Return 列值中的多行
Return Multiple Rows from Column Value
我需要从我的存储过程创建一个 XML。我的数据库有多个值存储在一行中,如下所示:
ScheduleID EmployeeID M Tu W Th F Sa Su
======================================================
10 10001 1 1 0 0 0 0 0
11 10001 0 0 0 1 0 0 0
12 10002 0 0 0 0 0 1 1
我需要创建一个如下所示的 XML:
<schedules>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Monday</Workday>
</task>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Tuesday</Workday>
</task>
<task>
<ScheduleID>11</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Thursday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Saturday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Sunday</Workday>
</task>
</schedules>
我遇到的问题是,为了执行上述操作,我需要 return return 一周中的每一天都有不同的行。所以我在考虑使用 case 语句,但是,我最接近的是以下行不通的,因为它创建了多个名为 "Workday" 的列。由于每个 ScheduleID 可能有 1-7 天有效,因此添加 ELSE 也不是一个选项。我该怎么做呢?
SELECT ScheduleID, EmployeeID,
CASE WHEN (M = 1) THEN 'Monday' END as Workday,
CASE WHEN (Tu = 1) THEN 'Tuesday' END as Workday,
CASE WHEN (W = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (Th = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (F = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (Sa = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (Su = 1) THEN 1 ELSE 0 END as Workday
FROM Schedules
FOR XML PATH('task'), ROOT('schedules')
测试数据
DECLARE @T TABLE (ScheduleID INT, EmployeeID INT , M INT,
Tu INT, W INT, Th INT, F INT, Sa INT, Su INT)
INSERT INTO @T VALUES
(10 ,10001 ,1 , 1 , 0 , 0 , 0 , 0 , 0),
(11 ,10001 ,0 , 0 , 0 , 1 , 0 , 0 , 0),
(12 ,10002 ,0 , 0 , 0 , 0 , 0 , 1 , 1)
查询
;WITH X AS
(
SELECT *
FROM (
SELECT ScheduleID
,EmployeeID
,NULLIF(M , 0) AS Monday
,NULLIF(Tu, 0) AS Tuesday
,NULLIF(W , 0) AS Wednesday
,NULLIF(Th, 0) AS Thursday
,NULLIF(F , 0) AS Friday
,NULLIF(Sa, 0) AS Saturday
,NULLIF(Su, 0) AS Sunday
FROM @T
)t
UNPIVOT (Vals FOR Workday IN (Monday,Tuesday,Wednesday,Thursday
,Friday,Saturday,Sunday))up
)
SELECT ScheduleID
,EmployeeID
,Workday
FROM X
FOR XML PATH('task'), ROOT('schedules')
结果:
<schedules>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Monday</Workday>
</task>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Tuesday</Workday>
</task>
<task>
<ScheduleID>11</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Thursday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Saturday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Sunday</Workday>
</task>
</schedules>
我需要从我的存储过程创建一个 XML。我的数据库有多个值存储在一行中,如下所示:
ScheduleID EmployeeID M Tu W Th F Sa Su
======================================================
10 10001 1 1 0 0 0 0 0
11 10001 0 0 0 1 0 0 0
12 10002 0 0 0 0 0 1 1
我需要创建一个如下所示的 XML:
<schedules>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Monday</Workday>
</task>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Tuesday</Workday>
</task>
<task>
<ScheduleID>11</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Thursday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Saturday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Sunday</Workday>
</task>
</schedules>
我遇到的问题是,为了执行上述操作,我需要 return return 一周中的每一天都有不同的行。所以我在考虑使用 case 语句,但是,我最接近的是以下行不通的,因为它创建了多个名为 "Workday" 的列。由于每个 ScheduleID 可能有 1-7 天有效,因此添加 ELSE 也不是一个选项。我该怎么做呢?
SELECT ScheduleID, EmployeeID,
CASE WHEN (M = 1) THEN 'Monday' END as Workday,
CASE WHEN (Tu = 1) THEN 'Tuesday' END as Workday,
CASE WHEN (W = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (Th = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (F = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (Sa = 1) THEN 1 ELSE 0 END as Workday,
CASE WHEN (Su = 1) THEN 1 ELSE 0 END as Workday
FROM Schedules
FOR XML PATH('task'), ROOT('schedules')
测试数据
DECLARE @T TABLE (ScheduleID INT, EmployeeID INT , M INT,
Tu INT, W INT, Th INT, F INT, Sa INT, Su INT)
INSERT INTO @T VALUES
(10 ,10001 ,1 , 1 , 0 , 0 , 0 , 0 , 0),
(11 ,10001 ,0 , 0 , 0 , 1 , 0 , 0 , 0),
(12 ,10002 ,0 , 0 , 0 , 0 , 0 , 1 , 1)
查询
;WITH X AS
(
SELECT *
FROM (
SELECT ScheduleID
,EmployeeID
,NULLIF(M , 0) AS Monday
,NULLIF(Tu, 0) AS Tuesday
,NULLIF(W , 0) AS Wednesday
,NULLIF(Th, 0) AS Thursday
,NULLIF(F , 0) AS Friday
,NULLIF(Sa, 0) AS Saturday
,NULLIF(Su, 0) AS Sunday
FROM @T
)t
UNPIVOT (Vals FOR Workday IN (Monday,Tuesday,Wednesday,Thursday
,Friday,Saturday,Sunday))up
)
SELECT ScheduleID
,EmployeeID
,Workday
FROM X
FOR XML PATH('task'), ROOT('schedules')
结果:
<schedules>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Monday</Workday>
</task>
<task>
<ScheduleID>10</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Tuesday</Workday>
</task>
<task>
<ScheduleID>11</ScheduleID>
<EmployeeID>10001</EmployeeID>
<Workday>Thursday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Saturday</Workday>
</task>
<task>
<ScheduleID>12</ScheduleID>
<EmployeeID>10002</EmployeeID>
<Workday>Sunday</Workday>
</task>
</schedules>