从生成器函数中退出 Final Promise 作用域
Exiting Final Promise Scope from Within a Generator Function
我在尝试 return 承诺结果作为回馈给原始调用者时遇到问题。
store.js
module.exports = {
find: function *(storeRequest){
if(!_gateway){
_gateway = realGateway;
}
storeResponse.http.statusCode = 200;
var stores = _gateway.find(storeRequest.id).next().value; // I want to be able to get the stores array back here ultimately by calling next() like I am trying to do here
console.log(stores[0]);
//yield storeResponse;
}
};
storeGateway.js
module.exports = {
find: function *(id){
var stores = [];
var entity;
database.find.then(function(foundStores){
entity = testUtil.createStore(foundStores[0].id, foundStores[0].name);
console.log("ENTITY:");
console.log(entity);
stores.push(entity);
console.log("STORES[0]:");
console.log(stores[0]);
// I am getting the results here successfully so far when I console.log(stores[0])! But now I want to return stores now from here and yield the array so it propogates up to the caller of storeGateway's find()
// yield entity; --- this doesn't work because I think I'm in the promise then scope
}
);
//yield entity; -- and this definitely won't work because it's not in the promise callback (then)
}
};
database.js
var co = require('co');
var pg = require('co-pg')(require('pg'));
var config = require('./postgreSQL-config');
var database = module.exports = {};
var _id;
var _foundStores;
database.find = co(function* poolExample(id) {
var query = "Select id, name from stores";
try {
var connectionResults = yield pg.connectPromise(config.postgres);
var client = connectionResults[0];
var done = connectionResults[1];
var result = yield client.queryPromise(query);
done();
console.log("PRINTING ROWS:");
console.log(result.rows[0]);
_foundStores = yield result.rows;
} catch(ex) {
console.error(ex.toString());
}
console.log("RESULTS!:");
console.log(_foundStores);
return _foundStores;
});
我正在为您在上面看到的每个 console.log 打印数据。我只是不知道如何从 storeGateway 的 find() 方法 return 存储,因为它在承诺结果中接收存储数组(在 .then() 中),我需要能够返回它上游。
(请参阅我在代码中的评论,我正在尝试 return 在 promise 中找到的存储然后从我的 store.js 的查找生成器函数返回上游)。
有两种方法可以做到这一点。你要么在你的函数中接收到一个回调参数,并在承诺被解决时调用它(在你的 then 函数中),要么更好,return then 的结果。 then() 本身 return 是一个承诺,无论您 return 在函数中使用 with 都可用于链接到承诺的后续函数,所以如果您这样做
return database.find.then(function(foundStores){
entity = testUtil.createStore(foundStores[0].id, foundStores[0].name);
console.log("ENTITY:");
console.log(entity);
stores.push(entity);
console.log("STORES[0]:");
console.log(stores[0]);
return stores[0];
}
然后您可以执行 gateway.find().then(function(stores){}) 并且 stores 将是您 return 编辑的内容,即 stores[0].
使用生成器和 co
的要点是你可以 yield
向协程运行器承诺并取回它们的结果,这样你就不必使用 then
.
首先在您的 database.js
中创建 find
方法:
database.find = co.wrap(function* poolExample(id) {
// ^^^^^
…
});
然后在storeGateway.js
你应该做
module.exports = {
find: function*(id) {
var foundStores = yield database.find(id);
var entity = testUtil.createStore(foundStores[0].id, foundStores[0].name);
console.log("ENTITY:", entity);
var stores = [entity];
console.log("STORES[0]:", stores[0]);
return stores;
}
};
(也许将生成器函数包装在 co.wrap(…)
中)。
然后在store.js
你可以做
module.exports = {
find: co.wrap(function*(storeRequest) {
if (!_gateway) _gateway = realGateway;
storeResponse.http.statusCode = 200;
var stores = yield* _gateway.find(storeRequest.id);
// or yield _gateway.find(storeRequest.id); if you did wrap it and it
// returns a promise, not a generator
console.log(stores[0]);
return stores;
})
};
我在尝试 return 承诺结果作为回馈给原始调用者时遇到问题。
store.js
module.exports = {
find: function *(storeRequest){
if(!_gateway){
_gateway = realGateway;
}
storeResponse.http.statusCode = 200;
var stores = _gateway.find(storeRequest.id).next().value; // I want to be able to get the stores array back here ultimately by calling next() like I am trying to do here
console.log(stores[0]);
//yield storeResponse;
}
};
storeGateway.js
module.exports = {
find: function *(id){
var stores = [];
var entity;
database.find.then(function(foundStores){
entity = testUtil.createStore(foundStores[0].id, foundStores[0].name);
console.log("ENTITY:");
console.log(entity);
stores.push(entity);
console.log("STORES[0]:");
console.log(stores[0]);
// I am getting the results here successfully so far when I console.log(stores[0])! But now I want to return stores now from here and yield the array so it propogates up to the caller of storeGateway's find()
// yield entity; --- this doesn't work because I think I'm in the promise then scope
}
);
//yield entity; -- and this definitely won't work because it's not in the promise callback (then)
}
};
database.js
var co = require('co');
var pg = require('co-pg')(require('pg'));
var config = require('./postgreSQL-config');
var database = module.exports = {};
var _id;
var _foundStores;
database.find = co(function* poolExample(id) {
var query = "Select id, name from stores";
try {
var connectionResults = yield pg.connectPromise(config.postgres);
var client = connectionResults[0];
var done = connectionResults[1];
var result = yield client.queryPromise(query);
done();
console.log("PRINTING ROWS:");
console.log(result.rows[0]);
_foundStores = yield result.rows;
} catch(ex) {
console.error(ex.toString());
}
console.log("RESULTS!:");
console.log(_foundStores);
return _foundStores;
});
我正在为您在上面看到的每个 console.log 打印数据。我只是不知道如何从 storeGateway 的 find() 方法 return 存储,因为它在承诺结果中接收存储数组(在 .then() 中),我需要能够返回它上游。
(请参阅我在代码中的评论,我正在尝试 return 在 promise 中找到的存储然后从我的 store.js 的查找生成器函数返回上游)。
有两种方法可以做到这一点。你要么在你的函数中接收到一个回调参数,并在承诺被解决时调用它(在你的 then 函数中),要么更好,return then 的结果。 then() 本身 return 是一个承诺,无论您 return 在函数中使用 with 都可用于链接到承诺的后续函数,所以如果您这样做
return database.find.then(function(foundStores){
entity = testUtil.createStore(foundStores[0].id, foundStores[0].name);
console.log("ENTITY:");
console.log(entity);
stores.push(entity);
console.log("STORES[0]:");
console.log(stores[0]);
return stores[0];
}
然后您可以执行 gateway.find().then(function(stores){}) 并且 stores 将是您 return 编辑的内容,即 stores[0].
使用生成器和 co
的要点是你可以 yield
向协程运行器承诺并取回它们的结果,这样你就不必使用 then
.
首先在您的 database.js
中创建 find
方法:
database.find = co.wrap(function* poolExample(id) {
// ^^^^^
…
});
然后在storeGateway.js
你应该做
module.exports = {
find: function*(id) {
var foundStores = yield database.find(id);
var entity = testUtil.createStore(foundStores[0].id, foundStores[0].name);
console.log("ENTITY:", entity);
var stores = [entity];
console.log("STORES[0]:", stores[0]);
return stores;
}
};
(也许将生成器函数包装在 co.wrap(…)
中)。
然后在store.js
你可以做
module.exports = {
find: co.wrap(function*(storeRequest) {
if (!_gateway) _gateway = realGateway;
storeResponse.http.statusCode = 200;
var stores = yield* _gateway.find(storeRequest.id);
// or yield _gateway.find(storeRequest.id); if you did wrap it and it
// returns a promise, not a generator
console.log(stores[0]);
return stores;
})
};