如何在 JavaScript 中组合原型函数样式？

Question

我因 5 "simular" 原型函数的重复而受到 CodeClimate 的指责，因为重复导致了 D 评级。

我缺乏关于如何组合/不重复类似代码以改进我的知识 "code style"。非常感谢您的帮助。

原型：

SomeThing.prototype.destination = function(path) {
  if (!arguments.length) {
    return this.path(this._destination);
  }
  assert(is.string(path), 'You must pass a destination path string.');

SomeThing.prototype.frontmatter = function(frontmatter) {
  if (!arguments.length) {
    return this._frontmatter;
  }
  assert(is.boolean(frontmatter), 'You must pass a boolean.');

SomeThing.prototype.clean = function(clean) {
  if (!arguments.length) {
    return this._clean;
  }
  assert(is.boolean(clean), 'You must pass a boolean.');

SomeThing.prototype.concurrency = function(max) {
  if (!arguments.length) {
    return this._concurrency;
  }
  assert(is.number(max), 'You must pass a number for concurrency.');

Answer 1

这会干掉你的代码：

function makeProp(prop, type) {
    return function(someArg) {
        if (!arguments.length) return this['_' + prop];
        var msg = 'You must pass a ' + type + ' for ' + prop;
        assert(is[type], msg)
    }
}

Something.prototype = {
    destination: makeProp('destination', 'string'),
    frontmatter: makeProp('frontmatter', 'boolean'),
    clean: makeProp('clean', 'boolean'),
    concurrency: makeProp('concurrency', 'number')
}

如何在 JavaScript 中组合原型函数样式？

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