TYPO3：将当前菜单页面 uid 作为参数传递给 userFunc

Question

如何将菜单页面 ID 传递给自定义用户函数？我需要它以便我可以更改一些在 TYPO3 中无效的页面链接。它们将在另一个应用程序中解析。

lib.test = HMENU
lib.test {
  ...
  1 = TMENU
  1 {
    NO = 1
    NO {
        # do not create a link here else there are double <a> tags
        doNotLinkIt = 1
        stdWrap.cObject = CASE
        stdWrap.cObject {
            key.field = doktype
            default = TEXT
            default {
                field = nav_title // title
                typolink.parameter.field = uid
                typolink.wrap = |<span><strong></strong></span>
                typolink.ATagBeforeWrap = 1
                stdWrap.htmlSpecialChars = 1

                postUserFunc = user_productsOnCurrentPage->main
                postUserFunc {
                    // not working
                    pageId.data = {page:uid}
                    pageId.insertData = 1

                    // also not working
                    pageId.field = uid 
                }
            }
    }
  }
  ...
}

Answer 1

我可以直接在用户函数中访问页面 ID：

打字错误：

typolink.userFunc = user_mcfazabosOnCurrentPage->main

PHP:

$pageId = $this->cObj->getFieldVal( 'uid' );

Answer 2

This 可能有解决您问题的办法：

In TMENU $cObj->data is set to the page-record for each menu item.

因此，要传递 hmenu "current iteration" 的页面 uid，应该这样做：

postUserFunc.pageId.data = field:uid

归功于 this（德语）线程。

TYPO3：将当前菜单页面 uid 作为参数传递给 userFunc

TYPO3: Pass current menu page uid as parameter to userFunc

parameters

menu

function

typoscript