PIL 图片模式 I 是灰度？

Question

我正在尝试以整数格式而不是 (R,G,B) 格式指定图像的颜色。我假设我必须以“I”模式创建图像，因为根据 documentation:

The mode of an image defines the type and depth of a pixel in the image. The current release supports the following standard modes:

1 (1-bit pixels, black and white, stored with one pixel per byte)

L (8-bit pixels, black and white)

P (8-bit pixels, mapped to any other mode using a colour palette)

RGB (3x8-bit pixels, true colour)

RGBA (4x8-bit pixels, true colour with transparency mask)

CMYK (4x8-bit pixels, colour separation)

YCbCr (3x8-bit pixels, colour video format)

I (32-bit signed integer pixels)

F (32-bit floating point pixels)

然而，这似乎是一张灰度图像。这是预期的吗？有没有办法根据 32 位整数指定彩色图像？在我的 MWE 中，我什至让 PIL 决定如何将“红色”转换为“I”格式。

MWE

from PIL import Image

ImgRGB=Image.new('RGB', (200,200),"red") # create a new blank image
ImgI=Image.new('I', (200,200),"red") # create a new blank image
ImgRGB.show()
ImgI.show()

Answer 1

Is there a way of specifying a coloured image based on a 32-bit integer?

是的，为此使用 RGB 格式，但使用整数而不是 "red" 作为颜色参数：

from PIL import Image

r, g, b = 255, 240, 227
intcolor = (b << 16 ) | (g << 8 ) | r                                       
print intcolor # 14938367
ImgRGB = Image.new("RGB", (200, 200), intcolor)
ImgRGB.show()

PIL 图片模式 I 是灰度？

PIL Image mode I is grayscale?

python

python-imaging-library

MWE