C中二维字符数组的行数

Question

是否可以计算二维 char 数组的线？

上下文：

我已经从 csv 文件中读取了名称，我想用它后面的数字进行计算。

伪代码：

int workers = size of the 2d char array (a_name)

workers = sizeof(a_name)显然是不行的。

Answer 1

1.你可以在读取csv文件的同时统计worker的数量

2. 你可以写一个函数来计算工人的数量（取决于你期望的工人数量，这可能是值得的）。无论如何，如果你要使用 strlen - 它会运行遍历整个东西，直到它到达第一个 '\0'。

它应该看起来像这样

char workers[ MAX_WORKERS ][ MAX_NAME_LENGTH ];
int counter;

// assuming the array was filled from 0 sequntially
for ( counter = 0; counter < MAX_WORKERS; counter++ ) {
    if ( *(workers[ i ]) == 0 )
         break;
}

// counter now holds the number of workers

另一种可能的解决方案（不确定我这样做是否正确）

char workers[ MAX_WORKERS ][ MAX_NAME_LENGTH ];
char *pointer;
int counter

counter = 0;
pointer = workers;

// assuming a memset or calloc have been made for workers, and that the array was filled from 0 sequntially
while( pointer != NULL ) {
    pointer += MAX_NAME_LENGTH;
    counter++;
}

// counter now holds the number of workers

C中二维字符数组的行数

Amount of lines of a 2D Char array in C

c

arrays

2d