do/while 循环懒惰的餐饮服务商的序列

Question

我无法完全理解this。我目前正在研究如何完成这项工作，而且我希望打印第一个 11 个结果（1、2、4、7、11、16、22、29、37、46、56）。

请解释并帮助我做？

注：我正在使用do/while循环

import java.util.Scanner;
import java.io.*;

    public class DoWhileLoop {
        public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int N;
        System.out.print("Enter a number ");
        N = in.nextInt();

        int cut0 = 1;
        int totalpieces = 1;
        int Ncut = cutN+((cutN-1)+N); // help me here pls

        do {
        totalpieces = totalpieces + N; // not sure how to construct this too
        totalpieces++;
        }
        while(totalpieces<=56);

        System.out.println(totalpieces + " "); // I would want the 1st 11  outcome to be printed (1, 2, 4, 7, 11, 16, 22, 29, 37, 46, 56)
    }
}

Answer 1

尝试这样的事情：

    String result = "";

    Scanner in = new Scanner(System.in);
    System.out.print("Enter a number ");
    int numberOfCuts = in.nextInt();

    int pieces = 1;
    int cutCount = 1;

    do {
        result += " " + pieces;

        pieces += cutCount;
        cutCount++;
    }
    while (cutCount <= numberOfCuts);

    System.out.println(result);

Answer 2

试试这个：

 Scanner in = new Scanner(System.in);
 int N, cut;
 System.out.print("Enter a number ");
 N = in.nextInt();
    do
    {
        cut = 1+(N*(N+1))/2;
        N--;
    }while(N == 0);

 System.out.println("Total cut: " + cut);

输入 N = 5 预期输出：16 打印：

Enter a number 5

16

do/while 循环懒惰的餐饮服务商的序列

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