将所选答案保存在 php 中
save id with the selected answer in php
我正在尝试使用问题 ID 保存所选答案的结果。不知道如何将 id 传递给数据库。这是我的代码
<?php
session_start();
include('config/manpower_db.php');
$sql = mysql_query("SELECT * FROM question") or die(mysql_error());
$i = '1';
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form action="save_feedback.php" method="post">
<H2> How Will You Rate This Service</H2>
<?php
while($row = mysql_fetch_array($sql))
{
echo $row['question'];
// $comp = $row['id'][$i];
// $_SESSION['comp']= $comp;
?>
<br />
<?php
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='1' >1";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='2' >2";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='3' >3";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='4' >4";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='5' >5";
echo'<br/>';
$i++;
}
?>
<br/>
<strong> NOTE:</strong> 1 - Very Poor, 2 - poor, 3 - Okay, 4 - Fair, 5 - Good
<p>
<input name="submit" type="submit" value="submit" />
</form>
</body>
</html>
保存到数据库
<?php
session_start();
$answer = $_POST['answer'];
include('config/manpower_db.php');
foreach($hobb as $key=>$val)
{
$var1=$hobb[$key];
$var2=$answer[$key];
//include ('connect.php');
//include ('mysql_connect.php');
$table = "INSERT INTO answer (answer) ".
"VALUES ('$var2')";
mysql_query($table) or die(mysql_error());
$inserted_fid = mysql_insert_id();
mysql_close();
}
echo'<script>alert("Inserted Successfully")</script>';
?>
这有效,但我正在尝试保存问题 ID。不知道如何将其传递给数据库。
提前致谢
在隐藏字段中传递 ID
试试这个
<?php
session_start();
include('config/manpower_db.php');
$sql = mysql_query("SELECT * FROM question") or die(mysql_error());
$i = '1';
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form action="save_feedback.php" method="post">
<H2> How Will You Rate This Service</H2>
<?php
while($row = mysql_fetch_array($sql))
{
echo $row['question'];
$comp = $row['id'][$i];
// $_SESSION['comp']= $comp;
?>
<br />
<?php
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='1' >1";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='2' >2";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='3' >3";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='4' >4";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='5' >5";
echo "<input type='hidden' name='question_id' value=$comp >";
echo'<br/>';
$i++;
}
?>
<br/>
<strong> NOTE:</strong> 1 - Very Poor, 2 - poor, 3 - Okay, 4 - Fair, 5 - Good
<p>
<input name="submit" type="submit" value="submit" />
</form>
</body>
</html>
并保存数据文件
<?php
session_start();
$answer = $_POST['answer'];
$question_id = $_POST['question_id'];
include('config/manpower_db.php');
foreach($hobb as $key=>$val)
{
$var1=$hobb[$key];
$var2=$answer[$key];
//include ('connect.php');
//include ('mysql_connect.php');
$table = "INSERT INTO answer (answer) ".
"VALUES ('$var2')";
mysql_query($table) or die(mysql_error());
$inserted_fid = mysql_insert_id();
mysql_close();
}
echo'<script>alert("Inserted Successfully")</script>';
?>
在隐藏字段中传递 ID
如果只有一个按钮,则将您的 id 分配给 button
的值
您的问题是您为每一行分配了不同的 <input>
名称,这意味着每个输入本质上是一个不同的问题。因此,每个答案都会被发送到服务器,例如 $_POST['answer1'];
、$_POST['answer2'];
等
从您的输入中删除 [".$row['id']."]
,$answer = $_POST['answer'];
将导致仅存储选定的输入值,从而输入到数据库中。
请记住,您正在将输入 value
属性传递给服务器并使用 name
属性引用它。
我假设 $row['id']
是从 questions
table 中提取的唯一数字,所以这就是问题 ID。
因此在您的保存文件中从这一行开始。
$var2=$answer[$key];
$key
为题号,可以用来保存。
我正在尝试使用问题 ID 保存所选答案的结果。不知道如何将 id 传递给数据库。这是我的代码
<?php
session_start();
include('config/manpower_db.php');
$sql = mysql_query("SELECT * FROM question") or die(mysql_error());
$i = '1';
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form action="save_feedback.php" method="post">
<H2> How Will You Rate This Service</H2>
<?php
while($row = mysql_fetch_array($sql))
{
echo $row['question'];
// $comp = $row['id'][$i];
// $_SESSION['comp']= $comp;
?>
<br />
<?php
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='1' >1";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='2' >2";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='3' >3";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='4' >4";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='5' >5";
echo'<br/>';
$i++;
}
?>
<br/>
<strong> NOTE:</strong> 1 - Very Poor, 2 - poor, 3 - Okay, 4 - Fair, 5 - Good
<p>
<input name="submit" type="submit" value="submit" />
</form>
</body>
</html>
保存到数据库
<?php
session_start();
$answer = $_POST['answer'];
include('config/manpower_db.php');
foreach($hobb as $key=>$val)
{
$var1=$hobb[$key];
$var2=$answer[$key];
//include ('connect.php');
//include ('mysql_connect.php');
$table = "INSERT INTO answer (answer) ".
"VALUES ('$var2')";
mysql_query($table) or die(mysql_error());
$inserted_fid = mysql_insert_id();
mysql_close();
}
echo'<script>alert("Inserted Successfully")</script>';
?>
这有效,但我正在尝试保存问题 ID。不知道如何将其传递给数据库。 提前致谢
在隐藏字段中传递 ID
试试这个
<?php
session_start();
include('config/manpower_db.php');
$sql = mysql_query("SELECT * FROM question") or die(mysql_error());
$i = '1';
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form action="save_feedback.php" method="post">
<H2> How Will You Rate This Service</H2>
<?php
while($row = mysql_fetch_array($sql))
{
echo $row['question'];
$comp = $row['id'][$i];
// $_SESSION['comp']= $comp;
?>
<br />
<?php
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='1' >1";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='2' >2";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='3' >3";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='4' >4";
echo "<td> <input type='radio' name='answer[".$row['id']."]' value='5' >5";
echo "<input type='hidden' name='question_id' value=$comp >";
echo'<br/>';
$i++;
}
?>
<br/>
<strong> NOTE:</strong> 1 - Very Poor, 2 - poor, 3 - Okay, 4 - Fair, 5 - Good
<p>
<input name="submit" type="submit" value="submit" />
</form>
</body>
</html>
并保存数据文件
<?php
session_start();
$answer = $_POST['answer'];
$question_id = $_POST['question_id'];
include('config/manpower_db.php');
foreach($hobb as $key=>$val)
{
$var1=$hobb[$key];
$var2=$answer[$key];
//include ('connect.php');
//include ('mysql_connect.php');
$table = "INSERT INTO answer (answer) ".
"VALUES ('$var2')";
mysql_query($table) or die(mysql_error());
$inserted_fid = mysql_insert_id();
mysql_close();
}
echo'<script>alert("Inserted Successfully")</script>';
?>
在隐藏字段中传递 ID 如果只有一个按钮,则将您的 id 分配给 button
的值您的问题是您为每一行分配了不同的 <input>
名称,这意味着每个输入本质上是一个不同的问题。因此,每个答案都会被发送到服务器,例如 $_POST['answer1'];
、$_POST['answer2'];
等
从您的输入中删除 [".$row['id']."]
,$answer = $_POST['answer'];
将导致仅存储选定的输入值,从而输入到数据库中。
请记住,您正在将输入 value
属性传递给服务器并使用 name
属性引用它。
我假设 $row['id']
是从 questions
table 中提取的唯一数字,所以这就是问题 ID。
因此在您的保存文件中从这一行开始。
$var2=$answer[$key];
$key
为题号,可以用来保存。