使用 python 将 txt 转换为 xlsx 时出错

Error in converting txt to xlsx using python

我的代码如下。

import csv
import openpyxl

import sys


def convert(input_path, output_path):
    """
    Read a csv file (with no quoting), and save its contents in an excel file.
    """
    wb = openpyxl.Workbook()
    ws = wb.worksheets[0]

    with open(input_path) as f:
        reader = csv.reader(f, delimiter='\t', quoting=csv.QUOTE_NONE)
        for row_index, row in enumerate(reader):
            for col_index, value in enumerate(row):
                ws.cell(row=row_index, column=col_index).value = value

    wb.save(output_path)


def main():
    try:
        input_path, output_path = sys.argv[1:]
    except ValueError:
        print 'Usage: python %s input_path output_path' % (sys.argv[0],)
    else:
        convert(input_path, output_path)


if __name__ == '__main__':
    main()

但是我遇到了这个错误。

Traceback (most recent call last): 
  File "txt2xlsx.py", line 33, in <module> 
    main() 
  File "txt2xlsx.py", line 29, in main 
    convert(input_path, output_path) 
  File "txt2xlsx.py", line 18, in convert 
    ws.cell(row=row_index, column=col_index).value = value 
  File "C:\python27\lib\site-packages\openpyxl\worksheet\worksheet.py", line 350, in cell 
    column = get_column_letter(column) 
  File "C:\python27\lib\site-packages\openpyxl\utils\__init__.py", line 100, in get_column_letter 
    raise ValueError("Invalid column index {0}".format(idx)) 
ValueError: Invalid column index 0 

我想我已经正确安装了openpyxl。

而且我记得我以前使用这个程序没有任何问题。我最近买了一台新电脑,所以这可能是电脑配置问题。但我想不通。

根据 changelog for Openpyxl 2.0.0 -

,您似乎正在使用 openpyxl 2.0.0 +

Cells are referenced with 1-indexing: A1 == cell(row=1, column=1)

行和列索引从 1 开始。因此您也应该使 enumerate() 函数从 1 开始。例子-

    for row_index, row in enumerate(reader, 1):
        for col_index, value in enumerate(row, 1):
            ws.cell(row=row_index, column=col_index).value = value

您的特定代码可以在低于 2.0.0 的 openpyxl 版本中运行,但由于上述 2.0.0 版本中的更改而失败。