在 PHP-CPP 中将 Php::Object 转换回 C++ 对象?

Convert a Php::Object back to a C++ object in PHP-CPP?

我试图制作一个 Bencode extension for PHP by PHP-CPP,所以有几个 类 比如:

class BItem : public Php::Base {
public:
virtual std::string getType() const {
    return "BItem";
}
};

class BDict : public BItem {
public:
std::unordered_map<std::string, BItem*> BData;

std::string getType() const {
    return "BDict";
}

Php::Value getItem(Php::Parameters &params) {
    std::string key = params[0];
    ...
    ...
    return Php::Object(...);
}

// PHP: $a = new BDict(); $b = new BDict(); $a->addItem($b);
void addItem(Php::Parameters &params) {
    std::string key = params[0];

    /**
     * Here's the part confusing me
     * Is there something like:
     */
    BItem *toInsert = &params[1]; // However, params[1] is actually a Php::Object
    BData.insert({key, toInsert});
}
};

class BStr : public BItem {...};
class BList : public BItem {...};
class BInt : public BItem {...};

除了BItem之外的所有类型都可以插入到BDict

因此,在创建其中之一的实例后,我如何将它传回 C++ 部分,"convert" 将其传回 C++ 对象,最后将其插入 BData

我是 php 扩展的新手,非常感谢任何帮助或提示。

根据Emiel's answer

void myFunction(Php::Parameters &params)
{
    // store the first parameter in a variable
    Php::Value object = params[0];

    // we want to be 100% sure that the passed in parameter is indeed one of our own objects
    if (!object.instanceOf("MySpecialClass")) throw Php::Exception("Wrong parameter passed");

    // cast the PHP object back into a C++ class
    MySpecialClass *cppobject = (MySpecialClass *)object.implementation();

    // @todo add your own code
}