禁用 JIT 调试

Disable JIT debugging

此主题已在许多问题中被询问和回答,我做了尽职调查,但我就是不明白为什么我会遇到这个问题。

在testfailure.exe:

namespace testfailture
{
 class Program
  {
    static void Main(string[] args)
  {
       try
      {
          throw new Exception("I want to report this in the parent window");
      }
      catch (Exception ex)
      {
          throw ex;
      }
   }
}

在test.exe中:

internal void Execute(string packageVersion)
 {

    Process exeProcess = new Process();   
    exeProcess.StartInfo.FileName = "testfailure.exe";
    exeProcess.StartInfo.RedirectStandardOutput = true;
    exeProcess.StartInfo.UseShellExecute = false;
    exeProcess.StartInfo.CreateNoWindow = true;

    try
    {
        exeProcess.Start();
        Console.WriteLine(exeProcess.StandardOutput.ReadToEnd());

    }
    catch (Exception ex)
    {
        throw ex;
    }
}

当我 运行 程序时,我收到弹出窗口并且在执行操作之前不会让程序继续。

我认为这是由于 JIT 调试造成的,所以我做了以下所有事情: https://social.msdn.microsoft.com/Forums/vstudio/en-US/a52eb0ae-bcd8-4043-9661-d5fc3aa5167c/getting-rid-of-justintime-debugger?forum=vsdebug

这是我遇到的一个问题,但最终我想做的是子进程向父级报告错误(不是 console.writeline 因为我想用它来报告状态)并显示在父级的 window.

有什么想法吗?

顺便说一下,我使用的是 Visual Studio Professional 2012。非常感谢您的帮助。

谢谢!

编辑 #1----------------------------

我的过程完全期望一切正常,但我想做的是为意外故障编写代码。当失败时,我希望有一个很好的对话,这样我就可以轻松快速地检测和调试。

无法将未处理的异常传递给父进程。

然而,您可以做的是将数据写入 StandardError,并在父进程中捕获它。

下面的例子来自MSDN:

    Public Sub Main()
      Dim args() As String = Environment.GetCommandLineArgs()
      Dim errorOutput As String = "" 
      ' Make sure that there is at least one command line argument. 
      If args.Length <= 1 Then
         errorOutput += "You must include a filename on the command line." +
                        vbCrLf
      End If 

      For ctr As Integer = 1 To args.GetUpperBound(0)
         ' Check whether the file exists. 
         If Not File.Exists(args(ctr)) Then
            errorOutput += String.Format("'{0}' does not exist.{1}",
                                         args(ctr), vbCrLf)
         Else 
            ' Display the contents of the file. 
            Dim sr As New StreamReader(args(ctr))
            Dim contents As String = sr.ReadToEnd()
            sr.Close()
            Console.WriteLine("***** Contents of file '{0}':{1}{1}",
                              args(ctr), vbCrLf)
            Console.WriteLine(contents)
            Console.WriteLine("*****{0}", vbCrLf)
         End If 
      Next 

      ' Check for error conditions. 
      If Not String.IsNullOrEmpty(errorOutput) Then 
         ' Write error information to a file.
         Console.SetError(New StreamWriter(".\ViewTextFile.Err.txt"))
         Console.Error.WriteLine(errorOutput)
         Console.Error.Close()
         ' Reacquire the standard error stream. 
         Dim standardError As New StreamWriter(Console.OpenStandardError())
         standardError.AutoFlush = True
         Console.SetError(standardError)
         Console.Error.WriteLine("{0}Error information written to ViewTextFile.Err.txt",
                                 vbCrLf)
      End If 
   End Sub