使用 java 解析 SOAP/XML 时出现问题
Issue in parsing SOAP/XML using java
我编写了一个 java 程序来解析 SOAP/XML。这是我的代码。
public static void main(String[] args) throws Exception {
Customer customer = new Customer();
customer.id = 123;
customer.firstName = "Jane";
customer.lastName = "Doe";
QName root = new QName("return");
JAXBElement<Customer> je = new JAXBElement<Customer>(root, Customer.class, customer);
XMLOutputFactory xof = XMLOutputFactory.newFactory();
XMLStreamWriter xsw = xof.createXMLStreamWriter(System.out);
xsw.writeStartDocument();
xsw.writeStartElement("soapenv", "Envelope", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("soapenv", "Body", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("", "InitializePayment", "http://service.jaxws.blog/");
xsw.writeStartElement("", "request", "http://service.jaxws.blog/");
JAXBContext jc = JAXBContext.newInstance(Customer.class);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);
marshaller.marshal(je, xsw);
xsw.writeEndDocument();
xsw.close();
}
我得到这样的输出。
<?xml version="1.0" ?>
<soapenv:Envelope>
<soapenv:Body>
<InitializePayment>
<request>
<return id="123">
<firstName>Jane</firstName>
<lastName>Doe</lastName>
</return>
</request>
</InitializePayment>
</soapenv:Body>
</soapenv:Envelope>
但我需要 id
必须作为标签出现在 <return>
中的输出 i。像这样
<return>
<id>123</id>
<firstName>Jane</firstName>
<lastName>Doe</lastName>
</return>
您只需删除 id
field/property 上的 @XmlAttribute
注释。
thanks it works. But url which in a envelope is not come in output
您需要利用 writeNamespace
和 writeDefaultNamespace
方法,如下所示:
xsw.writeStartElement("soapenv", "Envelope", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeNamespace("soapenv", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("soapenv", "Body", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("", "InitializePayment", "http://service.jaxws.blog/");
xsw.writeDefaultNamespace("http://service.jaxws.blog/");
xsw.writeStartElement("", "request", "http://service.jaxws.blog/");
我编写了一个 java 程序来解析 SOAP/XML。这是我的代码。
public static void main(String[] args) throws Exception {
Customer customer = new Customer();
customer.id = 123;
customer.firstName = "Jane";
customer.lastName = "Doe";
QName root = new QName("return");
JAXBElement<Customer> je = new JAXBElement<Customer>(root, Customer.class, customer);
XMLOutputFactory xof = XMLOutputFactory.newFactory();
XMLStreamWriter xsw = xof.createXMLStreamWriter(System.out);
xsw.writeStartDocument();
xsw.writeStartElement("soapenv", "Envelope", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("soapenv", "Body", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("", "InitializePayment", "http://service.jaxws.blog/");
xsw.writeStartElement("", "request", "http://service.jaxws.blog/");
JAXBContext jc = JAXBContext.newInstance(Customer.class);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);
marshaller.marshal(je, xsw);
xsw.writeEndDocument();
xsw.close();
}
我得到这样的输出。
<?xml version="1.0" ?>
<soapenv:Envelope>
<soapenv:Body>
<InitializePayment>
<request>
<return id="123">
<firstName>Jane</firstName>
<lastName>Doe</lastName>
</return>
</request>
</InitializePayment>
</soapenv:Body>
</soapenv:Envelope>
但我需要 id
必须作为标签出现在 <return>
中的输出 i。像这样
<return>
<id>123</id>
<firstName>Jane</firstName>
<lastName>Doe</lastName>
</return>
您只需删除 id
field/property 上的 @XmlAttribute
注释。
thanks it works. But url which in a envelope is not come in output
您需要利用 writeNamespace
和 writeDefaultNamespace
方法,如下所示:
xsw.writeStartElement("soapenv", "Envelope", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeNamespace("soapenv", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("soapenv", "Body", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("", "InitializePayment", "http://service.jaxws.blog/");
xsw.writeDefaultNamespace("http://service.jaxws.blog/");
xsw.writeStartElement("", "request", "http://service.jaxws.blog/");