Retrofit 2.0 如何得到反序列化错误 response.body

Question

我正在使用 Retrofit 2.0.0-beta1。

在测试中，我有一个替代方案，预计错误 HTTP 400

我想要retrofit.Response<MyError> response 但是 response.body() == null

MyError 没有反序列化 - 我只在这里看到它

response.errorBody().string()

但它没有给我 MyError 作为对象

Answer 1

通过以下方式解决：

Converter<MyError> converter = 
    (Converter<MyError>)JacksonConverterFactory.create().get(MyError.class);
MyError myError =  converter.fromBody(response.errorBody());

Answer 2

在 Retrofit 2.0 beta2 中，这是我收到错误响应的方式：

同步

try {
   Call<RegistrationResponse> call = backendServiceApi.register(data.in.account, data.in.password,
           data.in.email);
   Response<RegistrationResponse> response = call.execute();
   if (response != null && !response.isSuccess() && response.errorBody() != null) {
       Converter<ResponseBody, BasicResponse> errorConverter =
               MyApplication.getRestClient().getRetrofitInstance().responseConverter(BasicResponse.class, new Annotation[0]);
       BasicResponse error = errorConverter.convert(response.errorBody());
       //DO ERROR HANDLING HERE
       return;
   }
   RegistrationResponse registrationResponse = response.body();
   //DO SUCCESS HANDLING HERE
} catch (IOException e) {
   //DO NETWORK ERROR HANDLING HERE
}

异步

Call<BasicResponse> call = service.loadRepo();
call.enqueue(new Callback<BasicResponse>() {
    @Override
    public void onResponse(Response<BasicResponse> response, Retrofit retrofit) {
        if (response != null && !response.isSuccess() && response.errorBody() != null) {
            Converter<ResponseBody, BasicResponse> errorConverter =
                retrofit.responseConverter(BasicResponse.class, new Annotation[0]);
            BasicResponse error = errorConverter.convert(response.errorBody());
            //DO ERROR HANDLING HERE
            return;
        }
        RegistrationResponse registrationResponse = response.body();
        //DO SUCCESS HANDLING HERE
    }

    @Override
    public void onFailure(Throwable t) {
        //DO NETWORK ERROR HANDLING HERE
    }
});

Retrofit 2 beta3 更新：

同步 - 未更改

异步 - 从 onResponse 中删除了 Retrofit 参数

Call<BasicResponse> call = service.loadRepo();
call.enqueue(new Callback<BasicResponse>() {
    @Override
    public void onResponse(Response<BasicResponse> response) {
        if (response != null && !response.isSuccess() && response.errorBody() != null) {
            Converter<ResponseBody, BasicResponse> errorConverter =
                MyApplication.getRestClient().getRetrofitInstance().responseConverter(BasicResponse.class, new Annotation[0]);
            BasicResponse error = errorConverter.convert(response.errorBody());
            //DO ERROR HANDLING HERE
            return;
        }
        RegistrationResponse registrationResponse = response.body();
        //DO SUCCESS HANDLING HERE
    }

    @Override
    public void onFailure(Throwable t) {
        //DO NETWORK ERROR HANDLING HERE
    }
});

Answer 3

对于使用 Retrofit 2.0-beta2 的异步调用，我是这样做的：

@Override
public void onResponse(Response<RegistrationResponse> response, 
                       Retrofit retrofit) {
    if (response.isSuccess()) {
        // Do success handling here
    } else {
        try {
            MyError myError = (MyError)retrofit.responseConverter(
                    MyError.class, MyError.class.getAnnotations())
                .convert(response.errorBody());
            // Do error handling here
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

Answer 4

我目前使用一个非常简单的实现，不需要使用转换器或特殊的类。我使用的代码如下：

public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
    DialogHelper.dismiss();

    if (response.isSuccessful()) {
        // Do your success stuff...
    } else {
        try {
            JSONObject jObjError = new JSONObject(response.errorBody().string());
            Toast.makeText(getContext(), jObjError.getJSONObject("error").getString("message"), Toast.LENGTH_LONG).show();
        } catch (Exception e) {
            Toast.makeText(getContext(), e.getMessage(), Toast.LENGTH_LONG).show();
        }
    }
}

这里要注意的一点是 response.errorBody().string() 只会 return 一次正确的值。如果您再次调用它，它将 return 一个空字符串。因此，如果您想重用它，请在第一次调用时将值存储在变量中。

Answer 5

在 and https://futurestud.io/tutorials/retrofit-2-simple-error-handling 中，此变体显示为 Retrofit 2.1.0。

call.enqueue(new Callback<MyResponse>() {
    @Override
    public void onResponse(Call<MyResponse> call, Response<MyResponse> response) {
        if (response.isSuccessful()) {
            ...
        } else {
            Converter<ResponseBody, MyError> converter
                    = MyApplication.getRetrofit().responseBodyConverter(
                    MyError.class, new Annotation[0]);
            MyError errorResponse = null;
            try {
                errorResponse = converter.convert(response.errorBody());
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }

Answer 6

当您将 OkHttp 与 Retrofit 一起使用时，这似乎是问题所在，因此您可以删除 OkHttp 或使用下面的代码来获取错误正文：

if (!response.isSuccessful()) {
 InputStream i = response.errorBody().byteStream();
 BufferedReader r = new BufferedReader(new InputStreamReader(i));
 StringBuilder errorResult = new StringBuilder();
 String line;
 try {
   while ((line = r.readLine()) != null) {
   errorResult.append(line).append('\n');
   }
 } catch (IOException e) { 
    e.printStackTrace(); 
}
}

Answer 7

我通过以下方式解决了它：

 if(!response.isSuccessful()){
       Gson gson = new Gson();
       MyErrorMessage message=gson.fromJson(response.errorBody().charStream(),MyErrorMessage.class);
       if(message.getCode()==ErrorCode.DUPLICATE_EMAIL_ID_CODE){
                  //DO Error Code specific handling                        
        }else{
                 //DO GENERAL Error Code Specific handling                               
        }
    }

MyErrorMessage Class:

  public class MyErrorMessage {
     private int code;
     private String message;

     public int getCode() {
        return code;
     }

     public void setCode(int code) {
        this.code = code;
     }

     public String getMessage() {
         return message;
     }

     public void setMessage(String message) {
        this.message = message;
     }
   }

Answer 8

try{
                ResponseBody response = ((HttpException) t).response().errorBody();
                JSONObject json = new JSONObject( new String(response.bytes()) );
                errMsg = json.getString("message");
            }catch(JSONException e){
                return t.getMessage();
            }
            catch(IOException e){
                return t.getMessage();
            }

Answer 9

 @Override
 public void onResponse(Call<Void> call, retrofit2.Response<Void> response) {
            if (response.isSuccessful()) {

            //Do something if response is ok
            } else {

                JsonParser parser = new JsonParser();
                JsonElement mJson = null;
                try {
                    mJson = parser.parse(response.errorBody().string());
                    Gson gson = new Gson();
                    MyError errorResponse = gson.fromJson(mJson, MyError.class);
                } catch (IOException ex) {
                    ex.printStackTrace();
                }

            }

Answer 10

在 Kotlin 中：

val call = APIClient.getInstance().signIn(AuthRequestWrapper(AuthRequest("1234567890z", "12341234", "nonce")))
call.enqueue(object : Callback<AuthResponse> {
    override fun onResponse(call: Call<AuthResponse>, response: Response<AuthResponse>) {
        if (response.isSuccessful) {

        } else {
            val a = object : Annotation{}
            val errorConverter = RentalGeekClient.getRetrofitInstance().responseBodyConverter<AuthFailureResponse>(AuthFailureResponse::class.java, arrayOf(a))
            val authFailureResponse = errorConverter.convert(response.errorBody())
        }
    }

    override fun onFailure(call: Call<AuthResponse>, t: Throwable) {
    }
})

Answer 11

这样，如果您只注入从 Retrofit 创建的服务，则不需要 Retrofit 实例。

public class ErrorUtils {

  public static APIError parseError(Context context, Response<?> response) {

    APIError error = new APIError();

    try {
        Gson gson = new Gson();
        error = gson.fromJson(response.errorBody().charStream(), APIError.class);
    } catch (Exception e) {
        Toast.makeText(context, e.getMessage(), Toast.LENGTH_LONG).show();
    }

    if (TextUtils.isEmpty(error.getErrorMessage())) {
        error.setError(response.raw().message());
    }
    return error;
  }
}

这样使用：

if (response.isSuccessful()) {

      ...

    } else {

      String msg = ErrorUtils.parseError(fragment.getActivity(), response).getError(); // would be from your error class
      Snackbar.make(someview, msg, Snackbar.LENGTH_LONG).show();
    }
  }

Answer 12

ErrorResponse 是您的自定义响应对象

科特林

val gson = Gson()
val type = object : TypeToken<ErrorResponse>() {}.type
var errorResponse: ErrorResponse? = gson.fromJson(response.errorBody()!!.charStream(), type)

Java

Gson gson = new Gson();
Type type = new TypeToken<ErrorResponse>() {}.getType();
ErrorResponse errorResponse = gson.fromJson(response.errorBody.charStream(),type);

Answer 13

errorBody 值应该在 Retrofit 中设置 APIError 对象。因此，您可以使用以下代码结构。

public class APIErrorUtils {

    public static APIError parseError(Response<?> response) {
        Converter<ResponseBody, APIError> converter = API.getClient().responseBodyConverter(APIError.class, new Annotation[0]);

        APIError error;

        try {
            error = converter.convert(response.errorBody());
            Log.d("SERVICELOG", "****************************************************");
            Log.d("SERVICELOG", "***** SERVICE LOG");
            Log.d("SERVICELOG", "***** TIMESTAMP: " + String.valueOf(error.getTimestamp()));
            Log.d("SERVICELOG", "***** STATUS: " + String.valueOf(error.getStatus()));
            Log.d("SERVICELOG", "***** ERROR: " + error.getError());
            Log.d("SERVICELOG", "***** MESSAGE: " + error.getMessage());
            Log.d("SERVICELOG", "***** PATH: " + error.getPath());
            Log.d("SERVICELOG", "****************************************************");
        } catch (IOException e) {
            return new APIError();
        }

        return error;
    }
}

APIError error = APIErrorUtils.parseError(response);
if (error.getStatus() == 400) {
    ....
}

Answer 14

我遇到了同样的问题。我通过改造解决了它。让我展示一下...

如果你的错误 JSON 结构像

{
"error": {
    "status": "The email field is required."
}
}


My ErrorRespnce.java 

public class ErrorResponse {

   @SerializedName("error")
   @Expose
   private ErrorStatus error;

   public ErrorStatus getError() {
      return error;
   }

   public void setError(ErrorStatus error) {
      this.error = error;
   }
}

这是我的错误状态 class

public class ErrorStatus {

  @SerializedName("status")
  @Expose
  private String status;

  public String getStatus() {
      return status;
  }

  public void setStatus(String status) {
      this.status = status;
  }
}

现在我们需要一个 class 来处理我们的 json。

  public class ErrorUtils {

   public static ErrorResponse parseError (Response<?> response){
      Converter<ResponseBody , ErrorResponse> converter =          ApiClient.getClient().responseBodyConverter(ErrorResponse.class , new Annotation[0]);
    ErrorResponse errorResponse;
    try{
        errorResponse = converter.convert(response.errorBody());
    }catch (IOException e){
        return new ErrorResponse();
    }
    return errorResponse;
}
}

现在我们可以在改造 api 调用

中检查我们的响应

private void registrationRequest(String name , String email , String password , String c_password){


    final Call<RegistrationResponce> registrationResponceCall = apiInterface.getRegistration(name , email , password , c_password);
    registrationResponceCall.enqueue(new Callback<RegistrationResponce>() {
        @Override
        public void onResponse(Call<RegistrationResponce> call, Response<RegistrationResponce> response) {



            if (response.code() == 200){


            }else if (response.code() == 401){


                ErrorResponse errorResponse = ErrorUtils.parseError(response);
                Toast.makeText(MainActivity.this, ""+errorResponse.getError().getStatus(), Toast.LENGTH_SHORT).show();
            }
        }

        @Override
        public void onFailure(Call<RegistrationResponce> call, Throwable t) {

        }
    });
}

到此为止，您可以展示您的 Toast

Answer 15

如果您使用 Kotlin，另一个解决方案可能只是为 Response 创建扩展函数 class:

inline fun <reified T>Response<*>.parseErrJsonResponse(): T?
{
    val moshi = MyCustomMoshiBuilder().build()
    val parser = moshi.adapter(T::class.java)
    val response = errorBody()?.string()
    if(response != null)
        try {
            return parser.fromJson(response)
        } catch(e: JsonDataException) {
            e.printStackTrace()
        }
    return null
}

用法

val myError = response.parseErrJsonResponse<MyErrorResponse>()
if(myError != null) {
   // handle your error logic here
   // ...
}

Answer 16

if(!response.isSuccessful()) {
    StringBuilder error = new StringBuilder();
    try {
        BufferedReader bufferedReader = null;
        if (response.errorBody() != null) {
            bufferedReader = new BufferedReader(new InputStreamReader(
                    response.errorBody().byteStream()));

            String eLine = null;
            while ((eLine = bufferedReader.readLine()) != null) {
                error.append(eLine);
            }
            bufferedReader.close();
        }

    } catch (Exception e) {
        error.append(e.getMessage());
    }

    Log.e("Error", error.toString());
}

Answer 17

已测试并有效

 public BaseModel parse(Response<BaseModel> response , Retrofit retrofit){
            BaseModel error = null;
            Converter<ResponseBody, BaseModel> errorConverter =
                    retrofit.responseBodyConverter(BaseModel.class, new Annotation[0]);
            try {
                if (response.errorBody() != null) {
                    error = errorConverter.convert(response.errorBody());
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
            return error;
        }

Answer 18

val error = JSONObject(callApi.errorBody()?.string() as String)
            CustomResult.OnError(CustomNotFoundError(userMessage = error["userMessage"] as String))

open class CustomError (
    val traceId: String? = null,
    val errorCode: String? = null,
    val systemMessage: String? = null,
    val userMessage: String? = null,
    val cause: Throwable? = null
)

open class ErrorThrowable(
    private val traceId: String? = null,
    private val errorCode: String? = null,
    private val systemMessage: String? = null,
    private val userMessage: String? = null,
    override val cause: Throwable? = null
) : Throwable(userMessage, cause) {
    fun toError(): CustomError = CustomError(traceId, errorCode, systemMessage, userMessage, cause)
}


class NetworkError(traceId: String? = null, errorCode: String? = null, systemMessage: String? = null, userMessage: String? = null, cause: Throwable? = null):
    CustomError(traceId, errorCode, systemMessage, userMessage?: "Usted no tiene conexión a internet, active los datos", cause)

class HttpError(traceId: String? = null, errorCode: String? = null, systemMessage: String? = null, userMessage: String? = null, cause: Throwable? = null):
    CustomError(traceId, errorCode, systemMessage, userMessage, cause)

class UnknownError(traceId: String? = null, errorCode: String? = null, systemMessage: String? = null, userMessage: String? = null, cause: Throwable? = null):
    CustomError(traceId, errorCode, systemMessage, userMessage?: "Unknown error", cause)

class CustomNotFoundError(traceId: String? = null, errorCode: String? = null, systemMessage: String? = null, userMessage: String? = null, cause: Throwable? = null):
    CustomError(traceId, errorCode, systemMessage, userMessage?: "Data not found", cause)`

Answer 19

创建错误响应和用户 Gson 的模型以将响应转换为它。这会很好用。

APIError.java

public class APIError {
    private String message;

    public String getMessage() {
        return message;
    }
}

MainActivity.java（内部请求 onResponse）

if (response.isSuccessful()) {
    // Do your success stuff...

} else {
    APIError message = new Gson().fromJson(response.errorBody().charStream(), APIError.class);
    Toast.makeText(MainActivity.this, "" + message.getMessage(), Toast.LENGTH_SHORT).show();
}

Answer 20

这是使用 Kotlin 扩展的优雅解决方案：

data class ApiError(val code: Int, val message: String?) {
    companion object {
        val EMPTY_API_ERROR = ApiError(-1, null)
    }
}

fun Throwable.getApiError(): ApiError? {
    if (this is HttpException) {
        try {
            val errorJsonString = this.response()?.errorBody()?.string()
            return Gson().fromJson(errorJsonString, ApiError::class.java)
        } catch (exception: Exception) {
            // Ignore
        }
    }
    return EMPTY_API_ERROR
}

和用法：

showError(retrofitThrowable.getApiError()?.message)

Answer 21

其实很简单。

科特林：

val jsonObj = JSONObject(response.errorBody()!!.charStream().readText())
responseInterface.onFailure(jsonObj.getString("msg"))

Java:

    if(response.errorBody()!=null){
    JSONObject jsonObj = new JSONObject(TextStreamsKt.readText(response.errorBody().charStream()));
        responseInterface.onFailure(jsonObj.getString("msg"));
    }else{
        responseInterface.onFailure("you might want to return a generic error message.");
    }

在 retrofit:2.5.0 上测试。从 charStream 中读取文本，它将为您提供一个字符串，然后解析为 JSONObject。

再见。

Answer 22

kotlin 中的错误主体处理 Android

catch (cause: Throwable) {
            when (cause) {
                is HttpException -> {
                    try {
                        val YourErrorResponseClassObj = Gson().fromJson(cause.response()?.errorBody()?.charStream(), YourErrorResponseClass::class.java)
                    } catch (e: Exception) {
                        
                    }
                }
                else -> {
                    //Other errors like Network ...
                }
            }
        }

Answer 23

已经有很多有效的答案。这只是一个用例的补充，当您需要多次使用相同的 Retrofit 响应时。以下两个都不能使用，如 you can read response body only once，因为它会在之后关闭，并且下次您尝试从同一个响应对象读取时，每次都会得到 null：

response()?.errorBody()?.charStream()?.readText()
response()?.errorBody()?.string()

相反，您可以获得响应字符串的只读副本（而响应本身可以传递并最终在以后使用）：

response()?.errorBody()?.source()?.buffer?.snapshot()?.utf8()

Answer 24

很简单。这救了我的命

public static void displayApiResponseErrorBody(Response<?> response)
{
    InputStream i = response.errorBody().byteStream();
    BufferedReader r = new BufferedReader(new InputStreamReader(i));
    StringBuilder errorResult = new StringBuilder();
    String line;
    try {
        while ((line = r.readLine()) != null) 
        {
            errorResult.append(line).append('\n');
        }
        Log.d("API_RESPONSE_ERROR_BODY",String.valueOf(errorResult));
        System.out.println(errorResult);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

Answer 25

如果您的错误响应是一个字符串，您可以使用以下 kotlin 代码将其反序列化：

val errorString = response.errorBody()?.byteStream()?.bufferedReader().use { it?.readText() }  // defaults to UTF-8

Answer 26

json 回应

{
    "success": false,
    "status_code": 32,
    "status_message": "Email not verified: Your email address has not been verified."
}

错误class

data class ResponseError(
    @SerializedName("status_code")
    val statusCode: Int,
    @SerializedName("status_message")
    val statusMessage: String,
    @SerializedName("success")
    val success: Boolean
)

获取错误信息

fun <T : Any> getResultOrError(response: Response<T>): T? {
    if (response.isSuccessful) {
        return response.body()
    } else {
        try {
            val responseError = Gson().fromJson(
                response.errorBody()?.string(),
                ResponseError::class.java
            )
            throw Throwable(responseError.statusMessage)
        } catch (e: Exception) {
            throw Throwable("Unknown error")
        }
    }
}

Answer 27

在改造错误响应的情况下，您可以使用error.getResponse()获取正文，这是示例。

        @Override
        public void failure(RetrofitError error){
            if(error.getResponse().getStatus()==201){
                LogUtil.INSTANCE.debug("Success : " + error.toString());
                callback.success(error.getResponse().getBody);
            }else{
                LogUtil.INSTANCE.debug("failure: " + error.toString());
                callback.failure(error);
            }
        }

Answer 28

在 Kotlin 中，我解决了创建自定义 ResponseBody 通用扩展函数的问题，该函数将响应主体转换为 JSONObject。然后你可以使用 gson 来自定义错误响应正文和你的自定义错误数据 Class.

inline fun <reified T> ResponseBody.getErrorObject(): T {
    val gson = Gson()
    val jsonObject = JSONObject(charStream().readText())
    return gson.fromJson(jsonObject.toString(), T::class.java)
}

然后您可以将错误响应客户化为您的自定义 class。为此，我使用了一个例子

data class LoginError(
    val error: Error,
    val message: String,
    val success: Boolean
)

data class Error(
    val error: String,
    val status: Int
)

那就这样使用扩展功能

val error = state.errorBody.getErrorObject<LoginError>()

state.errorBody 是我对 ResponseBody

类型改造的错误响应

Answer 29

我这样做了，效果很好

val errorBody = (response?.errorBody() as ResponseBody).string()

Retrofit 2.0 如何得到反序列化错误 response.body

Retrofit 2.0 how to get deserialised error response.body

java

retrofit

retrofit2