getch() 将回车 return 等同于 esc 键

Question

我正在编写一个重设密码的程序，但在最终（接受新密码）条件成立之前，我在退出程序时遇到了一些问题。我正在使用 conio.h 的 getch() 函数接受输入以将其写入字符串（使用 string.h）

我使用 Borland TurboC++ V4.0 来保持兼容性，因为这是 add-on 旧 MS DOS 程序的代码。如果可以的话，我会使用更新的 ide/compiler。

这是程序的一小段；我省略了 headers 和新的 password/check 密码行，因为它们在 atm 上起作用。我是 C 编程的新手，我知道这可能不是最简单的编写方式，而且有很多冗余。我已经尝试创建一个标志来退出程序，以及一个中断函数，它们都运行进入了同样的问题；他们将 '\r' 视为 esc，反之亦然。

main()
{
char password[] = "0000000000000000000";
char newpassword[] = "0000000000000000000";
char checkpassword[] = "0000000000000000000";
char answer[] = "hrigsetup";
initgraph(&gd,&gm,"C://TC//BGI");

//draw screen
rectangle(0,0,screen_x,screen_y);
rectangle(screen_x/4,screen_y/3,(3*(screen_x/4)),(2*(screen_y/3)));
rectangle(((screen_x/4)+50),((screen_y/3)+45),(3*(screen_x/4)-50),((screen_y/3)+20));
rectangle(((screen_x/4)+50),((screen_y/3)+90),(3*(screen_x/4)-50),((screen_y/3)+65));
rectangle(((screen_x/4)+50),((screen_y/3)+135),(3*(screen_x/4)-50),((screen_y/3)+110));

//write text
setcolor(headercolor);
settextstyle(DEFAULT_FONT,HORIZ_DIR,2);
settextjustify(CENTER_TEXT,TOP_TEXT);
outtextxy(screen_x/2,((screen_y/4)),"Change Password");
setcolor(drawcolor);
settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
settextjustify(LEFT_TEXT,TOP_TEXT);
outtextxy((screen_x/2)-108,((screen_y/2)-70),"Enter Old Password");
outtextxy((screen_x/2)-108,((screen_y/2)-25),"Enter New Password");
outtextxy((screen_x/2)-108,((screen_y/2)+20),"Re-Enter New Password");


//enter old password
//password entry
while(unlock != 1 && esc_key != 1)
{
    while((password[p] = getch()) != '\r')                                          //mask text logic
    {
        if(password[p] == '\b')                                                 //tolerate a backspace
        {
            if(p == 17 && endchar == 0)                                     //Logic password field
            {                                                               //bounds/overflow protection
                password[p] = ' ';
                setcolor(clear);
                settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
                settextjustify(LEFT_TEXT,TOP_TEXT);
                outtextxy((screen_x/2)-(100-(p*8)),(screen_y/2)-50,"Û");
                endchar = 1;
            }
            else
            {
                password[p] = ' ';
                setcolor(clear);
                settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
                settextjustify(LEFT_TEXT,TOP_TEXT);
                outtextxy((screen_x/2)-(100-((p-1)*8)),(screen_y/2)-50,"Û");
                p--;
                if(p <= -1)
                    p = 0;
            }
        }
            else if(password[p] == 27 )          //esc logic
            {                                  //have tried 27, 0x1b, '7
                break;
        }
        else
        {
            if(clear_bar == 1)                                            //erase contents of password
            {                                                             //box
                setcolor(clear);
                settextstyle(DEFAULT_FONT,HORIZ_DIR,3);
                outtextxy((screen_x/2)-2,(screen_y/2)-59,"ÛÛÛÛÛÛÛÛÛ");
                setcolor(drawcolor);
                settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
                settextjustify(LEFT_TEXT,TOP_TEXT);
                clear_bar = 0;
            }
            setcolor(drawcolor);
            settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
            settextjustify(LEFT_TEXT,TOP_TEXT);
            outtextxy((screen_x/2)-(100-(p*8)),(screen_y/2)-50,"*");
            if(p == 17)
            {
                p = 17;
                endchar = 0;
            }
            else
                p++;

        }
    }
    if(strcmp(password, answer) !=0 && esc_key != 1)                                    //check password = wrong,
    {                                                                   //clear password box, fill
        setcolor(headercolor);                                      //read and write "incorrect"
        settextjustify(CENTER_TEXT,TOP_TEXT);                       //in the box, write "Try Again"
        settextstyle(DEFAULT_FONT,HORIZ_DIR,3);                     //below input box
        outtextxy((screen_x/2)-2,(screen_y/2)-59,"ÛÛÛÛÛÛÛÛÛ");
        setcolor(drawcolor);
        settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
        outtextxy(screen_x/2,(screen_y/2)-50,"Incorrect");
        outtextxy(screen_x/2,(screen_y/2)+100,"Try Again");
        unlock = 0;
        clear_bar = 1;
        newp_ent = 0;
        password[p] = 0;
        p = 0;


    }
    if(strcmp(password, answer) == 0 && esc_key != 1)                                //check password = correct
    {                                                                // clear and fill input box
        setcolor(unlock_color);                                  //green and display "Correct"
        settextjustify(CENTER_TEXT,TOP_TEXT);                    //write "Press Any Key" below
        settextstyle(DEFAULT_FONT,HORIZ_DIR,3);                  //the input box
        outtextxy((screen_x/2)-2,(screen_y/2)-59,"ÛÛÛÛÛÛÛÛÛ");
        setcolor(clear);
        settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
        outtextxy(screen_x/2,(screen_y/2)+100,"ÛÛÛÛÛÛÛÛÛ");
        setcolor(drawcolor);
        settextstyle(DEFAULT_FONT,HORIZ_DIR,1);
        outtextxy(screen_x/2,(screen_y/2)-50,"Correct");
        unlock = 1;
        newp_ent = 0;
    }
}

Answer 1

检测 Esc 键的代码块中缺少一行。您已检测到它，但没有为此目的设置标志。

else if(password[p] == 27 )
{
    esc_key = 1;            // <-- add this line
    break;
}

getch() 将回车 return 等同于 esc 键

getch() equating carriage return to esc key

c

dos

getch

turbo-c++

bgi