look:", arg1, arg2)
function_to_decorate(arg1, arg2)
return a_wrapper_accepting_arguments
#@a_decorator_passing_arguments
def print_full_name(first_name, last_name):
print("My name is", first_name, last_name)
decorated_print_full_name = a_decorator_passing_arguments(print_full_name(first_name, last_name))
decorated_print_full_name("Peter", "Venkman")
但是 Python 抱怨 first_name
没有在第 11 行定义。我对 Python 还是个新手所以如果我在这里遗漏了一些非常明显的东西请原谅我。
它应该适用于:
decorated_print_full_name = a_decorator_passing_arguments(print_full_name)