正在向 PHP 服务器发送数据

Question

我正在尝试设置将数据发送到 PHP 服务器，但我一点运气都没有。

这是我的 PHP 代码。

<?php
require_once "../config/config.php";
var_dump($_POST);
var_dump($_REQUEST);
// Read request parameters
if(isset($_REQUEST)){
    $username = $db->escape($_REQUEST["username"]);
    $email = $db->escape($_REQUEST["email"]);
    $password = $db->escape($_REQUEST["password"]);
    $id = MD5($email);
    echo $username;
    //$db->query("INSERT INTO user ('id','username','email','password') VALUES ('$id','$username','$email',PASSWORD('$password'))");
    $returnValue = $id;
}else{
    $returnValue = "No data received";
}
// Send back request in JSON format
echo json_encode($returnValue); 
?>

这是我的Swift代码

    let request = NSMutableURLRequest(URL: NSURL(string: "http://***************/register.php")!)

    let session = NSURLSession.sharedSession()

    request.HTTPMethod = "POST"

    let data = "username=JoeBloggs&email=joe@bloggs.com&password=12345"

    request.HTTPBody = (data as NSString).dataUsingEncoding(NSUTF8StringEncoding)
    request.addValue("application/json", forHTTPHeaderField: "Content-Type")
    request.addValue("application/json", forHTTPHeaderField: "Accept")

    let task = session.dataTaskWithRequest(request) { (data, response, error) -> Void in
        print(response)
        let strData = NSString(data: data!, encoding: NSUTF8StringEncoding)
        print(strData)
        print(error)

    }
    task.resume()

我还不担心得到结果（我的工作正常）。我只是无法向服务器获取任何数据。

这是上述脚本的结果。

Optional(<NSHTTPURLResponse: 0x7ff9b3d6ea90> { URL: http://iep.almartin.co.uk/register.php } { status code: 200, headers {
"Cache-Control" = "no-store, no-cache, must-revalidate, post-check=0, pre-check=0";
Connection = close;
"Content-Type" = "text/html; charset=UTF-8";
Date = "Tue, 01 Sep 2015 09:02:46 GMT";
Expires = "Thu, 19 Nov 1981 08:52:00 GMT";
Pragma = "no-cache";
Server = nginx;
"Set-Cookie" = "PHPSESSID=8j2d7oobg9plvdik1dcbqtoq70; path=/";
"Transfer-Encoding" = Identity;
} })
Optional(array(0) {
 }
 array(0) {
 }
 <br />
 <b>Notice</b>:  Undefined index: username in <b>/home/linweb34/i/iep.almartin.co.uk/user/htdocs/register.php</b> on line <b>7</b><br />
 <br />
 <b>Notice</b>:  Undefined index: email in <b>/home/linweb34/i/iep.almartin.co.uk/user/htdocs/register.php</b> on line <b>8</b><br />
 <br />
 <b>Notice</b>:  Undefined index: password in <b>/home/linweb34/i/iep.almartin.co.uk/user/htdocs/register.php</b> on line <b>9</b><br />
 "d41d8cd98f00b204e9800998ecf8427e")
 nil

如您所见，$_REQUEST 和 $_POST 都返回空数组。

我做错了什么？

Answer 1

错误清楚地表明您的 MySQL 使用有问题。以下是工作代码模板。它使用 PDO 进行数据库连接。

function __construct() {
    $this->conn = new PDO('mysql:host=<your hostnam>;dbname=<dbname>', '<user>', '<pass>');
    // Generate stack trace on failure.
    $this->conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}

/*
 * Write a function and pass your variables
 */
function get_data_from_db($id,$username,$password,$email) {
    $stmt = $this->conn->prepare("INSERT INTO `user`(`id`,`username`,`email`,`password`) VALUES (:id,:username,:email,PASSWORD(:password))");
    $stmt->execute(array(':id' => $id, ':username' => $username, ':email' => $email, ':password' => $password));
    $data = $stmt->fetchAll(PDO::FETCH_ASSOC);
    $stmt->closeCursor();

    return $data;
}

现在在您的代码中，只需添加一个函数调用即可：

if(isset($_REQUEST)){
    $username = $db->escape($_REQUEST["username"]);
    $email = $db->escape($_REQUEST["email"]);
    $password = $db->escape($_REQUEST["password"]);
    $id = MD5($email);

    $result = get_result_from_db($id,$username,$password,$email);

    echo json_encode($result);
}

注意：未测试，但应该可以。

Answer 2

找到问题了。

这些行似乎是我应用程序中的罪魁祸首。

request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")

当我删除它们时它工作正常。

这又引出了另一个问题，我如何设置 PHP 以接受 header 类型 "application/json"？

Answer 3

要使用 POST 将 JSON 发送到服务器，您必须将要发送的数据放入字典中并使用 NSJSONSerialization

序列化字典

let request = NSMutableURLRequest(URL: NSURL(string: "http://***************/register.php")!)

let session = NSURLSession.sharedSession()
let postData = ["username" : "JoeBloggs", "email" : "joe@bloggs.com", "password" : "12345"]

do {
  let jsonData = try NSJSONSerialization.dataWithJSONObject(postData, options: NSJSONWritingOptions())
  request.HTTPMethod = "POST"
  request.setValue("\(jsonData.length)", forHTTPHeaderField:"Content-Length")
  request.setValue("application/json", forHTTPHeaderField:"Accept")
  request.setValue("application/json", forHTTPHeaderField:"Content-Type")
  request.HTTPBody = jsonData

  let task = session.dataTaskWithRequest(request) { (data, response, error) -> Void in
    print(response)
    let strData = NSString(data: data!, encoding: NSUTF8StringEncoding)
    print(strData)
    print(error)

  }
  task.resume()
} catch let error as NSError {
  print(error)
}

Answer 4

所以我遵循了@vadian 的回答，但最初没有用。我研究了为什么 PHP 不接受 application/json.

我通过在 php 文件中使用 $HTTP_RAW_POST_DATA 而不是 $_POST 或 $_REQUEST 使其工作。

但是！ $HTTP_RAW_POST_DATA 现在已折旧，但以下代码有效

$json = file_get_contents('php://input'); 
$obj = json_decode($json);

对我来说似乎是 PHP 破解，但至少它有效。

正在向 PHP 服务器发送数据

Sending data to PHP server

ios

xcode7

swift2