为什么压缩会输出更大的 zip 文件？

Question

我真的不了解 python 压缩，因为每当我尝试压缩文件夹或文件时，我最终得到的文件比原始文件大 5.5 倍。为什么会这样？有什么方法可以用 python 压缩文件夹或文件并获得最大为原始文件大小的输出？这是我正在使用的代码。

import os, zipfile

def zipfiles(filename, destname):
  try:
   zf = zipfile.ZipFile(destname, 'w', zipfile.ZIP_DEFLATED)
   for dirname, subdirs, files in os.walk(filename):
      zf.write(dirname)
      for filename in files:
          zf.write(os.path.join(dirname, filename))
   zf.close()
  except Exception, e:
   print str(e)
def main():
   x = raw_input('Enter Filename:   ')
   while len(x) == 0:
       x = raw_input('Enter Filename:   ')
   y = raw_input('Enter destination name:   ')
   while len(y) == 0:
       y = raw_input('Enter destination name:   ')
   zipfiles(x, y+'.zip')
main()

Answer 1

确保目标 .zip 文件不在您正在压缩的同一文件夹中，否则您的脚本可能会将正在创建的文件的副本添加到自身 - 这显然会使它变得更大。

这是您的代码的修订版本，当它在同一目录文件夹中创建时将跳过存档：

import os, zipfile

def zipfiles(source_folder, destination_name):
    source_folder = os.path.abspath(source_folder)
    destination_path = os.path.abspath(destination_name)
    try:
        with zipfile.ZipFile(destination_name, 'w', zipfile.ZIP_DEFLATED) as zf:
            for dirname, subdirs, files in os.walk(source_folder):
                # zf.write(dirname)  # Not needed.
                for filename in files:
                    filepath = os.path.join(dirname, filename)
                    if filepath != destination_path:  # Skip file being created.
                        zf.write(filepath)
    except Exception as e:
        print(e)

def main():
    x = ''
    while not x:
        x = raw_input('Enter source folder name: ')
    y = ''
    while not y:
        y = raw_input('Enter destination archive file name: ')
    zipfiles(x, y+'.zip')

main()

为什么压缩会输出更大的 zip 文件？

Why does compression output a larger zip file?

python

compression

zip

file