无法解析 Sendgrid 解析 api 原始回调到 Griddler 电子邮件对象

Question

我正在努力完成以下任务：

让所有发送到我的域的电子邮件解析收件人、正文、主题行和...的内容，以便我从中构建传真对象并将其作为传真发送

到目前为止，我已经能够将我的 MX 记录设置为指向 Sendgrid，并且使用 Ngrok 从 Sendgrid 的解析 API 我在我的本地主机服务器中获得了回调。下一步是将原始对象变成我可以使用的对象。这让我想到了 Thoughbot 的 Griddler Gem.

到目前为止，我是这样设置我的应用程序的：

发送网格设置： URL: https://8c00fab0.ngrok.io/email_processor | Spam Check 和 Send Raw 都被选中

如前所述，这部分有效，因为我确实收到了：

Parameters: {"dkim"=>"{@gmail.com : pass}", "email"=>"Received: by mx0034p1mdw1.sendgrid.net with SMTP id 253FfvZ40f Wed, 09 Sep 2015 22:31:48 +0000 (UTC)\nReceived: from mail-qg0-f54.google.com (mail-qg0-f54.google.com [209.85.192.54]) by mx0034p1mdw1.sendgrid.net (Postfix) with ESMTPS id 63848A83017 for <14085552422@faxbyemail.co>; Wed,  9 Sep 2015 22:31:48 +0000 (UTC)\nReceived: by qgx61 with SMTP id 61so21251135qgx.3 for <14085552422@faxbyemail.co>; Wed, 09 Sep 2015 15:31:48 -0700 (PDT)\nDKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:from:date:message-id:subject:to:content-type; bh=Wo6p7CSlR30aGxf5SwjuZ2klt31URDqTZUHrKdmLz7s=; b=fWfFOQ4YOtijYvphYL9/1shyzK8CBTcHS37s89t9Qn4xK8OrXwVKtmGtNnwg7a1n48 JHkEeAdxVvRMpinxPllGiJoPNy0ivVN36uEYbsrLTcZVlx9RIIl8u5PjmrE1aqlnkjPy gOcbfJunVCFZLaLpv3RB/GiNYL1bodgW7nn8sMTmwN5EwoH7SncS7cle4ksPadgiGv9f DVoJniX2yuMqygSVLT4Qrk4JDzR6G2oj1Fz3QkcrQfNKxOS6iyBhpnh3cDuUi8GTSVYl Nqq2dtKlUNqI+U9ojtG1BjGVUKbP0v5apF3Wvmj72p8L0AB3FHqL8uvFnhi2dGTFVq+y 6nUQ==\nX-Received: by 10.140.233.137 with SMTP id e131mr48879201qhc.37.1441837907953; Wed, 09 Sep 2015 15:31:47 -0700 (PDT)\nMIME-Version: 1.0\nFrom: Sam Sedighian <samansb@gmail.com>\nDate: Wed, 09 Sep 2015 22:31:38 +0000\nMessage-ID: <CAEMkzYbhsLLB3NPLznG+-RibP5kzDG5yTT++mQL1ep-vH6_orA@mail.gmail.com>\nSubject: test 20\nTo: \"14085552422@faxbyemail.co\" <14085552422@faxbyemail.co>\nContent-Type: multipart/alternative; boundary=001a11354d8053d2d1051f580c22\n\n--001a11354d8053d2d1051f580c22\nContent-Type: text/plain; charset=UTF-8\n\nbody etxt\n\n--001a11354d8053d2d1051f580c22\nContent-Type: text/html; charset=UTF-8\n\n<div dir=\"ltr\">body etxt</div>\n\n--001a11354d8053d2d1051f580c22--\n", "to"=>"\"14085552422@faxbyemail.co\" <14085552422@faxbyemail.co>", "from"=>"Sam Sedighian <samansb@gmail.com>", "sender_ip"=>"209.85.192.54", "spam_report"=>"Spam detection software, running on the system \"mx0034p1mdw1.sendgrid.net\", has\nidentified this incoming email as possible spam.  The original message\nhas been attached to this so you can view it (if it isn't spam) or label\nsimilar future email.  If you have any questions, see\n@@CONTACT_ADDRESS@@ for details.\n\nContent preview:  body etxt body etxt [...] \n\nContent analysis details:   (0.0 points, 5.0 required)\n\n pts rule name              description\n---- ---------------------- --------------------------------------------------\n 0.0 FREEMAIL_FROM          Sender email is freemail (samansb[at]gmail.com)\n 0.0 HTML_MESSAGE           BODY: HTML included in message\n 0.0 T_MIME_NO_TEXT         No text body parts\n\n", "envelope"=>"{\"to\":[\"14085552422@faxbyemail.co\"],\"from\":\"samansb@gmail.com\"}", "subject"=>"test 20", "spam_score"=>"0.012", "charsets"=>"{\"to\":\"UTF-8\",\"subject\":\"UTF-8\",\"from\":\"UTF-8\"}", "SPF"=>"pass"}

Gemfile

gem 'griddler'
gem 'griddler-sendgrid'

Gemfile.lock

griddler (1.2.1)
  htmlentities
  rails (>= 3.2.0)
griddler-sendgrid (0.0.1)
  griddler

routes.rb

post '/email_processor' => 'fax#sendgrid'
# this corresponds to the following route when I rake route:
# email_processor POST   /email_processor(.:format) fax#sendgrid

config/initializers/griddler.rb

Griddler.configure do |config|
  config.processor_class = EmailProcessor
  config.processor_method = :process
  config.reply_delimiter = '-- REPLY ABOVE THIS LINE --'
  config.email_service = :sendgrid
end

app/controllers/fax_controller.rb

def sendgrid
  EmailProcessor.new(params).process
end

app/models/email_processor.rb

class EmailProcessor

  def initialize(email)
    @email = email
    @from = email.from
    @body = email.body
  end

  def self.process(email)
    Fax.create({params go here})
  end

end

我最终给出了 Completed 500 内部服务器错误 - 因为我没有将 200 OK 传递回 Sendgrid，但重要的是我在日志中收到以下错误：

NoMethodError (undefined method `from' for #<ActionController::Parameters:0x007fc742a33070>):
  app/models/email_processor.rb:5:in `initialize'
  app/controllers/fax_controller.rb:31:in `new'
  app/controllers/fax_controller.rb:31:in `sendgrid'

Answer 1

我在 Rails 中执行此操作的方法是在控制器中收集电子邮件参数。

例如，在我创建的示例应用程序中，人们将自拍照通过电子邮件发送到我们的 Parse API。在我的 selfie_controller.rb 中，我有一条路线 '/inbound' 并且我有以下内容：

def inbound

    if !params['attachment1'].nil? and params['attachment1'].content_type == "image/jpeg"

        Selfy.create!({ pic: params['attachment1'], email: params['from'] })

    end

end

来电Selfy.create！使用 selfy.rb 模型，但我从电子邮件中收集参数以从控制器发送给它。

你可以试试这个吗？

Answer 2

我认为问题在于您绕过了 Griddler 在控制器端所做的工作。您将 Sendgrid 指向您自己创建的控制器和操作。相反，我认为您想指向 Griddler 的控制器和动作。参见 the README under "Installation"。

将您的 routes.rb 更改为：

# your own route
# post '/email_processor' => 'fax#sendgrid'

# griddler's
post '/email_processor' => 'griddler/emails#create'

如果你 take a look at Griddler's controller 你会发现它可以做一些事情来让你的电子邮件处理器 class。

无法解析 Sendgrid 解析 api 原始回调到 Griddler 电子邮件对象

Unable to parse Sendgrid parse api raw callback into Griddler email object

ruby-on-rails

sendgrid

griddler