C#。如何计算从输入中输入的数字?
C#. How to count digits entered from input?
这是一个数字相乘的代码,用户输入。
string x;
double t, s = 1;
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
while ((x = Console.ReadLine()) != "")
{
t = Convert.ToDouble(x);
s *= t;
}
Console.WriteLine("The result is: {0}", s);
Console.ReadLine();
结果显示在最后,但是如何让它显示输入的数字总数?
例如:我输入 1、2 和 3。所以总计数为 3。
string x;
double t, s = 1;
int count = 0;
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
while ((x = Console.ReadLine()) != "")
{
t = Convert.ToDouble(x);
s *= t;
count++;
}
Console.WriteLine("The result is: {0}", s);
Console.WriteLine("The count is: {0}", count);
Console.ReadLine();
为什么不是计数器的变量?
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
int i=0;
while ((x = Console.ReadLine()) != "")
{
i++;
t = Convert.ToDouble(x);
s *= t;
}
Console.WriteLine("The result is: {0}", s);
Console.ReadLine();
您必须计算使用计数器变量的循环迭代次数:
int loopCounter=0;
while ((x = Console.ReadLine()) != "")
{
t = Convert.ToDouble(x);
s *= t;
loopCounter++;
}
Console.WriteLine("The count is: {0}", loopCounter);
您可以尝试计算字符串输入中的字符数 (x)。
int temp=x.Length();
- 最好用TryParse避免
FormatException
- Char.IsDigit returns true 是当前字符是数字(显然)
示例:
string x;
double t, s = 1;
int digitCount = 0;
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
while ((x = Console.ReadLine()) != "")
{
if (!Double.TryParse(x, out t))
continue;
foreach (var c in x)
if (Char.IsDigit(c))
digitCount++;
s *= t;
}
Console.WriteLine("The result is: {0}", s);
Console.WriteLine("The count of digits is: {0}", digitCount);
Console.ReadLine();
这是一个数字相乘的代码,用户输入。
string x;
double t, s = 1;
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
while ((x = Console.ReadLine()) != "")
{
t = Convert.ToDouble(x);
s *= t;
}
Console.WriteLine("The result is: {0}", s);
Console.ReadLine();
结果显示在最后,但是如何让它显示输入的数字总数? 例如:我输入 1、2 和 3。所以总计数为 3。
string x;
double t, s = 1;
int count = 0;
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
while ((x = Console.ReadLine()) != "")
{
t = Convert.ToDouble(x);
s *= t;
count++;
}
Console.WriteLine("The result is: {0}", s);
Console.WriteLine("The count is: {0}", count);
Console.ReadLine();
为什么不是计数器的变量?
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
int i=0;
while ((x = Console.ReadLine()) != "")
{
i++;
t = Convert.ToDouble(x);
s *= t;
}
Console.WriteLine("The result is: {0}", s);
Console.ReadLine();
您必须计算使用计数器变量的循环迭代次数:
int loopCounter=0;
while ((x = Console.ReadLine()) != "")
{
t = Convert.ToDouble(x);
s *= t;
loopCounter++;
}
Console.WriteLine("The count is: {0}", loopCounter);
您可以尝试计算字符串输入中的字符数 (x)。 int temp=x.Length();
- 最好用TryParse避免
FormatException
- Char.IsDigit returns true 是当前字符是数字(显然)
示例:
string x;
double t, s = 1;
int digitCount = 0;
Console.WriteLine("Enter some numbers: ");
Console.WriteLine("To finish, press Enter");
while ((x = Console.ReadLine()) != "")
{
if (!Double.TryParse(x, out t))
continue;
foreach (var c in x)
if (Char.IsDigit(c))
digitCount++;
s *= t;
}
Console.WriteLine("The result is: {0}", s);
Console.WriteLine("The count of digits is: {0}", digitCount);
Console.ReadLine();