打开 XML 直接在磁盘上导出数据表到 excel
Open XML Export datatable to excel directly on disk
我想将数据表直接导出到 xlsx 到我的磁盘,而不是在服务器上提供目标路径和保存文件。
我有以下功能:
private void ExportToCSVFileOpenXML(DataTable dt, string destination)
{
DataSet ds = new DataSet();
DataTable dtCopy = new DataTable();
dtCopy = dt.Copy();
ds.Tables.Add(dtCopy);
try
{
var workbook = SpreadsheetDocument.Create(Server.MapPath("~/" + destination.Replace("/","").Replace(":","")), DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
{
var workbookPart = workbook.AddWorkbookPart();
workbook.WorkbookPart.Workbook = new DocumentFormat.OpenXml.Spreadsheet.Workbook();
workbook.WorkbookPart.Workbook.Sheets = new DocumentFormat.OpenXml.Spreadsheet.Sheets();
foreach (System.Data.DataTable table in ds.Tables)
{
var sheetPart = workbook.WorkbookPart.AddNewPart<WorksheetPart>();
var sheetData = new DocumentFormat.OpenXml.Spreadsheet.SheetData();
sheetPart.Worksheet = new DocumentFormat.OpenXml.Spreadsheet.Worksheet(sheetData);
DocumentFormat.OpenXml.Spreadsheet.Sheets sheets = workbook.WorkbookPart.Workbook.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.Sheets>();
string relationshipId = workbook.WorkbookPart.GetIdOfPart(sheetPart);
uint sheetId = 1;
if (sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Count() > 0)
{
sheetId =
sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Select(s => s.SheetId.Value).Max() + 1;
}
DocumentFormat.OpenXml.Spreadsheet.Sheet sheet = new DocumentFormat.OpenXml.Spreadsheet.Sheet() { Id = relationshipId, SheetId = sheetId, Name = table.TableName };
sheets.Append(sheet);
DocumentFormat.OpenXml.Spreadsheet.Row headerRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
List<String> columns = new List<string>();
foreach (System.Data.DataColumn column in table.Columns)
{
columns.Add(column.ColumnName);
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(column.ColumnName);
headerRow.AppendChild(cell);
}
sheetData.AppendChild(headerRow);
foreach (System.Data.DataRow dsrow in table.Rows)
{
DocumentFormat.OpenXml.Spreadsheet.Row newRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
foreach (String col in columns)
{
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(dsrow[col].ToString()); //
newRow.AppendChild(cell);
}
sheetData.AppendChild(newRow);
}
}
}
}
catch (Exception)
{
throw;
}
}
我怎样才能将目标路径直接导出到磁盘而不是保存在服务器上:
var workbook = SpreadsheetDocument.Create(Server.MapPath("~/" + destination.Replace("/","").Replace(":","")), DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
请帮帮我。
SpreadsheetDocument.Create 接受流、字符串或包作为其第一个参数,因此我们可以只使用 MemoryStream 在内存中创建工作簿,return 一个字节数组。
应该是这样的:
public byte[] ExportToCSVFileOpenXML(DataTable dt)
{
byte[] returnBytes = null;
using (MemoryStream mem = new MemoryStream())
{
var workbook = SpreadsheetDocument.Create(mem, DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
// your code
workbook.WorkbookPart.Workbook.Save();
workbook.Close();
returnBytes = mem.ToArray();
}
return returnBytes;
}
一旦你有一个字节数组将它作为文件传递应该很容易。
如果您使用的是 MVC,那么在您的控制器中应该是这样的:
return File(ExportToCSVFileOpenXML(aTable), "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet", "export.xlsx");
Alex 的回答让我找到正确的答案。
我做了以下事情:
private byte[] ExportToCSVFileOpenXML(DataTable dt)
{
DataSet ds = new DataSet();
DataTable dtCopy = new DataTable();
dtCopy = dt.Copy();
ds.Tables.Add(dtCopy);
try
{
byte[] returnBytes = null;
MemoryStream mem = new MemoryStream();
var workbook = SpreadsheetDocument.Create(mem, DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
{
var workbookPart = workbook.AddWorkbookPart();
workbook.WorkbookPart.Workbook = new DocumentFormat.OpenXml.Spreadsheet.Workbook();
workbook.WorkbookPart.Workbook.Sheets = new DocumentFormat.OpenXml.Spreadsheet.Sheets();
foreach (System.Data.DataTable table in ds.Tables)
{
var sheetPart = workbook.WorkbookPart.AddNewPart<WorksheetPart>();
var sheetData = new DocumentFormat.OpenXml.Spreadsheet.SheetData();
sheetPart.Worksheet = new DocumentFormat.OpenXml.Spreadsheet.Worksheet(sheetData);
DocumentFormat.OpenXml.Spreadsheet.Sheets sheets = workbook.WorkbookPart.Workbook.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.Sheets>();
string relationshipId = workbook.WorkbookPart.GetIdOfPart(sheetPart);
uint sheetId = 1;
if (sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Count() > 0)
{
sheetId =
sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Select(s => s.SheetId.Value).Max() + 1;
}
DocumentFormat.OpenXml.Spreadsheet.Sheet sheet = new DocumentFormat.OpenXml.Spreadsheet.Sheet() { Id = relationshipId, SheetId = sheetId, Name = table.TableName };
sheets.Append(sheet);
DocumentFormat.OpenXml.Spreadsheet.Row headerRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
List<String> columns = new List<string>();
foreach (System.Data.DataColumn column in table.Columns)
{
columns.Add(column.ColumnName);
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(column.ColumnName);
headerRow.AppendChild(cell);
}
sheetData.AppendChild(headerRow);
foreach (System.Data.DataRow dsrow in table.Rows)
{
DocumentFormat.OpenXml.Spreadsheet.Row newRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
foreach (String col in columns)
{
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(dsrow[col].ToString()); //
newRow.AppendChild(cell);
}
sheetData.AppendChild(newRow);
}
}
}
workbook.WorkbookPart.Workbook.Save();
workbook.Close();
returnBytes = mem.ToArray();
return returnBytes;
}
catch (Exception)
{
throw;
}
}
将此函数称为:
protected void hlInCorrectRecords_Click(object sender, EventArgs e)
{
lblmsg.Text = "";
DataSet dsDtUploadedSummary = (DataSet)ViewState["dsDtUploadedSummary"];
if (dsDtUploadedSummary.Tables.Count > 0)
{
DataTable dtFreshRecords = dsDtUploadedSummary.Tables[4];
if (dtFreshRecords.Rows.Count > 0 && dtFreshRecords != null)
{
Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
string filename = @"IncorrectRecordsUploaded_" + DateTime.Now.ToString();
Response.AddHeader("Content-Disposition", "inline;filename=" + filename.Replace("/", "").Replace(":", "")+".xlsx");
Response.BinaryWrite(ExportToCSVFileOpenXML(dtFreshRecords));
Response.Flush();
Response.End();
}
else
{
lblmsg.Text = "No Data To Export";
}
}
else
{
lblmsg.Text = "No Data To Export";
}
}
谢谢亚历克斯。我使用的是纯 ASP.NET 而不是 MVC
我想将数据表直接导出到 xlsx 到我的磁盘,而不是在服务器上提供目标路径和保存文件。
我有以下功能:
private void ExportToCSVFileOpenXML(DataTable dt, string destination)
{
DataSet ds = new DataSet();
DataTable dtCopy = new DataTable();
dtCopy = dt.Copy();
ds.Tables.Add(dtCopy);
try
{
var workbook = SpreadsheetDocument.Create(Server.MapPath("~/" + destination.Replace("/","").Replace(":","")), DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
{
var workbookPart = workbook.AddWorkbookPart();
workbook.WorkbookPart.Workbook = new DocumentFormat.OpenXml.Spreadsheet.Workbook();
workbook.WorkbookPart.Workbook.Sheets = new DocumentFormat.OpenXml.Spreadsheet.Sheets();
foreach (System.Data.DataTable table in ds.Tables)
{
var sheetPart = workbook.WorkbookPart.AddNewPart<WorksheetPart>();
var sheetData = new DocumentFormat.OpenXml.Spreadsheet.SheetData();
sheetPart.Worksheet = new DocumentFormat.OpenXml.Spreadsheet.Worksheet(sheetData);
DocumentFormat.OpenXml.Spreadsheet.Sheets sheets = workbook.WorkbookPart.Workbook.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.Sheets>();
string relationshipId = workbook.WorkbookPart.GetIdOfPart(sheetPart);
uint sheetId = 1;
if (sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Count() > 0)
{
sheetId =
sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Select(s => s.SheetId.Value).Max() + 1;
}
DocumentFormat.OpenXml.Spreadsheet.Sheet sheet = new DocumentFormat.OpenXml.Spreadsheet.Sheet() { Id = relationshipId, SheetId = sheetId, Name = table.TableName };
sheets.Append(sheet);
DocumentFormat.OpenXml.Spreadsheet.Row headerRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
List<String> columns = new List<string>();
foreach (System.Data.DataColumn column in table.Columns)
{
columns.Add(column.ColumnName);
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(column.ColumnName);
headerRow.AppendChild(cell);
}
sheetData.AppendChild(headerRow);
foreach (System.Data.DataRow dsrow in table.Rows)
{
DocumentFormat.OpenXml.Spreadsheet.Row newRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
foreach (String col in columns)
{
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(dsrow[col].ToString()); //
newRow.AppendChild(cell);
}
sheetData.AppendChild(newRow);
}
}
}
}
catch (Exception)
{
throw;
}
}
我怎样才能将目标路径直接导出到磁盘而不是保存在服务器上:
var workbook = SpreadsheetDocument.Create(Server.MapPath("~/" + destination.Replace("/","").Replace(":","")), DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
请帮帮我。
SpreadsheetDocument.Create 接受流、字符串或包作为其第一个参数,因此我们可以只使用 MemoryStream 在内存中创建工作簿,return 一个字节数组。
应该是这样的:
public byte[] ExportToCSVFileOpenXML(DataTable dt)
{
byte[] returnBytes = null;
using (MemoryStream mem = new MemoryStream())
{
var workbook = SpreadsheetDocument.Create(mem, DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
// your code
workbook.WorkbookPart.Workbook.Save();
workbook.Close();
returnBytes = mem.ToArray();
}
return returnBytes;
}
一旦你有一个字节数组将它作为文件传递应该很容易。
如果您使用的是 MVC,那么在您的控制器中应该是这样的:
return File(ExportToCSVFileOpenXML(aTable), "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet", "export.xlsx");
Alex 的回答让我找到正确的答案。
我做了以下事情:
private byte[] ExportToCSVFileOpenXML(DataTable dt)
{
DataSet ds = new DataSet();
DataTable dtCopy = new DataTable();
dtCopy = dt.Copy();
ds.Tables.Add(dtCopy);
try
{
byte[] returnBytes = null;
MemoryStream mem = new MemoryStream();
var workbook = SpreadsheetDocument.Create(mem, DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
{
var workbookPart = workbook.AddWorkbookPart();
workbook.WorkbookPart.Workbook = new DocumentFormat.OpenXml.Spreadsheet.Workbook();
workbook.WorkbookPart.Workbook.Sheets = new DocumentFormat.OpenXml.Spreadsheet.Sheets();
foreach (System.Data.DataTable table in ds.Tables)
{
var sheetPart = workbook.WorkbookPart.AddNewPart<WorksheetPart>();
var sheetData = new DocumentFormat.OpenXml.Spreadsheet.SheetData();
sheetPart.Worksheet = new DocumentFormat.OpenXml.Spreadsheet.Worksheet(sheetData);
DocumentFormat.OpenXml.Spreadsheet.Sheets sheets = workbook.WorkbookPart.Workbook.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.Sheets>();
string relationshipId = workbook.WorkbookPart.GetIdOfPart(sheetPart);
uint sheetId = 1;
if (sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Count() > 0)
{
sheetId =
sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Select(s => s.SheetId.Value).Max() + 1;
}
DocumentFormat.OpenXml.Spreadsheet.Sheet sheet = new DocumentFormat.OpenXml.Spreadsheet.Sheet() { Id = relationshipId, SheetId = sheetId, Name = table.TableName };
sheets.Append(sheet);
DocumentFormat.OpenXml.Spreadsheet.Row headerRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
List<String> columns = new List<string>();
foreach (System.Data.DataColumn column in table.Columns)
{
columns.Add(column.ColumnName);
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(column.ColumnName);
headerRow.AppendChild(cell);
}
sheetData.AppendChild(headerRow);
foreach (System.Data.DataRow dsrow in table.Rows)
{
DocumentFormat.OpenXml.Spreadsheet.Row newRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
foreach (String col in columns)
{
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(dsrow[col].ToString()); //
newRow.AppendChild(cell);
}
sheetData.AppendChild(newRow);
}
}
}
workbook.WorkbookPart.Workbook.Save();
workbook.Close();
returnBytes = mem.ToArray();
return returnBytes;
}
catch (Exception)
{
throw;
}
}
将此函数称为:
protected void hlInCorrectRecords_Click(object sender, EventArgs e)
{
lblmsg.Text = "";
DataSet dsDtUploadedSummary = (DataSet)ViewState["dsDtUploadedSummary"];
if (dsDtUploadedSummary.Tables.Count > 0)
{
DataTable dtFreshRecords = dsDtUploadedSummary.Tables[4];
if (dtFreshRecords.Rows.Count > 0 && dtFreshRecords != null)
{
Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
string filename = @"IncorrectRecordsUploaded_" + DateTime.Now.ToString();
Response.AddHeader("Content-Disposition", "inline;filename=" + filename.Replace("/", "").Replace(":", "")+".xlsx");
Response.BinaryWrite(ExportToCSVFileOpenXML(dtFreshRecords));
Response.Flush();
Response.End();
}
else
{
lblmsg.Text = "No Data To Export";
}
}
else
{
lblmsg.Text = "No Data To Export";
}
}
谢谢亚历克斯。我使用的是纯 ASP.NET 而不是 MVC